我的Bash脚本贡献大致基于mmrobin的答案。

它需要一些有用的参数来指定include和exclude，或者只检查/删除本地或远程分支，而不是两者。

#!/bin/bash

# exclude branches regex, configure as "(branch1|branch2|etc)$"
excludes_default="(master|next|ag/doc-updates)$"
excludes="__NOTHING__"
includes=
merged="--merged"
local=1
remote=1

while [ $# -gt 0 ]; do
  case "$1" in
  -i) shift; includes="$includes $1" ;;
  -e) shift; excludes="$1" ;;
  --no-local) local=0 ;;
  --no-remote) remote=0 ;;
  --all) merged= ;;
  *) echo "Unknown argument $1"; exit 1 ;;
  esac
  shift   # next option
done

if [ "$includes" == "" ]; then
  includes=".*"
else
  includes="($(echo $includes | sed -e 's/ /|/g'))"
fi

current_branch=$(git branch --no-color 2> /dev/null | sed -e '/^[^*]/d' -e 's/* \(.*\)/\1/')
if [ "$current_branch" != "master" ]; then
  echo "WARNING: You are on branch $current_branch, NOT master."
fi
echo -e "Fetching branches...\n"

git remote update --prune
remote_branches=$(git branch -r $merged | grep -v "/$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
local_branches=$(git branch $merged | grep -v "$current_branch$" | grep -v -E "$excludes" | grep -v -E "$excludes_default" | grep -E "$includes")
if [ -z "$remote_branches" ] && [ -z "$local_branches" ]; then
  echo "No existing branches have been merged into $current_branch."
else
  echo "This will remove the following branches:"
  if [ "$remote" == 1 -a -n "$remote_branches" ]; then
    echo "$remote_branches"
  fi
  if [ "$local" == 1 -a -n "$local_branches" ]; then
    echo "$local_branches"
  fi
  read -p "Continue? (y/n): " -n 1 choice
  echo
  if [ "$choice" == "y" ] || [ "$choice" == "Y" ]; then
    if [ "$remote" == 1 ]; then
      remotes=$(git remote)
      # Remove remote branches
      for remote in $remotes
      do
        branches=$(echo "$remote_branches" | grep "$remote/" | sed "s/$remote\/\(.*\)/:\1 /g" | tr -d '\n')
        git push $remote $branches
      done
    fi

    if [ "$local" == 1 ]; then
      # Remove local branches
      locals=$(echo "$local_branches" | sed 's/origin\///g' | tr -d '\n')
      if [ -z "$locals" ]; then
        echo "No branches removed."
      else
        git branch -d $(echo "$locals" | tr -d '\n')
      fi
    fi
  fi
fi

以下查询适用于我

for branch in  `git branch -r --merged | grep -v '\*\|master\|develop'|awk 'NR > 0 {print$1}'|awk '{gsub(/origin\//, "")}1'`;do git push origin --delete $branch; done

这将过滤grep管道中的任何给定分支。

在http克隆上运行良好，但在ssh连接上运行不太好。

截至2018.07

将其添加到~/.gitconfig的[alias]部分：

sweep = !"f() { git branch --merged | egrep -v \"(^\\*|master|dev)\" || true | xargs git branch -d; }; f"

现在，您只需调用git扫描来执行所需的清理。

如果要删除合并的分支，则只需删除远程跟踪分支，除非您另有说明。

因此，要删除这些分支，您可以通过

git branch--remote--合并原始/主|egrep-v“（^\*|master|development）”|cut-b 10-|xargs git push--删除原始

这将删除除主分支和开发分支外的所有合并分支（合并到主分支）。

对于我来说，gitbranch--merged不显示通过GitHub PR合并的分支。我不确定原因，但我使用以下行删除所有没有远程跟踪分支的本地分支：

diff <(git branch --format "%(refname:short)") <(git branch -r | grep -v HEAD | cut -d/ -f2-) | grep '<' | cut -c 3- | xargs git branch -D

说明：

gitbranch--格式“%（refname:short）”提供本地分支列表gitbranch-r | grep-v HEAD | cut-d/-f2-提供远程分支列表，过滤掉HEADdiff<（…）<（grep“<”筛选第一个列表中存在但第二个列表中不存在的分支cut-c 3-给出从第3个字符开始的行，从而删除前缀<xargs git branch-D针对每个分支名称执行git branch-D

或者，可以这样避免grep-v“<”：

diff --old-line-format="%L" --new-line-format="" --unchanged-line-format="" <(git branch --format "%(refname:short)") <(git branch -r | grep -v HEAD | cut -d/ -f2-) | xargs git branch -D

git从git额外回购中删除合并的分支。

https://github.com/tj/git-extras/blob/master/Commands.md#git-删除合并的分支