我如何分裂一个字符串与多个分隔符在JavaScript?
我试图拆分逗号和空格,但AFAIK JavaScript的split()函数只支持一个分隔符。
我如何分裂一个字符串与多个分隔符在JavaScript?
我试图拆分逗号和空格,但AFAIK JavaScript的split()函数只支持一个分隔符。
当前回答
让我们保持简单:(在你的RegEx中添加“[]+”表示“1或更多”)
这意味着“+”和“{1,}”是相同的。
var words = text.split(/[ .:;?!~,`"&|()<>{}\[\]\r\n/\\]+/); // note ' and - are kept
其他回答
一个简单的方法是用每个分隔符处理字符串中的每个字符,并构建一个分隔符数组:
splix = function ()
{
u = [].slice.call(arguments); v = u.slice(1); u = u[0]; w = [u]; x = 0;
for (i = 0; i < u.length; ++i)
{
for (j = 0; j < v.length; ++j)
{
if (u.slice(i, i + v[j].length) == v[j])
{
y = w[x].split(v[j]); w[x] = y[0]; w[++x] = y[1];
};
};
};
return w;
};
console.logg = function () { document.body.innerHTML += "<br>" + [].slice.call(arguments).join(); } splix = function() { u = [].slice.call(arguments); v = u.slice(1); u = u[0]; w = [u]; x = 0; console.logg("Processing: <code>" + JSON.stringify(w) + "</code>"); for (i = 0; i < u.length; ++i) { for (j = 0; j < v.length; ++j) { console.logg("Processing: <code>[\x22" + u.slice(i, i + v[j].length) + "\x22, \x22" + v[j] + "\x22]</code>"); if (u.slice(i, i + v[j].length) == v[j]) { y = w[x].split(v[j]); w[x] = y[0]; w[++x] = y[1]; console.logg("Currently processed: " + JSON.stringify(w) + "\n"); }; }; }; console.logg("Return: <code>" + JSON.stringify(w) + "</code>"); }; setTimeout(function() { console.clear(); splix("1.23--4", ".", "--"); }, 250); @import url("http://fonts.googleapis.com/css?family=Roboto"); body {font: 20px Roboto;}
用法:splix(字符串,分隔符…) 示例:splix("1.23- 4", ".", "——") 返回:["1","23","4"]
我认为如果你指定你想要保留什么,而不是你想要删除什么,会更容易。
如果你只想要英语单词,你可以这样用:
text.match(/[a-z'\-]+/gi);
示例(运行片段):
var R=[/[a-z'\-]+/gi,/[a-z'\-\s]+/gi]; var s=document.getElementById('s'); for(var i=0;i<R.length;i++) { var o=document.createElement('option'); o.innerText=R[i]+''; o.value=i; s.appendChild(o); } var t=document.getElementById('t'); var r=document.getElementById('r'); s.onchange=function() { r.innerHTML=''; var x=s.value; if((x>=0)&&(x<R.length)) x=t.value.match(R[x]); for(i=0;i<x.length;i++) { var li=document.createElement('li'); li.innerText=x[i]; r.appendChild(li); } } <textarea id="t" style="width:70%;height:12em">even, test; spider-man But saying o'er what I have said before: My child is yet a stranger in the world; She hath not seen the change of fourteen years, Let two more summers wither in their pride, Ere we may think her ripe to be a bride. —Shakespeare, William. The Tragedy of Romeo and Juliet</textarea> <p><select id="s"> <option selected>Select a regular expression</option> <!-- option value="1">/[a-z'\-]+/gi</option> <option value="2">/[a-z'\-\s]+/gi</option --> </select></p> <ol id="r" style="display:block;width:auto;border:1px inner;overflow:scroll;height:8em;max-height:10em;"></ol> </div>
您可以将所有想要单独或共同用作分隔符的字符合并到一个正则表达式中,并将它们传递给split函数。例如,你可以这样写:
console.log( "dasdnk asd, (naks) :d skldma".split(/[ \(,\)]+/) );
输出将是:
["dasdnk", "asd", "naks", ":d", "skldma"]
我将为这样的函数提供一个经典的实现。代码可以在几乎所有版本的JavaScript中运行,并且在某种程度上是最优的。
它不使用正则表达式,这很难维护 它没有使用JavaScript的新特性 它不使用需要更多计算机内存的多次.split() .join()调用
只是纯代码:
var text = "Create a function, that will return an array (of string), with the words inside the text";
println(getWords(text));
function getWords(text)
{
let startWord = -1;
let ar = [];
for(let i = 0; i <= text.length; i++)
{
let c = i < text.length ? text[i] : " ";
if (!isSeparator(c) && startWord < 0)
{
startWord = i;
}
if (isSeparator(c) && startWord >= 0)
{
let word = text.substring(startWord, i);
ar.push(word);
startWord = -1;
}
}
return ar;
}
function isSeparator(c)
{
var separators = [" ", "\t", "\n", "\r", ",", ";", ".", "!", "?", "(", ")"];
return separators.includes(c);
}
你可以看到代码在playground中运行: https://codeguppy.com/code.html?IJI0E4OGnkyTZnoszAzf
从@stephen-sweriduk解决方案开始(这对我来说更有趣!),我对它进行了轻微的修改,使其更加通用和可重用:
/**
* Adapted from: http://stackoverflow.com/questions/650022/how-do-i-split-a-string-with-multiple-separators-in-javascript
*/
var StringUtils = {
/**
* Flatten a list of strings
* http://rosettacode.org/wiki/Flatten_a_list
*/
flatten : function(arr) {
var self=this;
return arr.reduce(function(acc, val) {
return acc.concat(val.constructor === Array ? self.flatten(val) : val);
},[]);
},
/**
* Recursively Traverse a list and apply a function to each item
* @param list array
* @param expression Expression to use in func
* @param func function of (item,expression) to apply expression to item
*
*/
traverseListFunc : function(list, expression, index, func) {
var self=this;
if(list[index]) {
if((list.constructor !== String) && (list[index].constructor === String))
(list[index] != func(list[index], expression)) ? list[index] = func(list[index], expression) : null;
(list[index].constructor === Array) ? self.traverseListFunc(list[index], expression, 0, func) : null;
(list.constructor === Array) ? self.traverseListFunc(list, expression, index+1, func) : null;
}
},
/**
* Recursively map function to string
* @param string
* @param expression Expression to apply to func
* @param function of (item, expressions[i])
*/
mapFuncToString : function(string, expressions, func) {
var self=this;
var list = [string];
for(var i=0, len=expressions.length; i<len; i++) {
self.traverseListFunc(list, expressions[i], 0, func);
}
return self.flatten(list);
},
/**
* Split a string
* @param splitters Array of characters to apply the split
*/
splitString : function(string, splitters) {
return this.mapFuncToString(string, splitters, function(item, expression) {
return item.split(expression);
})
},
}
然后
var stringToSplit = "people and_other/things";
var splitList = [" ", "_", "/"];
var splittedString=StringUtils.splitString(stringToSplit, splitList);
console.log(splitList, stringToSplit, splittedString);
归还原物的:
[ ' ', '_', '/' ] 'people and_other/things' [ 'people', 'and', 'other', 'things' ]