有人能告诉我如何将参数传递给线程吗?

另外,匿名类是如何工作的?


当前回答

通过Runnable或Thread类的构造函数

class MyThread extends Thread {

    private String to;

    public MyThread(String to) {
        this.to = to;
    }

    @Override
    public void run() {
        System.out.println("hello " + to);
    }
}

public static void main(String[] args) {
    new MyThread("world!").start();
}

其他回答

参数通过start()和run()方法传递:

// Tester
public static void main(String... args) throws Exception {
    ThreadType2 t = new ThreadType2(new RunnableType2(){
        public void run(Object object) {
            System.out.println("Parameter="+object);
        }});
    t.start("the parameter");
}

// New class 1 of 2
public class ThreadType2 {
    final private Thread thread;
    private Object objectIn = null;
    ThreadType2(final RunnableType2 runnableType2) {
        thread = new Thread(new Runnable() {
            public void run() {
                runnableType2.run(objectIn);
            }});
    }
    public void start(final Object object) {
        this.objectIn = object;
        thread.start();
    }
    // If you want to do things like setDaemon(true); 
    public Thread getThread() {
        return thread;
    }
}

// New class 2 of 2
public interface RunnableType2 {
    public void run(Object object);
}

通过Runnable或Thread类的构造函数

class MyThread extends Thread {

    private String to;

    public MyThread(String to) {
        this.to = to;
    }

    @Override
    public void run() {
        System.out.println("hello " + to);
    }
}

public static void main(String[] args) {
    new MyThread("world!").start();
}

从Java 8开始,您可以使用lambda来捕获有效的final参数。例如:

final String param1 = "First param";
final int param2 = 2;
new Thread(() -> {
    // Do whatever you want here: param1 and param2 are in-scope!
    System.out.println(param1);
    System.out.println(param2);
}).start();

这个答案来得很晚,但也许有人会觉得它有用。它是关于如何在不声明命名类的情况下将参数传递给Runnable(对于内联程序来说很方便):

    String someValue = "Just a demo, really...";

    new Thread(new Runnable() {
        private String myParam;

        public Runnable init(String myParam) {
            this.myParam = myParam;
            return this;
        }

        @Override
        public void run() {
            System.out.println("This is called from another thread.");
            System.out.println(this.myParam);
        }
    }.init(someValue)).start();

当然,您可以将start的执行推迟到某个更方便或合适的时刻。这取决于你init方法的签名(所以它可能需要更多和/或不同的参数),当然甚至它的名字,但基本上你得到了一个想法。

事实上,还有另一种将参数传递给匿名类的方法,即使用初始化块。考虑一下:

    String someValue = "Another demo, no serious thing...";
    int anotherValue = 42;

    new Thread(new Runnable() {
        private String myParam;
        private int myOtherParam;
        // instance initializer
        {
            this.myParam = someValue;
            this.myOtherParam = anotherValue;
        }

        @Override
        public void run() {
            System.out.println("This comes from another thread.");
            System.out.println(this.myParam + ", " + this.myOtherParam);
        }
    }).start();

所有都发生在初始化程序块内部。

对于匿名类:

在这里回答问题编辑是如何工作的匿名类

   final X parameter = ...; // the final is important
   Thread t = new Thread(new Runnable() {
       p = parameter;
       public void run() { 
         ...
       };
   t.start();

命名的类:

您有一个扩展Thread(或实现Runnable)的类和一个带有您希望传递的参数的构造函数。然后,当你创建新线程时,你必须传入参数,然后启动线程,就像这样:

Thread t = new MyThread(args...);
t.start();

Runnable是一个比Thread更好的解决方案。所以我更喜欢:

   public class MyRunnable implements Runnable {
      private X parameter;
      public MyRunnable(X parameter) {
         this.parameter = parameter;
      }

      public void run() {
      }
   }
   Thread t = new Thread(new MyRunnable(parameter));
   t.start();

这个答案基本上与这个类似的问题相同:如何将参数传递给Thread对象