我使用regexp:

str =  'Write a program that extracts from a given text all palindromes, e.g. "ABBA", "lamal", "exe".';

var strNew = str.match(/\w+/g);

// Output: ["Write", "a", "program", "that", "extracts", "from", "a", "given", "text", "all", "palindromes", "e", "g", "ABBA", "lamal", "exe"]

a = "a=b,c:d"

array = ['=',',',':'];

for(i=0; i< array.length; i++){ a= a.split(array[i]).join(); }

这将返回没有特殊字符的字符串。

棘手的方法:

var s = "dasdnk asd, (naks) :d skldma";
var a = s.replace('(',' ').replace(')',' ').replace(',',' ').split(' ');
console.log(a);//["dasdnk", "asd", "naks", ":d", "skldma"]

在Github上查看我的简单库

如果你真的不想访问或与repo交互，下面是工作代码:

/**
 * 
 * @param {type} input The string input to be split
 * @param {type} includeTokensInOutput If true, the tokens are retained in the splitted output.
 * @param {type} tokens The tokens to be employed in splitting the original string.
 * @returns {Scanner}
 */
function Scanner(input, includeTokensInOutput, tokens) {
    this.input = input;
    this.includeTokensInOutput = includeTokensInOutput;
    this.tokens = tokens;
}

Scanner.prototype.scan = function () {
    var inp = this.input;

    var parse = [];
    this.tokens.sort(function (a, b) {
        return b.length - a.length; //ASC, For Descending order use: b - a
    });
    for (var i = 0; i < inp.length; i++) {


        for (var j = 0; j < this.tokens.length; j++) {

            var token = this.tokens[j];
            var len = token.length;
            if (len > 0 && i + len <= inp.length) {
                var portion = inp.substring(i, i + len);
                if (portion === token) {
                    if (i !== 0) {//avoid empty spaces
                        parse[parse.length] = inp.substring(0, i);
                    }
                    if (this.includeTokensInOutput) {
                        parse[parse.length] = token;
                    }
                    inp = inp.substring(i + len);
                    i = -1;
                    break;
                }

            }

        }

    }
    if (inp.length > 0) {
          parse[parse.length] = inp;
    }

    return parse;


};

用法很简单:

    var tokens = new Scanner("ABC+DE-GHIJK+LMNOP", false , new Array('+','-')).scan();

console.log(tokens); 

给:

['ABC', 'DE', 'GHIJK', 'LMNOP']

如果您希望在输出中包含分隔令牌(+和-)，将false设置为true，瞧!它仍然有效。

现在的用法是:

var tokens = new Scanner("ABC+DE-GHIJK+LMNOP", true , new Array('+','-')).scan();

and

console.log(tokens);

将:

['ABC', '+', 'DE', '-', 'GHIJK', '+', 'LMNOP']

享受吧!

我不知道RegEx的性能如何，但这里有另一个RegEx的替代方案，它利用了本机HashSet，并在O(max(str)中工作。长度，delimeter.length))

var multiSplit = function(str,delimiter){
    if (!(delimiter instanceof Array))
        return str.split(delimiter);
    if (!delimiter || delimiter.length == 0)
        return [str];
    var hashSet = new Set(delimiter);
    if (hashSet.has(""))
        return str.split("");
    var lastIndex = 0;
    var result = [];
    for(var i = 0;i<str.length;i++){
        if (hashSet.has(str[i])){
            result.push(str.substring(lastIndex,i));
            lastIndex = i+1;
        }
    }
    result.push(str.substring(lastIndex));
    return result;
}

multiSplit('1,2,3.4.5.6 7 8 9',[',','.',' ']);
// Output: ["1", "2", "3", "4", "5", "6", "7", "8", "9"]

multiSplit('1,2,3.4.5.6 7 8 9',' ');
// Output: ["1,2,3.4.5.6", "7", "8", "9"]

让我们保持简单:(在你的RegEx中添加“[]+”表示“1或更多”)

这意味着“+”和“{1，}”是相同的。

var words = text.split(/[ .:;?!~,`"&|()<>{}\[\]\r\n/\\]+/); // note ' and - are kept