简单的答案 角8。*

constructor(private route:ActivatedRoute) {
  console.log(route);
}

Angular 7，如果你想订阅路由器

import { Router, NavigationEnd } from '@angular/router';

import { filter } from 'rxjs/operators';

constructor(
  private router: Router
) {
  router.events.pipe(
    filter(event => event instanceof NavigationEnd)  
  ).subscribe((event: NavigationEnd) => {
    console.log(event.url);
  });
}

@Ludohen的回答很好，但如果你不想使用instanceof，请使用下面的方法

this.router.events.subscribe(event => {
  if(event.constructor.name === "NavigationStart") {
    // do something...
  }
});

通过这种方式，您可以检查当前事件名称作为字符串，如果事件发生，您可以执行您计划的函数要执行的操作。

RxJS 6

router.events.pipe(filter(event => event instanceof NavigationStart))

感谢Peilonrayz(见下面的评论)

new router >= RC.3

import { Router, NavigationStart, NavigationEnd, NavigationError, NavigationCancel, RoutesRecognized } from '@angular/router';

constructor(router:Router) {
  router.events.forEach((event) => {
    if(event instanceof NavigationStart) {
    }
    // NavigationEnd
    // NavigationCancel
    // NavigationError
    // RoutesRecognized
  });
}

你也可以通过给定的事件进行过滤:

import 'rxjs/add/operator/filter';

constructor(router:Router) {
  router.events
    .filter(event => event instanceof NavigationStart)
    .subscribe((event:NavigationStart) => {
      // You only receive NavigationStart events
    });
}

使用成对操作符来获取先前和当前事件也是一个不错的想法。https://github.com/angular/angular/issues/11268#issuecomment-244601977

进口的rxjs /添加/运营商/成对的; import {Router} from '@angular/ Router '; 导出类AppComponent { 构造函数(私有路由器:router) { This.router.events.pairwise ().subscribe((event) => { console.log(事件); })； }; ｝

角8。检查当前路由是否为基路由。

  baseroute: boolean;
  constructor(
    private router: Router,
  ) {
    router.events.subscribe((val: any) => {
      if (val.url == "/") {
        this.baseroute = true;
      } else {
        this.baseroute = false;
      }
    });
  }

如果你试图访问当前路由，同时监听路由变化:

router.events.pipe(filter(r=>r instanceof NavigationEnd)).subscribe(r=>{
      console.log((r as NavigationEnd).url);
    });