我想从Vimeo获得视频的缩略图。

当从Youtube上获得图像时,我只是这样做:

http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg

你知道如何处理Vimeo吗?

同样的问题,没有答案。


当前回答

来自Vimeo Simple API文档:

视频请求

为了获得特定视频的数据, 使用以下url: http://vimeo.com/api/v2/video/video_id.output video_id需要信息的视频ID。 指定 输出类型。我们目前提供JSON, PHP和XML格式。

获取这个URL http://vimeo.com/api/v2/video/6271487.xml

    <videos> 
      <video> 
        [skipped]
        <thumbnail_small>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_100.jpg</thumbnail_small> 
        <thumbnail_medium>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_200.jpg</thumbnail_medium> 
        <thumbnail_large>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_640.jpg</thumbnail_large> 
        [skipped]
    </videos>

解析每个视频以获得缩略图

下面是PHP的近似代码

<?php

$imgid = 6271487;

$hash = unserialize(file_get_contents("http://vimeo.com/api/v2/video/$imgid.php"));

echo $hash[0]['thumbnail_medium'];  

其他回答

分解Karthikeyan P的答案,使其可以用于更广泛的场景:

// Requires jQuery

function parseVimeoIdFromUrl(vimeoUrl) {
  var match = /vimeo.*\/(\d+)/i.exec(vimeoUrl);
  if (match)
    return match[1];

  return null;
};

function getVimeoThumbUrl(vimeoId) {
  var deferred = $.Deferred();
  $.ajax(
    '//www.vimeo.com/api/v2/video/' + vimeoId + '.json',
    {
        dataType: 'jsonp',
        cache: true
    }
  )
  .done(function (data) {
    // .thumbnail_small 100x75
    // .thumbnail_medium 200x150
    // 640 wide
        var img = data[0].thumbnail_large;
        deferred.resolve(img);  
    })
  .fail(function(a, b, c) {
    deferred.reject(a, b, c);
  });
  return deferred;
};

使用

从Vimeo视频URL获取Vimeo Id:

var vimeoId = parseVimeoIdFromUrl(vimeoUrl);

从vimeo Id获取一个vimeo缩略图URL:

getVimeoThumbUrl(vimeoIds[0])
.done(function(img) {
    $('div').append('<img src="' + img + '"/>');
});

https://jsfiddle.net/b9chris/nm8L8cc8/1/

您应该解析Vimeo API的响应。没有办法用URL调用(如dailymotion或youtube)。

下面是我的PHP解决方案:

/**
 * Gets a vimeo thumbnail url
 * @param mixed $id A vimeo id (ie. 1185346)
 * @return thumbnail's url
*/
function getVimeoThumb($id) {
    $data = file_get_contents("http://vimeo.com/api/v2/video/$id.json");
    $data = json_decode($data);
    return $data[0]->thumbnail_medium;
}

我创建了一个code depen来为您获取图像。

https://codepen.io/isramv/pen/gOpabXg

HTML

<input type="text" id="vimeoid" placeholder="257314493" value="257314493">
<button id="getVideo">Get Video</button>
<div id="output"></div>

JavaScript:

const videoIdInput = document.getElementById('vimeoid');
const getVideo = document.getElementById('getVideo');
const output = document.getElementById('output');

function getVideoThumbnails(videoid) {
  fetch(`https://vimeo.com/api/v2/video/${videoid}.json`)
  .then(response => {
    return response.text();
  })
  .then(data => {
    const { thumbnail_large, thumbnail_medium, thumbnail_small } = JSON.parse(data)[0];
    const small = `<img src="${thumbnail_small}"/>`;
    const medium = `<img src="${thumbnail_medium}"/>`;
    const large = `<img src="${thumbnail_large}"/>`;
    output.innerHTML = small + medium + large;
  })
  .catch(error => {
    console.log(error);
  });
}

getVideo.addEventListener('click', e => {
  if (!isNaN(videoIdInput.value)) {
    getVideoThumbnails(videoIdInput.value);
  }
});

使用Vimeo url(https://player.vimeo.com/video/30572181),下面是我的示例

<!DOCTYPE html> <html lang="en" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> <title>Vimeo</title> </head> <body> <div> <img src="" id="thumbImg"> </div> <script> $(document).ready(function () { var vimeoVideoUrl = 'https://player.vimeo.com/video/30572181'; var match = /vimeo.*\/(\d+)/i.exec(vimeoVideoUrl); if (match) { var vimeoVideoID = match[1]; $.getJSON('http://www.vimeo.com/api/v2/video/' + vimeoVideoID + '.json?callback=?', { format: "json" }, function (data) { featuredImg = data[0].thumbnail_large; $('#thumbImg').attr("src", featuredImg); }); } }); </script> </body> </html>

使用Ruby,你可以做以下事情,比如:

url                      = "http://www.vimeo.com/7592893"
vimeo_video_id           = url.scan(/vimeo.com\/(\d+)\/?/).flatten.to_s               # extract the video id
vimeo_video_json_url     = "http://vimeo.com/api/v2/video/%s.json" % vimeo_video_id   # API call

# Parse the JSON and extract the thumbnail_large url
thumbnail_image_location = JSON.parse(open(vimeo_video_json_url).read).first['thumbnail_large'] rescue nil