如何在Python中读取文件的每一行,并将每一行存储为列表中的元素?
我想逐行读取文件,并将每一行附加到列表的末尾。
如何在Python中读取文件的每一行,并将每一行存储为列表中的元素?
我想逐行读取文件,并将每一行附加到列表的末尾。
当前回答
如果您想从命令行或stdin读取文件,也可以使用fileinput模块:
# reader.py
import fileinput
content = []
for line in fileinput.input():
content.append(line.strip())
fileinput.close()
将文件传递给它,如下所示:
$ python reader.py textfile.txt
在此处阅读更多信息:http://docs.python.org/2/library/fileinput.html
其他回答
另一个选项是numpy.genfromttxt,例如:
import numpy as np
data = np.genfromtxt("yourfile.dat",delimiter="\n")
这将使数据成为一个NumPy数组,其行数与文件中的行数相同。
这比必要的更明确,但可以做到你想要的。
with open("file.txt") as file_in:
lines = []
for line in file_in:
lines.append(line)
下面是我用来简化文件I/O的Python(3)助手库类:
import os
# handle files using a callback method, prevents repetition
def _FileIO__file_handler(file_path, mode, callback = lambda f: None):
f = open(file_path, mode)
try:
return callback(f)
except Exception as e:
raise IOError("Failed to %s file" % ["write to", "read from"][mode.lower() in "r rb r+".split(" ")])
finally:
f.close()
class FileIO:
# return the contents of a file
def read(file_path, mode = "r"):
return __file_handler(file_path, mode, lambda rf: rf.read())
# get the lines of a file
def lines(file_path, mode = "r", filter_fn = lambda line: len(line) > 0):
return [line for line in FileIO.read(file_path, mode).strip().split("\n") if filter_fn(line)]
# create or update a file (NOTE: can also be used to replace a file's original content)
def write(file_path, new_content, mode = "w"):
return __file_handler(file_path, mode, lambda wf: wf.write(new_content))
# delete a file (if it exists)
def delete(file_path):
return os.remove() if os.path.isfile(file_path) else None
然后使用FileIO.lines函数,如下所示:
file_ext_lines = FileIO.lines("./path/to/file.ext"):
for i, line in enumerate(file_ext_lines):
print("Line {}: {}".format(i + 1, line))
请记住,mode(默认为“r”)和filter_fn(默认为检查空行)参数是可选的。
您甚至可以删除read、write和delete方法,只保留FileIO.line,甚至将其转换为一个单独的方法read_lines。
命令行版本
#!/bin/python3
import os
import sys
abspath = os.path.abspath(__file__)
dname = os.path.dirname(abspath)
filename = dname + sys.argv[1]
arr = open(filename).read().split("\n")
print(arr)
运行方式:
python3 somefile.py input_file_name.txt
f = open("your_file.txt",'r')
out = f.readlines() # will append in the list out
现在,变量out是您想要的列表(数组)。您可以选择:
for line in out:
print (line)
Or:
for line in f:
print (line)
你会得到同样的结果。