这就是字典
cars = {'A':{'speed':70,
'color':2},
'B':{'speed':60,
'color':3}}
使用这个for循环
for keys,values in cars.items():
print(keys)
print(values)
它打印以下内容:
B
{'color': 3, 'speed': 60}
A
{'color': 2, 'speed': 70}
但是我希望程序像这样打印它:
B
color : 3
speed : 60
A
color : 2
speed : 70
我刚开始学习字典，所以我不知道该怎么做。
当前回答
###newbie exact answer desired (Python v3):
###=================================
"""
cars = {'A':{'speed':70,
'color':2},
'B':{'speed':60,
'color':3}}
"""
for keys, values in reversed(sorted(cars.items())):
print(keys)
for keys,values in sorted(values.items()):
print(keys," : ", values)
"""
Output:
B
color : 3
speed : 60
A
color : 2
speed : 70
##[Finished in 0.073s]
"""
其他回答
for car,info in cars.items():
print(car)
for key,value in info.items():
print(key, ":", value)
如果你知道树只有两层，这是可行的:
for k1 in cars:
print(k1)
d = cars[k1]
for k2 in d
print(k2, ':', d[k2])
我认为列表理解是最干净的方法:
mydict = {a:1, b:2, c:3}
[(print("key:", key, end='\t'), print('value:', value)) for key, value in mydict.items()]
这是我对这个问题的解决办法。我认为它在方法上是相似的，但比其他一些答案更简单。它还允许任意数量的子字典，并且似乎适用于任何数据类型(我甚至在一个以函数为值的字典上测试了它):
def pprint(web, level):
for k,v in web.items():
if isinstance(v, dict):
print('\t'*level, f'{k}: ')
level += 1
pprint(v, level)
level -= 1
else:
print('\t'*level, k, ": ", v)
###newbie exact answer desired (Python v3):
###=================================
"""
cars = {'A':{'speed':70,
'color':2},
'B':{'speed':60,
'color':3}}
"""
for keys, values in reversed(sorted(cars.items())):
print(keys)
for keys,values in sorted(values.items()):
print(keys," : ", values)
"""
Output:
B
color : 3
speed : 60
A
color : 2
speed : 70
##[Finished in 0.073s]
"""
