我把我从几个答案和评论中找到的最好的东西结合起来。

加密文本前的随机初始化向量(@jbtule) 使用TransformFinalBlock()代替MemoryStream (@RenniePet) 没有预填充键，以避免任何人复制和粘贴灾难 正确处理和使用模式

代码:

/// <summary>
/// Simple encryption/decryption using a random initialization vector
/// and prepending it to the crypto text.
/// </summary>
/// <remarks>Based on multiple answers in http://stackoverflow.com/questions/165808/simple-two-way-encryption-for-c-sharp </remarks>
public class SimpleAes : IDisposable
{
    /// <summary>
    ///     Initialization vector length in bytes.
    /// </summary>
    private const int IvBytes = 16;

    /// <summary>
    ///     Must be exactly 16, 24 or 32 bytes long.
    /// </summary>
    private static readonly byte[] Key = Convert.FromBase64String("FILL ME WITH 24 (2 pad chars), 32 OR 44 (1 pad char) RANDOM CHARS"); // Base64 has a blowup of four-thirds (33%)

    private readonly UTF8Encoding _encoder;
    private readonly ICryptoTransform _encryptor;
    private readonly RijndaelManaged _rijndael;

    public SimpleAes()
    {
        _rijndael = new RijndaelManaged {Key = Key};
        _rijndael.GenerateIV();
        _encryptor = _rijndael.CreateEncryptor();
        _encoder = new UTF8Encoding();
    }

    public string Decrypt(string encrypted)
    {
        return _encoder.GetString(Decrypt(Convert.FromBase64String(encrypted)));
    }

    public void Dispose()
    {
        _rijndael.Dispose();
        _encryptor.Dispose();
    }

    public string Encrypt(string unencrypted)
    {
        return Convert.ToBase64String(Encrypt(_encoder.GetBytes(unencrypted)));
    }

    private byte[] Decrypt(byte[] buffer)
    {
        // IV is prepended to cryptotext
        byte[] iv = buffer.Take(IvBytes).ToArray();
        using (ICryptoTransform decryptor = _rijndael.CreateDecryptor(_rijndael.Key, iv))
        {
            return decryptor.TransformFinalBlock(buffer, IvBytes, buffer.Length - IvBytes);
        }
    }

    private byte[] Encrypt(byte[] buffer)
    {
        // Prepend cryptotext with IV
        byte [] inputBuffer = _encryptor.TransformFinalBlock(buffer, 0, buffer.Length); 
        return _rijndael.IV.Concat(inputBuffer).ToArray();
    }
}

更新2015-07-18:修复了@bpsilver和@Evereq注释中private Encrypt()方法的错误。IV被意外加密，现在以明文形式被Decrypt()前置。

命名空间System.Security.Cryptography包含TripleDESCryptoServiceProvider类和RijndaelManaged类

不要忘记添加对系统的引用。安全大会。

是，添加系统。安全程序集，导入System.Security.Cryptography名称空间。这是一个简单的对称(DES)算法加密的例子:

DESCryptoServiceProvider des = new DESCryptoServiceProvider();
des.GenerateKey();
byte[] key = des.Key; // save this!

ICryptoTransform encryptor = des.CreateEncryptor();
// encrypt
byte[] enc = encryptor.TransformFinalBlock(new byte[] { 1, 2, 3, 4 }, 0, 4);

ICryptoTransform decryptor = des.CreateDecryptor();

// decrypt
byte[] originalAgain = decryptor.TransformFinalBlock(enc, 0, enc.Length);
Debug.Assert(originalAgain[0] == 1);

如果你只是想要简单的加密(即，一个坚定的破解者可能会破解，但会锁定大多数普通用户)，只需选择两个长度相等的密码短语，例如:

deoxyribonucleicacid
while (x>0) { x-- };

和xor你的数据与他们(循环密码短语，如果需要)(a)。例如:

1111-2222-3333-4444-5555-6666-7777
deoxyribonucleicaciddeoxyribonucle
while (x>0) { x-- };while (x>0) { 

搜索二进制文件的人很可能认为DNA字符串是一个密钥，但他们不太可能认为C代码是用二进制文件保存的未初始化内存。

(a)请记住，这是非常简单的加密，根据某些定义，可能根本不被认为是加密(因为加密的目的是防止未经授权的访问，而不仅仅是使其更加困难)。当然，即使是最强的加密也不安全因为有人拿着钢管站在钥匙持有人旁边。

正如第一句所述，这是一种让随意的攻击者变得足够困难的方法，他们会继续前进。这类似于防止入室盗窃——你不需要让它变得坚不可摧，你只需要让它比隔壁的房子不那么坚不可摧:-)

我改了这个:

public string ByteArrToString(byte[] byteArr)
{
    byte val;
    string tempStr = "";
    for (int i = 0; i <= byteArr.GetUpperBound(0); i++)
    {
        val = byteArr[i];
        if (val < (byte)10)
            tempStr += "00" + val.ToString();
        else if (val < (byte)100)
            tempStr += "0" + val.ToString();
        else
            tempStr += val.ToString();
    }
    return tempStr;
}

:

    public string ByteArrToString(byte[] byteArr)
    {
        string temp = "";
        foreach (byte b in byteArr)
            temp += b.ToString().PadLeft(3, '0');
        return temp;
    }

多年后，我回来对他们说:不要这样做!看XOR加密有什么问题?获取详细信息。

一种非常简单的双向加密是异或加密。

Come up with a password. Let's have it be mypass. Convert the password into binary (according to ASCII). The password becomes 01101101 01111001 01110000 01100001 01110011 01110011. Take the message you want to encode. Convert that into binary, also. Look at the length of the message. If the message length is 400 bytes, turn the password into a 400 byte string by repeating it over and over again. It would become 01101101 01111001 01110000 01100001 01110011 01110011 01101101 01111001 01110000 01100001 01110011 01110011 01101101 01111001 01110000 01100001 01110011 01110011... (or mypassmypassmypass...) XOR the message with the long password. Send the result. Another time, XOR the encrypted message with the same password (mypassmypassmypass...). There's your message!