我想从Vimeo获得视频的缩略图。
当从Youtube上获得图像时,我只是这样做:
http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg
你知道如何处理Vimeo吗?
同样的问题,没有答案。
我想从Vimeo获得视频的缩略图。
当从Youtube上获得图像时,我只是这样做:
http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg
你知道如何处理Vimeo吗?
同样的问题,没有答案。
当前回答
来自Vimeo Simple API文档:
视频请求
为了获得特定视频的数据, 使用以下url: http://vimeo.com/api/v2/video/video_id.output video_id需要信息的视频ID。 指定 输出类型。我们目前提供JSON, PHP和XML格式。
获取这个URL http://vimeo.com/api/v2/video/6271487.xml
<videos>
<video>
[skipped]
<thumbnail_small>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_100.jpg</thumbnail_small>
<thumbnail_medium>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_200.jpg</thumbnail_medium>
<thumbnail_large>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_640.jpg</thumbnail_large>
[skipped]
</videos>
解析每个视频以获得缩略图
下面是PHP的近似代码
<?php
$imgid = 6271487;
$hash = unserialize(file_get_contents("http://vimeo.com/api/v2/video/$imgid.php"));
echo $hash[0]['thumbnail_medium'];
其他回答
分解Karthikeyan P的答案,使其可以用于更广泛的场景:
// Requires jQuery
function parseVimeoIdFromUrl(vimeoUrl) {
var match = /vimeo.*\/(\d+)/i.exec(vimeoUrl);
if (match)
return match[1];
return null;
};
function getVimeoThumbUrl(vimeoId) {
var deferred = $.Deferred();
$.ajax(
'//www.vimeo.com/api/v2/video/' + vimeoId + '.json',
{
dataType: 'jsonp',
cache: true
}
)
.done(function (data) {
// .thumbnail_small 100x75
// .thumbnail_medium 200x150
// 640 wide
var img = data[0].thumbnail_large;
deferred.resolve(img);
})
.fail(function(a, b, c) {
deferred.reject(a, b, c);
});
return deferred;
};
使用
从Vimeo视频URL获取Vimeo Id:
var vimeoId = parseVimeoIdFromUrl(vimeoUrl);
从vimeo Id获取一个vimeo缩略图URL:
getVimeoThumbUrl(vimeoIds[0])
.done(function(img) {
$('div').append('<img src="' + img + '"/>');
});
https://jsfiddle.net/b9chris/nm8L8cc8/1/
您应该解析Vimeo API的响应。没有办法用URL调用(如dailymotion或youtube)。
下面是我的PHP解决方案:
/**
* Gets a vimeo thumbnail url
* @param mixed $id A vimeo id (ie. 1185346)
* @return thumbnail's url
*/
function getVimeoThumb($id) {
$data = file_get_contents("http://vimeo.com/api/v2/video/$id.json");
$data = json_decode($data);
return $data[0]->thumbnail_medium;
}
我创建了一个code depen来为您获取图像。
https://codepen.io/isramv/pen/gOpabXg
HTML
<input type="text" id="vimeoid" placeholder="257314493" value="257314493">
<button id="getVideo">Get Video</button>
<div id="output"></div>
JavaScript:
const videoIdInput = document.getElementById('vimeoid');
const getVideo = document.getElementById('getVideo');
const output = document.getElementById('output');
function getVideoThumbnails(videoid) {
fetch(`https://vimeo.com/api/v2/video/${videoid}.json`)
.then(response => {
return response.text();
})
.then(data => {
const { thumbnail_large, thumbnail_medium, thumbnail_small } = JSON.parse(data)[0];
const small = `<img src="${thumbnail_small}"/>`;
const medium = `<img src="${thumbnail_medium}"/>`;
const large = `<img src="${thumbnail_large}"/>`;
output.innerHTML = small + medium + large;
})
.catch(error => {
console.log(error);
});
}
getVideo.addEventListener('click', e => {
if (!isNaN(videoIdInput.value)) {
getVideoThumbnails(videoIdInput.value);
}
});
使用Vimeo url(https://player.vimeo.com/video/30572181),下面是我的示例
<!DOCTYPE html> <html lang="en" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> <title>Vimeo</title> </head> <body> <div> <img src="" id="thumbImg"> </div> <script> $(document).ready(function () { var vimeoVideoUrl = 'https://player.vimeo.com/video/30572181'; var match = /vimeo.*\/(\d+)/i.exec(vimeoVideoUrl); if (match) { var vimeoVideoID = match[1]; $.getJSON('http://www.vimeo.com/api/v2/video/' + vimeoVideoID + '.json?callback=?', { format: "json" }, function (data) { featuredImg = data[0].thumbnail_large; $('#thumbImg').attr("src", featuredImg); }); } }); </script> </body> </html>
使用Ruby,你可以做以下事情,比如:
url = "http://www.vimeo.com/7592893"
vimeo_video_id = url.scan(/vimeo.com\/(\d+)\/?/).flatten.to_s # extract the video id
vimeo_video_json_url = "http://vimeo.com/api/v2/video/%s.json" % vimeo_video_id # API call
# Parse the JSON and extract the thumbnail_large url
thumbnail_image_location = JSON.parse(open(vimeo_video_json_url).read).first['thumbnail_large'] rescue nil