一行代码中用户输入值的反向:

for i in input()[::-1]: print(i,end='')

array=[0,10,20,40]
for e in reversed(array):
  print e

另一个解决方案是使用numpy。翻一下

import numpy as np
array = [0, 10, 20, 40]
list(np.flip(array))
[40, 20, 10, 0]

将你的需求转换成Python的最直接的方法是这样的for语句:

for i in xrange(len(array) - 1, -1, -1):
   print i, array[i]

这是相当神秘的，但可能有用。

内置功能最少，假设是面试设置

array = [1, 2, 3, 4, 5, 6,7, 8]
inverse = [] #create container for inverse array
length = len(array)  #to iterate later, returns 8 
counter = length - 1  #because the 8th element is on position 7 (as python starts from 0)

for i in range(length): 
   inverse.append(array[counter])
   counter -= 1
print(inverse)

这个类使用Python魔法方法和迭代器进行反转，并反转列表:

class Reverse(object):
    """ Builds a reverse method using magic methods """

    def __init__(self, data):
        self.data = data
        self.index = len(data)


    def __iter__(self):
        return self

    def __next__(self):
        if self.index == 0:
            raise StopIteration

        self.index = self.index - 1
        return self.data[self.index]


REV_INSTANCE = Reverse([0, 10, 20, 40])

iter(REV_INSTANCE)

rev_list = []
for i in REV_INSTANCE:
    rev_list.append(i)

print(rev_list)  

输出

[40, 20, 10, 0]