重构了已接受的答案，因此不再需要使用注释，因为我讨厌注释。这也更容易用茉莉花进行测试。

    allowBackspaceDeleteTabEscapeEnterPress: function(event){
    return ($.inArray(event.keyCode, [46, 8, 9, 27, 13, 190]) >= 0);
},
allowContorlAPress: function(event){
    return (event.keyCode == 65 && event.ctrlKey === true)
},
allowHomeEndLeftRightPress: function(event){
    return (event.keyCode >= 35 && event.keyCode <= 39)
},
theKeyPressedIsEditRelated: function (event) {
    return (this.allowBackspaceDeleteTabEscapeEnterPress(event)
            || this.allowContorlAPress(event)
            || this.allowHomeEndLeftRightPress(event));
},
isNotFromTheNumKeyPad: function (event) {
    return (event.keyCode < 96 || event.keyCode > 105);
},
isNotFromTopRowNumberKeys: function (event) {
    return (event.keyCode < 48 || event.keyCode > 57);
},
theKeyIsNonNumeric: function (event) {
   return (event.shiftKey
           || (this.isNotFromTopRowNumberKeys(event)
                && this.isNotFromTheNumKeyPad(event)));
},
bindInputValidator: function(){
    $('.myinputclassselector').keydown(function (event) {
        if(this.validateKeyPressEvent(event)) return false;
    });
},
validateKeyPressEvent: function(event){
    if(this.theKeyPressedIsEditRelated(event)){
        return;
    } else {
        if (this.theKeyIsNonNumeric(event)) {
            event.preventDefault();
        }
    }
}

为了更详细地说明#3的答案，我将执行以下操作(注意:仍然不支持通过键盘或鼠标粘贴操作):

$('#txtNumeric').keypress(
            function(event) {
                //Allow only backspace and delete
                if (event.keyCode != 46 && event.keyCode != 8) {
                    if (!parseInt(String.fromCharCode(event.which))) {
                        event.preventDefault();
                    }
                }
            }
        );

检查输入值是否为数字的简单方法是:

var checknumber = $('#textbox_id').val();

    if(jQuery.isNumeric(checknumber) == false){
        alert('Please enter numeric value');
        $('#special_price').focus();
        return;
    }

对我来说更简单的是

jQuery('.plan_eff').keyup(function () {     
  this.value = this.value.replace(/[^1-9\.]/g,'');
});

如果你必须解决变音符和特殊字符，尝试使用这个:

$(this).on( 'keypress', function( e )
{
    // Ensure that it is a number and stop the keypress
    if (e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) {
        e.preventDefault();
    }
});  

你可以使用一个简单的JavaScript正则表达式来测试纯数字字符:

/^[0-9]+$/.test(input);

如果输入是数字，则返回true，否则返回false。

或事件键码，简单使用如下:

     // Allow: backspace, delete, tab, escape, enter, ctrl+A and .
    if ($.inArray(e.keyCode, [46, 8, 9, 27, 13, 110, 190]) !== -1 ||
         // Allow: Ctrl+A
        (e.keyCode == 65 && e.ctrlKey === true) || 
         // Allow: home, end, left, right
        (e.keyCode >= 35 && e.keyCode <= 39)) {
             // let it happen, don't do anything
             return;
    }

    var charValue = String.fromCharCode(e.keyCode)
        , valid = /^[0-9]+$/.test(charValue);

    if (!valid) {
        e.preventDefault();
    }