如何删除已合并的分支?我可以一次删除所有分支,而不是逐个删除每个分支吗?


当前回答

我使用一个Python脚本,它自动执行最流行的答案中的步骤,并检查其余分支,看看它们是否会在合并时产生任何更改,如果没有,则交互提示删除它们:https://github.com/robertknight/prune-merged-branches.

其他回答

在安装了gitbash的Windows上,egrep-v将无法工作

git branch --merged | grep -E -v "(master|test|dev)" | xargs git branch -d

其中grep-E-v等于egrep-v

使用-d删除已合并的分支或-D删除未合并的分支

以下查询适用于我

for branch in  `git branch -r --merged | grep -v '\*\|master\|develop'|awk 'NR > 0 {print$1}'|awk '{gsub(/origin\//, "")}1'`;do git push origin --delete $branch; done

这将过滤grep管道中的任何给定分支。

在http克隆上运行良好,但在ssh连接上运行不太好。

对于Windows,您可以使用以下命令安装Cygwin并删除所有远程分支:

git branch -r --merged | "C:\cygwin64\bin\grep.exe" -v master | "C:\cygwin64\bin\sed.exe" 's/origin\///' | "C:\cygwin64\bin\xargs.exe" -n 1 git push --delete origin

我的Bash脚本贡献大致基于mmrobin的答案。

它需要一些有用的参数来指定include和exclude,或者只检查/删除本地或远程分支,而不是两者。

#!/bin/bash

# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1

while [ $# -gt 0 ]; do
  case "$1" in
  -i) shift; includes="$includes $1" ;;
  -e) shift; excludes="$1" ;;
  --no-local) local=0 ;;
  --no-remote) remote=0 ;;
  --all) merged= ;;
  *) echo "Unknown argument $1"; exit 1 ;;
  esac
  shift   # next option
done

if [ "$includes" == "" ]; then
  includes=".*"
else
  includes="($(echo $includes | sed -e 's/ /|/g'))"
fi

current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
  echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"

git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
  echo "No existing branches have been merged into $current_branch."
else
  echo "This will remove the following branches:"
  if [ "$remote" == 1 -a -n "$remote_branches" ]; then
    echo "$remote_branches"
  fi
  if [ "$local" == 1 -a -n "$local_branches" ]; then
    echo "$local_branches"
  fi
  read -p "Continue? (y/n): " -n 1 choice
  echo
  if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
    if [ "$remote" == 1 ]; then
      remotes=$(git remote)
      # Remove remote branches
      for remote in $remotes
      do
        branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
        git push $remote $branches
      done
    fi

    if [ "$local" == 1 ]; then
      # Remove local branches
      locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
      if [ -z "$locals" ]; then
        echo "No branches removed."
      else
        git branch -d $(echo "$locals" | tr -d '\n')
      fi
    fi
  fi
fi

要删除远程上已合并的所有分支,请执行以下操作:

git branch -r --merged | grep -v master | sed 's/origin\//:/' | xargs -n 1 git push origin

在Git的最新版本中

git branch -r --merged | grep -v master | sed 's/origin\///' | xargs -n 1 git push --delete origin

UPDATE(通过@oliver;因为不适合注释,但已经有足够的答案了):如果您在分支ABC上,那么ABC将出现在git branch-r--merged的结果中,因为未指定分支,所以分支默认为当前分支,分支始终符合自身合并的条件(因为分支和自身之间没有区别!)。

因此,指定分支:

git branch -r --merged master | grep -v master ...

OR第一个结账主机:

git checkout master | git branch -r --merged | grep -v ...