这就是字典
cars = {'A':{'speed':70,
'color':2},
'B':{'speed':60,
'color':3}}
使用这个for循环
for keys,values in cars.items():
print(keys)
print(values)
它打印以下内容:
B
{'color': 3, 'speed': 60}
A
{'color': 2, 'speed': 70}
但是我希望程序像这样打印它:
B
color : 3
speed : 60
A
color : 2
speed : 70
我刚开始学习字典，所以我不知道该怎么做。
当前回答
修改MrWonderful代码
import sys
def print_dictionary(obj, ident):
if type(obj) == dict:
for k, v in obj.items():
sys.stdout.write(ident)
if hasattr(v, '__iter__'):
print k
print_dictionary(v, ident + ' ')
else:
print '%s : %s' % (k, v)
elif type(obj) == list:
for v in obj:
sys.stdout.write(ident)
if hasattr(v, '__iter__'):
print_dictionary(v, ident + ' ')
else:
print v
else:
print obj
其他回答
如果你知道树只有两层，这是可行的:
for k1 in cars:
print(k1)
d = cars[k1]
for k2 in d
print(k2, ':', d[k2])
修改MrWonderful代码
import sys
def print_dictionary(obj, ident):
if type(obj) == dict:
for k, v in obj.items():
sys.stdout.write(ident)
if hasattr(v, '__iter__'):
print k
print_dictionary(v, ident + ' ')
else:
print '%s : %s' % (k, v)
elif type(obj) == list:
for v in obj:
sys.stdout.write(ident)
if hasattr(v, '__iter__'):
print_dictionary(v, ident + ' ')
else:
print v
else:
print obj
我认为列表理解是最干净的方法:
mydict = {a:1, b:2, c:3}
[(print("key:", key, end='\t'), print('value:', value)) for key, value in mydict.items()]
检查下面的一行代码:
print('\n'.join("%s\n%s" % (key1,('\n'.join("%s : %r" % (key2,val2) for (key2,val2) in val1.items()))) for (key1,val1) in cars.items()))
输出:
A
speed : 70
color : 2
B
speed : 60
color : 3
###newbie exact answer desired (Python v3):
###=================================
"""
cars = {'A':{'speed':70,
'color':2},
'B':{'speed':60,
'color':3}}
"""
for keys, values in reversed(sorted(cars.items())):
print(keys)
for keys,values in sorted(values.items()):
print(keys," : ", values)
"""
Output:
B
color : 3
speed : 60
A
color : 2
speed : 70
##[Finished in 0.073s]
"""
