棘手的方法:

var s = "dasdnk asd, (naks) :d skldma";
var a = s.replace('(',' ').replace(')',' ').replace(',',' ').split(' ');
console.log(a);//["dasdnk", "asd", "naks", ":d", "skldma"]

对于那些希望在拆分函数中进行更多自定义的人，我编写了一个递归算法，它使用要拆分的字符列表拆分给定的字符串。在我看到上面的帖子之前，我写了这篇文章。我希望它能帮助一些沮丧的程序员。

splitString = function(string, splitters) {
    var list = [string];
    for(var i=0, len=splitters.length; i<len; i++) {
        traverseList(list, splitters[i], 0);
    }
    return flatten(list);
}

traverseList = function(list, splitter, index) {
    if(list[index]) {
        if((list.constructor !== String) && (list[index].constructor === String))
            (list[index] != list[index].split(splitter)) ? list[index] = list[index].split(splitter) : null;
        (list[index].constructor === Array) ? traverseList(list[index], splitter, 0) : null;
        (list.constructor === Array) ? traverseList(list, splitter, index+1) : null;    
    }
}

flatten = function(arr) {
    return arr.reduce(function(acc, val) {
        return acc.concat(val.constructor === Array ? flatten(val) : val);
    },[]);
}

var stringToSplit = "people and_other/things";
var splitList = [" ", "_", "/"];
splitString(stringToSplit, splitList);

上面的例子返回:["people"， "and"， "other"， "things"]

注:flatten函数取自Rosetta Code

从@stephen-sweriduk解决方案开始(这对我来说更有趣!)，我对它进行了轻微的修改，使其更加通用和可重用:

/**
 * Adapted from: http://stackoverflow.com/questions/650022/how-do-i-split-a-string-with-multiple-separators-in-javascript
*/
var StringUtils = {

  /**
   * Flatten a list of strings
   * http://rosettacode.org/wiki/Flatten_a_list
   */
  flatten : function(arr) {
    var self=this;
    return arr.reduce(function(acc, val) {
        return acc.concat(val.constructor === Array ? self.flatten(val) : val);
    },[]);
  },

  /**
   * Recursively Traverse a list and apply a function to each item
   * @param list array
   * @param expression Expression to use in func
   * @param func function of (item,expression) to apply expression to item
   *
   */
  traverseListFunc : function(list, expression, index, func) {
    var self=this;
    if(list[index]) {
        if((list.constructor !== String) && (list[index].constructor === String))
            (list[index] != func(list[index], expression)) ? list[index] = func(list[index], expression) : null;
        (list[index].constructor === Array) ? self.traverseListFunc(list[index], expression, 0, func) : null;
        (list.constructor === Array) ? self.traverseListFunc(list, expression, index+1, func) : null;
    }
  },

  /**
   * Recursively map function to string
   * @param string
   * @param expression Expression to apply to func
   * @param function of (item, expressions[i])
   */
  mapFuncToString : function(string, expressions, func) {
    var self=this;
    var list = [string];
    for(var i=0, len=expressions.length; i<len; i++) {
        self.traverseListFunc(list, expressions[i], 0, func);
    }
    return self.flatten(list);
  },

  /**
   * Split a string
   * @param splitters Array of characters to apply the split
   */
  splitString : function(string, splitters) {
    return this.mapFuncToString(string, splitters, function(item, expression) {
      return item.split(expression);
    })
  },

}

然后

var stringToSplit = "people and_other/things";
var splitList = [" ", "_", "/"];
var splittedString=StringUtils.splitString(stringToSplit, splitList);
console.log(splitList, stringToSplit, splittedString);

归还原物的:

[ ' ', '_', '/' ] 'people and_other/things' [ 'people', 'and', 'other', 'things' ]

下面是在ES6中实现相同的新方法:

SplitByString(source, splitBy) { var splitter = splitBy.split("); splitter.push([源]);//推送初始值 返回分配器。reduceRight(函数(累加器，curValue) { Var k = []; 蓄电池。v => k =[…k…v.split (curValue)]); 返回k; })； ｝ Var source = "abc,def#hijk*lmn,opq#rst*uvw,xyz"; var splitBy = "，*#"; splitBy console.log (SplitByString(源));

在这个函数中请注意:

不涉及正则表达式 以源代码中显示的相同顺序返回拆分后的值

以上代码的结果为:

例如，如果你在String 07:05:45PM中使用了split and replace

var hour = time.replace("PM", "").split(":");

结果

[ '07', '05', '45' ]

一个简单的方法是用每个分隔符处理字符串中的每个字符，并构建一个分隔符数组:

splix = function ()
{
  u = [].slice.call(arguments); v = u.slice(1); u = u[0]; w = [u]; x = 0;

  for (i = 0; i < u.length; ++i)
  {
    for (j = 0; j < v.length; ++j)
    {
      if (u.slice(i, i + v[j].length) == v[j])
      {
        y = w[x].split(v[j]); w[x] = y[0]; w[++x] = y[1];
      };
    };
  };
  
  return w;
};

console.logg = function () { document.body.innerHTML += "<br>" + [].slice.call(arguments).join(); } splix = function() { u = [].slice.call(arguments); v = u.slice(1); u = u[0]; w = [u]; x = 0; console.logg("Processing: <code>" + JSON.stringify(w) + "</code>"); for (i = 0; i < u.length; ++i) { for (j = 0; j < v.length; ++j) { console.logg("Processing: <code>[\x22" + u.slice(i, i + v[j].length) + "\x22, \x22" + v[j] + "\x22]</code>"); if (u.slice(i, i + v[j].length) == v[j]) { y = w[x].split(v[j]); w[x] = y[0]; w[++x] = y[1]; console.logg("Currently processed: " + JSON.stringify(w) + "\n"); }; }; }; console.logg("Return: <code>" + JSON.stringify(w) + "</code>"); }; setTimeout(function() { console.clear(); splix("1.23--4", ".", "--"); }, 250); @import url("http://fonts.googleapis.com/css?family=Roboto"); body {font: 20px Roboto;}

用法:splix(字符串，分隔符…) 示例:splix("1.23- 4"， "."， "——") 返回:["1"，"23"，"4"]