是否有一种方法,我可以得到的最后一个值(基于'\'符号)从一个完整的路径?
例子:
C:\Documents and Settings\img\recycled log.jpg
在这种情况下,我只想从JavaScript的完整路径中回收log.jpg。
是否有一种方法,我可以得到的最后一个值(基于'\'符号)从一个完整的路径?
例子:
C:\Documents and Settings\img\recycled log.jpg
在这种情况下,我只想从JavaScript的完整路径中回收log.jpg。
当前回答
function getFileName(path, isExtension){
var fullFileName, fileNameWithoutExtension;
// replace \ to /
while( path.indexOf("\\") !== -1 ){
path = path.replace("\\", "/");
}
fullFileName = path.split("/").pop();
return (isExtension) ? fullFileName : fullFileName.slice( 0, fullFileName.lastIndexOf(".") );
}
其他回答
这个解决方案对'fileName'和'path'都更简单和通用。
parsePath = (path) => {
// regex to split path (untile last / or \ to two groups '(.*[\\\/])' for path and '(.*)' (untile the end after the \ or / )for file name
const regexPath = /^(?<path>(.*[\\\/])?)(?<filename>.*)$/;
const match = regexPath.exec(path);
if (path && match) {
return {
path: match.groups.path,
filename: match.groups.filename
}
}
throw Error("Error parsing path");
}
// example
const str = 'C:\\Documents and Settings\\img\\recycled log.jpg';
parsePath(str);
不是比nickf的回答更简洁,但是这个直接“提取”了答案,而不是用空字符串替换不需要的部分:
var filename = /([^\\]+)$/.exec(fullPath)[1];
为了提高性能,我测试了这里给出的所有答案:
var substringTest = function (str) {
return str.substring(str.lastIndexOf('/')+1);
}
var replaceTest = function (str) {
return str.replace(/^.*(\\|\/|\:)/, '');
}
var execTest = function (str) {
return /([^\\]+)$/.exec(str)[1];
}
var splitTest = function (str) {
return str.split('\\').pop().split('/').pop();
}
substringTest took 0.09508600000000023ms
replaceTest took 0.049203000000000004ms
execTest took 0.04859899999999939ms
splitTest took 0.02505500000000005ms
最后的赢家是“分拆式”答案,感谢波波斯!
function getFileName(path, isExtension){
var fullFileName, fileNameWithoutExtension;
// replace \ to /
while( path.indexOf("\\") !== -1 ){
path = path.replace("\\", "/");
}
fullFileName = path.split("/").pop();
return (isExtension) ? fullFileName : fullFileName.slice( 0, fullFileName.lastIndexOf(".") );
}
下面这行JavaScript代码将提供文件名。
var z = location.pathname.substring(location.pathname.lastIndexOf('/')+1);
alert(z);