我不知道为什么我没有找到最好的答案，但这真的很简单。

recyclerView.smoothScrollToPosition(position);

没有错误

创建动画

我所做的恢复滚动位置后刷新RecyclerView按钮点击:

if (linearLayoutManager != null) {

    index = linearLayoutManager.findFirstVisibleItemPosition();
    View v = linearLayoutManager.getChildAt(0);
    top = (v == null) ? 0 : (v.getTop() - linearLayoutManager.getPaddingTop());
    Log.d("TAG", "visible position " + " " + index);
}

else{
    index = 0;
}

linearLayoutManager = new LinearLayoutManager(getApplicationContext());
linearLayoutManager.scrollToPositionWithOffset(index, top);

在创建linearLayoutManager对象之前，从顶部获得第一个可见项的偏移量，并在实例化它之后，调用linearLayoutManager对象的scrollToPositionWithOffset。

如果你正在使用LinearLayoutManager或交错的GridLayoutManager，它们都有一个scrollToPositionWithOffset方法，该方法既取位置，也取项目从RecyclerView开始的偏移量，这似乎可以完成你所需要的(将偏移量设置为0应该与顶部对齐)。

例如:

//Scroll item 2 to 20 pixels from the top
linearLayoutManager.scrollToPositionWithOffset(2, 20);

调速器也一样

public class SmoothScrollLinearLayoutManager extends LinearLayoutManager {
private static final float MILLISECONDS_PER_INCH = 110f;
private Context mContext;

public SmoothScrollLinearLayoutManager(Context context,int orientation, boolean reverseLayout) {
    super(context,orientation,reverseLayout);
    mContext = context;
}

@Override
public void smoothScrollToPosition(RecyclerView recyclerView, RecyclerView.State state,
                                   int position) {
    RecyclerView.SmoothScroller smoothScroller = new TopSnappedSmoothScroller(recyclerView.getContext()){
        //This controls the direction in which smoothScroll looks for your view
        @Override
        public PointF computeScrollVectorForPosition(int targetPosition) {
            return new PointF(0, 1);
        }

        //This returns the milliseconds it takes to scroll one pixel.
        @Override
        protected float calculateSpeedPerPixel(DisplayMetrics displayMetrics) {
            return MILLISECONDS_PER_INCH / displayMetrics.densityDpi;
        }
    };
    smoothScroller.setTargetPosition(position);
    startSmoothScroll(smoothScroller);
}


private class TopSnappedSmoothScroller extends LinearSmoothScroller {
    public TopSnappedSmoothScroller(Context context) {
        super(context);

    }

    @Override
    public PointF computeScrollVectorForPosition(int targetPosition) {
        return SmoothScrollLinearLayoutManager.this
                .computeScrollVectorForPosition(targetPosition);
    }

    @Override
    protected int getVerticalSnapPreference() {
        return SNAP_TO_START;
    }
}
}

试试对我有效的方法，酷!

创建一个私有静态变量int displayedposition = 0;

现在你的RecyclerView在你的活动中的位置。

myRecyclerView.setOnScrollListener(new RecyclerView.OnScrollListener() {
            @Override
            public void onScrollStateChanged(RecyclerView recyclerView, int newState) {
                super.onScrollStateChanged(recyclerView, newState);
            }

            @Override
            public void onScrolled(RecyclerView recyclerView, int dx, int dy) {
                super.onScrolled(recyclerView, dx, dy);

                LinearLayoutManager llm = (LinearLayoutManager) myRecyclerView.getLayoutManager();


                displayedposition = llm.findFirstVisibleItemPosition();


            }
        });

将此语句放置在视图中显示前站点的位置。

LinearLayoutManager llm = (LinearLayoutManager) mRecyclerView.getLayoutManager();
        llm.scrollToPositionWithOffset(displayedposition , youList.size());

好吧，就是这样，它对我来说很好

如果你的LayoutManager是LinearLayoutManager，你可以使用scrollToPositionWithOffset(position,0);它会让你的项目成为列表中第一个可见的项目。否则，你可以直接在RecyclerView上使用smoothscrolltopposition。

我最终使用了下面的代码。

 RecyclerView.LayoutManager layoutManager = mainList.getLayoutManager();
        if (layoutManager instanceof LinearLayoutManager) {
            // Scroll to item and make it the first visible item of the list.
            ((LinearLayoutManager) layoutManager).scrollToPositionWithOffset(position, 0);
        } else {
            mainList.smoothScrollToPosition(position);
        }