这似乎牢不可破。

// Prevent NULL input and replace text.
$(document).on('change', 'input[type="number"]', function (event) {
    this.value = this.value.replace(/[^0-9\.]+/g, '');
    if (this.value < 1) this.value = 0;
});

// Block non-numeric chars.
$(document).on('keypress', 'input[type="number"]', function (event) {
    return (((event.which > 47) && (event.which < 58)) || (event.which == 13));
});

我认为这对每个人都有帮助

  $('input.valid-number').bind('keypress', function(e) { 
return ( e.which!=8 && e.which!=0 && (e.which<48 || e.which>57)) ? false : true ;
  })

我想帮点忙，我做了我的版本，onlyNumbers函数…

function onlyNumbers(e){
    var keynum;
    var keychar;

    if(window.event){  //IE
        keynum = e.keyCode;
    }
    if(e.which){ //Netscape/Firefox/Opera
        keynum = e.which;
    }
    if((keynum == 8 || keynum == 9 || keynum == 46 || (keynum >= 35 && keynum <= 40) ||
       (event.keyCode >= 96 && event.keyCode <= 105)))return true;

    if(keynum == 110 || keynum == 190){
        var checkdot=document.getElementById('price').value;
        var i=0;
        for(i=0;i<checkdot.length;i++){
            if(checkdot[i]=='.')return false;
        }
        if(checkdot.length==0)document.getElementById('price').value='0';
        return true;
    }
    keychar = String.fromCharCode(keynum);

    return !isNaN(keychar);
}

只需添加输入标签“…输入……id="price" onkeydown="return onlyNumbers(event)"…"然后你就完成了;)

使用jQuery.validate做一些相当简单的事情

$(document).ready(function() {
    $("#formID").validate({
        rules: {
            field_name: {
                numericOnly:true
            }
        }
    });
});

$.validator.addMethod('numericOnly', function (value) {
       return /^[0-9]+$/.test(value);
}, 'Please only enter numeric values (0-9)');

我也想回答:)

    $('.justNum').keydown(function(event){
        var kc, num, rt = false;
        kc = event.keyCode;
        if(kc == 8 || ((kc > 47 && kc < 58) || (kc > 95 && kc < 106))) rt = true;
        return rt;
    })
    .bind('blur', function(){
        num = parseInt($(this).val());
        num = isNaN(num) ? '' : num;
        if(num && num < 0) num = num*-1;
        $(this).val(num);
    });

就是这样……只是数字。:)几乎只用“模糊”就可以了，但是……

你可以使用一个简单的JavaScript正则表达式来测试纯数字字符:

/^[0-9]+$/.test(input);

如果输入是数字，则返回true，否则返回false。

或事件键码，简单使用如下:

     // Allow: backspace, delete, tab, escape, enter, ctrl+A and .
    if ($.inArray(e.keyCode, [46, 8, 9, 27, 13, 110, 190]) !== -1 ||
         // Allow: Ctrl+A
        (e.keyCode == 65 && e.ctrlKey === true) || 
         // Allow: home, end, left, right
        (e.keyCode >= 35 && e.keyCode <= 39)) {
             // let it happen, don't do anything
             return;
    }

    var charValue = String.fromCharCode(e.keyCode)
        , valid = /^[0-9]+$/.test(charValue);

    if (!valid) {
        e.preventDefault();
    }