我把所有的答案结合在一起，得出了以下代码:

jQuery('#input_id', function(e){
    // Allow: backspace, delete, tab, escape, enter
    if (jQuery.inArray(e.keyCode, [46, 8, 9, 27, 13, 110]) !== -1 ||
        // Allow: Ctrl+A
        (e.keyCode === 65 && e.ctrlKey === true) ||
        // Allow: Ctrl+C
        (e.keyCode === 67 && e.ctrlKey === true) ||
        // Allow: Ctrl+X
        (e.keyCode === 88 && e.ctrlKey === true) ||
        // Disallow several dots (allow 190 only if no dots found)
        (e.keyCode === 190 && jQuery(this).val().indexOf('.') == -1) ||
        // Bug in some Android devices where it is always 229
        (e.keyCode === 229) ||
        // Allow: home, end, left, right
        (e.keyCode >= 35 && e.keyCode <= 40)) {
        // let it happen, don't do anything
        return;
    }
    // Ensure that it is a number and stop the keypress
    if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) && (e.keyCode < 96 || e.keyCode > 105)) {
        e.preventDefault();
    }
});

此外，表单应该有autocomplete="off"。如果没有这个选项，你可能会在移动设备上遇到自动补全算法的问题。

jQuery("#no_of").keypress(function(event){
    //Allow only backspace and delete
    if (event.keyCode != 46 && event.keyCode != 8) {
        if (!parseInt(String.fromCharCode(event.which))) {
            event.preventDefault();
        }
    }
});

jQuery("#no_of").keyup(function(e){
    var temp_s= jQuery("#no_of").val();
    var multiply_val= temp_s*10;
    jQuery("#ex-r").html(multiply_val);
});

我把所有的答案结合在一起，得出了以下代码:

jQuery('#input_id', function(e){
    // Allow: backspace, delete, tab, escape, enter
    if (jQuery.inArray(e.keyCode, [46, 8, 9, 27, 13, 110]) !== -1 ||
        // Allow: Ctrl+A
        (e.keyCode === 65 && e.ctrlKey === true) ||
        // Allow: Ctrl+C
        (e.keyCode === 67 && e.ctrlKey === true) ||
        // Allow: Ctrl+X
        (e.keyCode === 88 && e.ctrlKey === true) ||
        // Disallow several dots (allow 190 only if no dots found)
        (e.keyCode === 190 && jQuery(this).val().indexOf('.') == -1) ||
        // Bug in some Android devices where it is always 229
        (e.keyCode === 229) ||
        // Allow: home, end, left, right
        (e.keyCode >= 35 && e.keyCode <= 40)) {
        // let it happen, don't do anything
        return;
    }
    // Ensure that it is a number and stop the keypress
    if ((e.shiftKey || (e.keyCode < 48 || e.keyCode > 57)) && (e.keyCode < 96 || e.keyCode > 105)) {
        e.preventDefault();
    }
});

此外，表单应该有autocomplete="off"。如果没有这个选项，你可能会在移动设备上遇到自动补全算法的问题。

我也想回答:)

    $('.justNum').keydown(function(event){
        var kc, num, rt = false;
        kc = event.keyCode;
        if(kc == 8 || ((kc > 47 && kc < 58) || (kc > 95 && kc < 106))) rt = true;
        return rt;
    })
    .bind('blur', function(){
        num = parseInt($(this).val());
        num = isNaN(num) ? '' : num;
        if(num && num < 0) num = num*-1;
        $(this).val(num);
    });

就是这样……只是数字。:)几乎只用“模糊”就可以了，但是……

只需要在Jquery中应用此方法，您可以验证您的文本框只接受数字。

function IsNumberKeyWithoutDecimal(element) {    
var value = $(element).val();
var regExp = "^\\d+$";
return value.match(regExp); 
}

试试这个解决方案

你会想要允许tab:

$("#txtboxToFilter").keydown(function(event) {
    // Allow only backspace and delete
    if ( event.keyCode == 46 || event.keyCode == 8 || event.keyCode == 9 ) {
        // let it happen, don't do anything
    }
    else {
        // Ensure that it is a number and stop the keypress
        if ((event.keyCode < 48 || event.keyCode > 57) && (event.keyCode < 96 || event.keyCode > 105 )) {
            event.preventDefault(); 
        }   
    }
});