如何计算特定字符串在另一个字符串中出现的次数。例如，这就是我试图在Javascript中做的事情：
var temp = "This is a string.";
alert(temp.count("is")); //should output '2'
当前回答
const getLetterMatchCount = (guessedWord, secretWord) => {
const secretLetters = secretWord.split('');
const guessedLetterSet = new Set(guessedWord);
return secretLetters.filter(letter => guessedLetterSet.has(letter)).length;
};
const str = "rahul";
const str1 = "rajendra";
getLetterMatchCount(str, str1)
其他回答
参数：ustring：超集字符串countChar：子字符串
一个计算JavaScript中子字符串出现次数的函数：
函数subStringCount（ustring，countChar）{var correspCount=0；var corresp=false；变量量=0；var prevChar=空；对于（var i=0；i！=ustring.length；i++）{如果（ustring.charAt（i）==countChar.charAt（0）&&corresp==false）{corresp=真；correspCount+=1；如果（correspCount==countChar.length）{数量+=1；corresp=false；correspCount=0；}prevChar=1；}否则如果（ustring.charAt（i）==countChar.charAt（prevChar）&&corresp==true）{correspCount+=1；如果（correspCount==countChar.length）{数量+=1；corresp=false；correspCount=0；prevChar=空；}其他{prevChar+=1；}}其他{corresp=false；correspCount=0；}} 回报金额；}console.log（subStringCount（“Hello World，Hello World”，“ll”））；
试试看
<?php
$str = "33,33,56,89,56,56";
echo substr_count($str, '56');
?>
<script type="text/javascript">
var temp = "33,33,56,89,56,56";
var count = temp.match(/56/g);
alert(count.length);
</script>
const getLetterMatchCount = (guessedWord, secretWord) => {
const secretLetters = secretWord.split('');
const guessedLetterSet = new Set(guessedWord);
return secretLetters.filter(letter => guessedLetterSet.has(letter)).length;
};
const str = "rahul";
const str1 = "rajendra";
getLetterMatchCount(str, str1)
太老了，但我今天需要做这样的事情，只想事后检查一下。对我来说工作很快。
String.prototype.count = function(substr,start,overlap) {
overlap = overlap || false;
start = start || 0;
var count = 0,
offset = overlap ? 1 : substr.length;
while((start = this.indexOf(substr, start) + offset) !== (offset - 1))
++count;
return count;
};
你可以试试这个
let count = s.length - s.replace(/is/g, "").length;
