我正在创建一个网页,其中我有一个输入文本字段,我想只允许数字字符,如(0,1,2,3,4,5…9)0-9。
我如何使用jQuery做到这一点?
我正在创建一个网页,其中我有一个输入文本字段,我想只允许数字字符,如(0,1,2,3,4,5…9)0-9。
我如何使用jQuery做到这一点?
当前回答
需要确保你有数字键盘和tab键工作
// Allow only backspace and delete
if (event.keyCode == 46 || event.keyCode == 8 || event.keyCode == 9) {
// let it happen, don't do anything
}
else {
// Ensure that it is a number and stop the keypress
if ((event.keyCode >= 48 && event.keyCode <= 57) || (event.keyCode >= 96 && event.keyCode <= 105)) {
}
else {
event.preventDefault();
}
}
其他回答
我根据@user261922上面的帖子写了我的,稍微修改了一下,所以你可以选择所有,标签和可以处理多个“数字”字段在同一个页面上。
var prevKey = -1, prevControl = '';
$(document).ready(function () {
$(".OnlyNumbers").keydown(function (event) {
if (!(event.keyCode == 8 // backspace
|| event.keyCode == 9 // tab
|| event.keyCode == 17 // ctrl
|| event.keyCode == 46 // delete
|| (event.keyCode >= 35 && event.keyCode <= 40) // arrow keys/home/end
|| (event.keyCode >= 48 && event.keyCode <= 57) // numbers on keyboard
|| (event.keyCode >= 96 && event.keyCode <= 105) // number on keypad
|| (event.keyCode == 65 && prevKey == 17 && prevControl == event.currentTarget.id)) // ctrl + a, on same control
) {
event.preventDefault(); // Prevent character input
}
else {
prevKey = event.keyCode;
prevControl = event.currentTarget.id;
}
});
});
下面是一个使用jQuery UI小部件工厂的答案。您可以轻松地自定义允许的字符。
$('input').numberOnly({
valid: "0123456789+-.$,"
});
这将允许数字、数字符号和美元金额。
$.widget('themex.numberOnly', {
options: {
valid : "0123456789",
allow : [46,8,9,27,13,35,39],
ctrl : [65],
alt : [],
extra : []
},
_create: function() {
var self = this;
self.element.keypress(function(event){
if(self._codeInArray(event,self.options.allow) || self._codeInArray(event,self.options.extra))
{
return;
}
if(event.ctrlKey && self._codeInArray(event,self.options.ctrl))
{
return;
}
if(event.altKey && self._codeInArray(event,self.options.alt))
{
return;
}
if(!event.shiftKey && !event.altKey && !event.ctrlKey)
{
if(self.options.valid.indexOf(String.fromCharCode(event.keyCode)) != -1)
{
return;
}
}
event.preventDefault();
});
},
_codeInArray : function(event,codes) {
for(code in codes)
{
if(event.keyCode == codes[code])
{
return true;
}
}
return false;
}
});
重构了已接受的答案,因此不再需要使用注释,因为我讨厌注释。这也更容易用茉莉花进行测试。
allowBackspaceDeleteTabEscapeEnterPress: function(event){
return ($.inArray(event.keyCode, [46, 8, 9, 27, 13, 190]) >= 0);
},
allowContorlAPress: function(event){
return (event.keyCode == 65 && event.ctrlKey === true)
},
allowHomeEndLeftRightPress: function(event){
return (event.keyCode >= 35 && event.keyCode <= 39)
},
theKeyPressedIsEditRelated: function (event) {
return (this.allowBackspaceDeleteTabEscapeEnterPress(event)
|| this.allowContorlAPress(event)
|| this.allowHomeEndLeftRightPress(event));
},
isNotFromTheNumKeyPad: function (event) {
return (event.keyCode < 96 || event.keyCode > 105);
},
isNotFromTopRowNumberKeys: function (event) {
return (event.keyCode < 48 || event.keyCode > 57);
},
theKeyIsNonNumeric: function (event) {
return (event.shiftKey
|| (this.isNotFromTopRowNumberKeys(event)
&& this.isNotFromTheNumKeyPad(event)));
},
bindInputValidator: function(){
$('.myinputclassselector').keydown(function (event) {
if(this.validateKeyPressEvent(event)) return false;
});
},
validateKeyPressEvent: function(event){
if(this.theKeyPressedIsEditRelated(event)){
return;
} else {
if (this.theKeyIsNonNumeric(event)) {
event.preventDefault();
}
}
}
我把所有的答案结合在一起,得出了以下代码:
jQuery('#input_id', function(e){
// Allow: backspace, delete, tab, escape, enter
if (jQuery.inArray(e.keyCode, [46, 8, 9, 27, 13, 110]) !== -1 ||
// Allow: Ctrl+A
(e.keyCode === 65 && e.ctrlKey === true) ||
// Allow: Ctrl+C
(e.keyCode === 67 && e.ctrlKey === true) ||
// Allow: Ctrl+X
(e.keyCode === 88 && e.ctrlKey === true) ||
// Disallow several dots (allow 190 only if no dots found)
(e.keyCode === 190 && jQuery(this).val().indexOf('.') == -1) ||
// Bug in some Android devices where it is always 229
(e.keyCode === 229) ||
// Allow: home, end, left, right
(e.keyCode >= 35 && e.keyCode <= 40)) {
// let it happen, don't do anything
return;
}
// Ensure that it is a number and stop the keypress
if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) && (e.keyCode < 96 || e.keyCode > 105)) {
e.preventDefault();
}
});
此外,表单应该有autocomplete="off"。如果没有这个选项,你可能会在移动设备上遇到自动补全算法的问题。
这是我用来验证整数或浮点值的数字输入(不显眼的jQuery风格):
$('input[name="number"]').keyup(function(e) { var float = parseFloat($(this).attr('data-float')); /* 2 regexp for validating integer and float inputs ***** > integer_regexp : allow numbers, but do not allow leading zeros > float_regexp : allow numbers + only one dot sign (and only in the middle of the string), but do not allow leading zeros in the integer part *************************************************************************/ var integer_regexp = (/[^0-9]|^0+(?!$)/g); var float_regexp = (/[^0-9\.]|^\.+(?!$)|^0+(?=[0-9]+)|\.(?=\.|.+\.)/g); var regexp = (float % 1 === 0) ? integer_regexp : float_regexp; if (regexp.test(this.value)) { this.value = this.value.replace(regexp, ''); } }); <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <input type="text" data-float="1" id="number" name="number" placeholder="integer"> <input type="text" data-float="0.1" id="number" name="number" placeholder="float">