有一件事你必须明白,第二件事你决定使用一个常规的表达式来验证电子邮件:这可能不是一个好主意,一旦你达成协议,有很多实施,可以让你在那里半路,这篇文章会把它们合成好。

简而言之,但是,唯一的方式是绝对的,肯定的是,用户输入的是实际上一个电子邮件是实际上发送一个电子邮件,看看发生了什么。

我写了一个JavaScript电子邮件验证器,完全兼容PHP的filter_var($值,FILTER_VALIDATE_EMAIL)实施。

https://github.com/mpyw/FILTER_VALIDATE_EMAIL.js

import validateEmail from 'filter-validate-email'

const value = '...'
const result = validateEmail(value)

相当于:

<?php

$value = '...';
$result = (bool)filter_var($value, FILTER_VALIDATE_EMAIL, FILTER_FLAG_EMAIL_UNICODE);

Regex 更新! 尝试此

let val = 'email@domain.com';
if(/^[a-z0-9][a-z0-9-_\.]+@([a-z]|[a-z0-9]?[a-z0-9-]+[a-z0-9])\.[a-z0-9]{2,10}(?:\.[a-z]{2,10})?$/.test(val)) {
   console.log('passed');
}

字体编辑完整版本

//
export const emailValid = (val:string):boolean => /^[a-z0-9][a-z0-9-_\.]+@([a-z]|[a-z0-9]?[a-z0-9-]+[a-z0-9])\.[a-z0-9]{2,10}(?:\.[a-z]{2,10})?$/.test(val);

更多信息 https://git.io/vhEfc

此分類上一篇

如果你想要一個人可以閱讀和維持的東西,我會推薦Masala Parser(我是它的創造者之一)。

import {C,Streams} from '@masala/parser'

const illegalCharset = ' @\u00A0\n\t';
const extendedIllegalCharset = illegalCharset + '.';


// Assume 'nicolas@internal.masala.co.uk'
export function simpleEmail() {

    return C.charNotIn(illegalCharset).rep() // 'nicolas'
        .then(C.char('@'))
        .then(subDns())  //'internal.masala.co.'
        .then(C.charNotIn(extendedIllegalCharset).rep()) //'uk'
        .eos(); // Must be end of the char stream
}

// x@internal.masala.co.uk => extract 'internal.masala.co.'
function  subDns() {
    return C.charNotIn(extendedIllegalCharset).rep().then(C.char('.')).rep()
}

function validateEmail(email:string) {
    console.log(email + ': ' + (simpleEmail().parse(Streams.ofString(email)).isAccepted()));
}


validateEmail('nicolas@internal.masala.co.uk'); // True
validateEmail('nz@co.'); // False, trailing "."

如果你想接受最终丑陋的电子邮件版本,你可以在第一部分添加引用:

function inQuote() {
    return C.char('"')
        .then(C.notChar('"').rep())
        .then(C.char('"'))
}

function allEmail() {

    return inQuote().or(C.charNotIn(illegalCharset))
        .rep() // repeat (inQuote or anyCharacter)
        .then(C.char('@'))
        .then(subDns())
        .then(C.charNotIn(extendedIllegalCharset).rep())
        .eos() // Must be end of the character stream
        // Create a structure
        .map(function (characters) { return ({ email: characters.join('') }); });
}

“Nicolas”“love-quotes”@masala.co.uk”是正式有效的,但应该在您的系统中吗?

至少与马萨拉,你给自己一个机会来理解它。

这个问题比一眼看起来更难回答。

世界各地有大量的人正在寻找“统治他们所有”,但事实是,有大量的电子邮件提供商。

为什么? 根据 RFC: https://en.wikipedia.org/wiki/Email_address#RFC_specification。

The local-part of the email address may use any of these ASCII characters:

- uppercase and lowercase Latin letters A to Z and a to z;
- digits 0 to 9;
- special characters !#$%&'*+-/=?^_`{|}~;
- dot ., provided that it is not the first or last character unless quoted, and provided also that it does not appear consecutively unless quoted (e.g. John..Doe@example.com is not allowed but "John..Doe"@example.com is allowed);[6]
Note that some mail servers wildcard local parts, typically the characters following a plus and less often the characters following a minus, so fred+bah@domain and fred+foo@domain might end up in the same inbox as fred+@domain or even as fred@domain. This can be useful for tagging emails for sorting, see below, and for spam control. Braces { and } are also used in that fashion, although less often.
- space and "(),:;<>@[\] characters are allowed with restrictions (they are only allowed inside a quoted string, as described in the paragraph below, and in addition, a backslash or double-quote must be preceded by a backslash);
- comments are allowed with parentheses at either end of the local-part; e.g. john.smith(comment)@example.com and (comment)john.smith@example.com are both equivalent to john.smith@example.com.

A__z/J0hn.sm{it!}h_comment@example.com.co

如果你尝试这个地址我赌它将失败在所有的或大部分的regex发布在整个网络上. 但记住这个地址遵循RFC规则,所以它是公平有效的。

想象一下我的失望,因为我无法在任何地方注册与这些 regex 检查!!!

如何处理,是的?

"very.(),:;<>[]\".VERY.\"very@\\ \"very\".unusual"@strange.example.com

在这样做时,一个好做法是“重新输入您的电子邮件”输入,以避免用户输入错误,如果这对您来说不够,请添加一个提前提交的模型窗口,标题为“这是您的当前电子邮件吗?”然后用户输入的电子邮件在一个H2标签中,您知道,清楚地显示他们输入的电子邮件,然后一个“是的,提交”按钮。

如果你正在使用NG模式和材料,这就是工作。

vm.validateEmail = '([a-zA-Z0-9_.]{1,})((@[a-zA-Z]{2,})[\\\.]([a-zA-Z]{2}|[a-zA-Z]{3}))';