我有一些东西在设置。py,我想能够从模板访问,但我不知道如何做到这一点。我已经试过了

{{CONSTANT_NAME}}

但这似乎并不奏效。这可能吗?


当前回答

我发现这是Django 1.3最简单的方法:

views.py 从local_settings导入BASE_URL def根(请求): 返回render_to_response('hero.html', {'BASE_URL': BASE_URL}) hero.html var BASE_URL = '{{JS_BASE_URL}}';

其他回答

上面来自bchhun的例子很好,只是你需要从settings.py显式地构建上下文字典。下面是一个未经测试的示例,说明如何从settings.py的所有大写属性(re: "^[A-Z0-9_]+$")自动构建上下文字典。

在settings.py的末尾:

_context = {} 
local_context = locals()
for (k,v) in local_context.items():
    if re.search('^[A-Z0-9_]+$',k):
        _context[k] = str(v)

def settings_context(context):
    return _context

TEMPLATE_CONTEXT_PROCESSORS = (
...
'myproject.settings.settings_context',
...
)

如果有人像我一样发现了这个问题,那么我将发布我的解决方案,它适用于Django 2.0:

这个标记将一些settings.py变量值赋给模板的变量:

用法:{% get_settings_value template_var "SETTINGS_VAR" %}

应用程序/ templatetags / my_custom_tags.py:

from django import template
from django.conf import settings

register = template.Library()

class AssignNode(template.Node):
    def __init__(self, name, value):
        self.name = name
        self.value = value

    def render(self, context):
        context[self.name] = getattr(settings, self.value.resolve(context, True), "")
        return ''

@register.tag('get_settings_value')
def do_assign(parser, token):
    bits = token.split_contents()
    if len(bits) != 3:
        raise template.TemplateSyntaxError("'%s' tag takes two arguments" % bits[0])
    value = parser.compile_filter(bits[2])
    return AssignNode(bits[1], value)

你的模板:

{% load my_custom_tags %}

# Set local template variable:
{% get_settings_value settings_debug "DEBUG" %}

# Output settings_debug variable:
{{ settings_debug }}

# Use variable in if statement:
{% if settings_debug %}
... do something ...
{% else %}
... do other stuff ...
{% endif %}

查看Django如何创建自定义模板标签的文档:https://docs.djangoproject.com/en/2.0/howto/custom-template-tags/

我发现这是Django 1.3最简单的方法:

views.py 从local_settings导入BASE_URL def根(请求): 返回render_to_response('hero.html', {'BASE_URL': BASE_URL}) hero.html var BASE_URL = '{{JS_BASE_URL}}';

对于那些想要使用@Berislav的方法(自定义模板标签)和if标签的人:

/ app / templatetags / my_settings.py:

from django import template
from django.conf import settings

register = template.Library()

@register.simple_tag
def settings_value(name):
    return getattr(settings, name, "")

模板文件:

<!-- Load your tags -->
{% load my_settings %}
{% settings_value 'ENABLE_FEATURE_A' as ENABLE_FEATURE_A %}

{% if ENABLE_FEATURE_A %}
<!-- Feature A stuffs -->
{% endif %}

If we were to compare context vs. template tags on a single variable, then knowing the more efficient option could be benificial. However, you might be better off to dip into the settings only from templates that need that variable. In that case it doesn't make sense to pass the variable into all templates. But if you are sending the variable into a common template such as the base.html template, Then it would not matter as the base.html template is rendered on every request, so you can use either methods.

如果您决定使用template tags选项,那么使用下面的代码,因为它允许您传入一个默认值,以防有问题的变量未定义。

例如:get_from_settings my_variable as my_context_value

例如:get_from_settings my_variable my_default as my_context_value

class SettingsAttrNode(Node):
    def __init__(self, variable, default, as_value):
        self.variable = getattr(settings, variable, default)
        self.cxtname = as_value

    def render(self, context):
        context[self.cxtname] = self.variable
        return ''


def get_from_setting(parser, token):
    as_value = variable = default = ''
    bits = token.contents.split()
    if len(bits) == 4 and bits[2] == 'as':
        variable = bits[1]
        as_value = bits[3]
    elif len(bits) == 5 and bits[3] == 'as':
        variable     = bits[1]
        default  = bits[2]
        as_value = bits[4]
    else:
        raise TemplateSyntaxError, "usage: get_from_settings variable default as value " \
                "OR: get_from_settings variable as value"

    return SettingsAttrNode(variable=variable, default=default, as_value=as_value)

get_from_setting = register.tag(get_from_setting)