不需要两个cron条目，你可以把它放在一个:

* * * * * /bin/bash -l -c "/path/to/executable; sleep 30 ; /path/to/executable"

在你的例子中:

* * * * * /bin/bash -l -c "cd /srv/last_song/releases/20120308133159 && script/rails runner -e production '\ "insert_latest \”;睡眠30分钟;cd /srv/last_song/releases/20120308133159 && script/rails runner -e production '\ " Song.insert_latest'\ " "

Have a look at frequent-cron - it's old but very stable and you can step down to micro-seconds. At this point in time, the only thing that I would say against it is that I'm still trying to work out how to install it outside of init.d but as a native systemd service, but certainly up to Ubuntu 18 it's running just fine still using init.d (distance may vary on latter versions). It has the added advantage (?) of ensuring that it won't spawn another instance of the PHP script unless a prior one has completed, which reduces potential memory leakage issues.

Cron作业不能用于以秒为间隔调度作业。例如，你不能安排一个cron作业每5秒运行一次。另一种方法是编写一个使用sleep 5命令的shell脚本。

使用bash while循环每5秒创建一个shell脚本。sh，如下所示。

$ cat every-5-seconds.sh
#!/bin/bash
while true
do
 /home/ramesh/backup.sh
 sleep 5
done

现在，在后台使用nohup执行这个shell脚本，如下所示。这将在退出会话后继续执行脚本。这将每5秒执行一次backup.sh shell脚本。

$ nohup ./every-5-seconds.sh &

编写一个shell脚本 创建.sh文件

纳米every30second.sh

并编写脚本

#!/bin/bash
For  (( i=1; i <= 2; i++ ))
do
    write Command here
    sleep 30
done

然后为该脚本设置cron crontab - e

(*****/家庭/用户名/每30秒.sh)

这个cron调用.sh文件每1分钟&在.sh文件命令在1分钟内运行2次

如果你想运行脚本5秒，那么将30替换为5，并像这样更改for循环:I <= 12;我+ +))

当你选择任意一秒时，计算60/你的秒并写入for循环

在shell循环中运行，示例:

#!/bin/sh    
counter=1
while true ; do
 echo $counter
 counter=$((counter+1))
 if [[ "$counter" -eq 60 ]]; then
  counter=0
 fi
 wget -q http://localhost/tool/heartbeat/ -O - > /dev/null 2>&1 &
 sleep 1
done

通过反复试验，我找到了正确的表达式:*/30 * * ?* * * 换算成每30秒。 参考:https://www.freeformatter.com/cron-expression-generator-quartz.html 他们提供了每秒运行的表达式:* * * ?* * * */x用于每x个单位运行一次。我在分位和中提琴上试过了。我相信其他人已经发现了这一点，但我想分享我的顿悟时刻!: D