我想从Vimeo获得视频的缩略图。

当从Youtube上获得图像时,我只是这样做:

http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg

你知道如何处理Vimeo吗?

同样的问题,没有答案。


当前回答

如果你正在寻找一个替代的解决方案,可以管理vimeo帐户,还有另一种方式,你只需添加每个视频你想显示到一个相册,然后使用API请求相册的详细信息-然后显示所有的缩略图和链接。这不是理想的,但可能有帮助。

API端点(游乐场)

推特与@vimeoapi对话

其他回答

如果您不需要自动解决方案,您可以通过在这里输入vimeo ID: http://video.depone.eu/来找到缩略图URL

你可能想看看马特·胡克斯的宝石。https://github.com/matthooks/vimeo

它为api提供了一个简单的vimeo包装器。

所有你需要的是存储video_id(和提供商,如果你也做其他视频网站)

你可以像这样提取vimeo视频id

def 
  get_vimeo_video_id (link)
        vimeo_video_id = nil
        vimeo_regex  = /http:\/\/(www\.)?vimeo.com\/(\d+)($|\/)/
        vimeo_match = vimeo_regex.match(link)


if vimeo_match.nil?
  vimeo_regex  = /http:\/\/player.vimeo.com\/video\/([a-z0-9-]+)/
  vimeo_match = vimeo_regex.match(link)
end

    vimeo_video_id = vimeo_match[2] unless vimeo_match.nil?
    return vimeo_video_id
  end

如果你需要你的试管,你可能会发现这个很有用

def
 get_youtube_video_id (link)
    youtube_video_id = nil
    youtube_regex  = /^(https?:\/\/)?(www\.)?youtu.be\/([A-Za-z0-9._%-]*)(\&\S+)?/
    youtube_match = youtube_regex.match(link)

if youtube_match.nil?
  youtubecom_regex  = /^(https?:\/\/)?(www\.)?youtube.com\/watch\?v=([A-Za-z0-9._%-]*)(\&\S+)?/
  youtube_match = youtubecom_regex.match(link)
end

youtube_video_id = youtube_match[3] unless youtube_match.nil?
return youtube_video_id
end
function getVimeoInfo($link)
 {
    if (preg_match('~^http://(?:www\.)?vimeo\.com/(?:clip:)?(\d+)~', $link, $match)) 
    {
        $id = $match[1];
    }
    else
    {
        $id = substr($link,10,strlen($link));
    }

    if (!function_exists('curl_init')) die('CURL is not installed!');
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, "http://vimeo.com/api/v2/video/$id.php");
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
    curl_setopt($ch, CURLOPT_TIMEOUT, 10);
    $output = unserialize(curl_exec($ch));
    $output = $output[0];
    curl_close($ch);
    return $output;
}`

//在下面的函数传递缩略图url。

function save_image_local($thumbnail_url)
    {

         //for save image at local server
         $filename = time().'_hbk.jpg';
         $fullpath = '../../app/webroot/img/videos/image/'.$filename;

         file_put_contents ($fullpath,file_get_contents($thumbnail_url));

        return $filename;
    }

使用Vimeo url(https://player.vimeo.com/video/30572181),下面是我的示例

<!DOCTYPE html> <html lang="en" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> <title>Vimeo</title> </head> <body> <div> <img src="" id="thumbImg"> </div> <script> $(document).ready(function () { var vimeoVideoUrl = 'https://player.vimeo.com/video/30572181'; var match = /vimeo.*\/(\d+)/i.exec(vimeoVideoUrl); if (match) { var vimeoVideoID = match[1]; $.getJSON('http://www.vimeo.com/api/v2/video/' + vimeoVideoID + '.json?callback=?', { format: "json" }, function (data) { featuredImg = data[0].thumbnail_large; $('#thumbImg').attr("src", featuredImg); }); } }); </script> </body> </html>

我创建了一个code depen来为您获取图像。

https://codepen.io/isramv/pen/gOpabXg

HTML

<input type="text" id="vimeoid" placeholder="257314493" value="257314493">
<button id="getVideo">Get Video</button>
<div id="output"></div>

JavaScript:

const videoIdInput = document.getElementById('vimeoid');
const getVideo = document.getElementById('getVideo');
const output = document.getElementById('output');

function getVideoThumbnails(videoid) {
  fetch(`https://vimeo.com/api/v2/video/${videoid}.json`)
  .then(response => {
    return response.text();
  })
  .then(data => {
    const { thumbnail_large, thumbnail_medium, thumbnail_small } = JSON.parse(data)[0];
    const small = `<img src="${thumbnail_small}"/>`;
    const medium = `<img src="${thumbnail_medium}"/>`;
    const large = `<img src="${thumbnail_large}"/>`;
    output.innerHTML = small + medium + large;
  })
  .catch(error => {
    console.log(error);
  });
}

getVideo.addEventListener('click', e => {
  if (!isNaN(videoIdInput.value)) {
    getVideoThumbnails(videoIdInput.value);
  }
});