一个有堆栈且没有递归方法的解决方案:

File dir = new File("/path/to/dir");
File[] currList;
Stack<File> stack = new Stack<File>();
stack.push(dir);
while (! stack.isEmpty()) {
    if (stack.lastElement().isDirectory()) {
        currList = stack.lastElement().listFiles();
        if (currList.length > 0) {
            for (File curr: currList) {
                stack.push(curr);
            }
        } else {
            stack.pop().delete();
        }
    } else {
        stack.pop().delete();
    }
}

在遗留项目中，我需要创建本地Java代码。我创建了类似于Paulitex代码的代码。看到:

public class FileHelper {

   public static boolean delete(File fileOrFolder) {
      boolean result = true;
      if(fileOrFolder.isDirectory()) {
         for (File file : fileOrFolder.listFiles()) {
            result = result && delete(file);
         }
      }
      result = result && fileOrFolder.delete();
      return result;
   } 
}

单元测试:

public class FileHelperTest {

    @Before
    public void setup() throws IOException {
       new File("FOLDER_TO_DELETE/SUBFOLDER").mkdirs();
       new File("FOLDER_TO_DELETE/SUBFOLDER_TWO").mkdirs();
       new File("FOLDER_TO_DELETE/SUBFOLDER_TWO/TEST_FILE.txt").createNewFile();
    }

    @Test
    public void deleteFolderWithFiles() {
       File folderToDelete = new File("FOLDER_TO_DELETE");
       Assert.assertTrue(FileHelper.delete(folderToDelete));
       Assert.assertFalse(new File("FOLDER_TO_DELETE").exists());
    }

}

for(Path p : Files.walk(directoryToDelete).
        sorted((a, b) -> b.compareTo(a)). // reverse; files before dirs
        toArray(Path[]::new))
{
    Files.delete(p);
}

或者如果你想处理IOException:

Files.walk(directoryToDelete).
    sorted((a, b) -> b.compareTo(a)). // reverse; files before dirs
    forEach(p -> {
        try { Files.delete(p); }
        catch(IOException e) { /* ... */ }
      });

在Java 7中，我们终于可以通过可靠的符号链接检测来做到这一点。(我不认为Apache的commons-io现在有可靠的符号链接检测，因为它不处理Windows上用mklink创建的链接。)

出于历史原因，这里有一个java 7之前的答案，它遵循符号链接。

void delete(File f) throws IOException {
  if (f.isDirectory()) {
    for (File c : f.listFiles())
      delete(c);
  }
  if (!f.delete())
    throw new FileNotFoundException("Failed to delete file: " + f);
}

刚刚看到我的解决方案或多或少与埃里克森的相同，只是包装成一个静态方法。把它放到某个地方，它的重量比安装所有Apache Commons要轻得多，因为(如您所见)非常简单。

public class FileUtils {
    /**
     * By default File#delete fails for non-empty directories, it works like "rm". 
     * We need something a little more brutual - this does the equivalent of "rm -r"
     * @param path Root File Path
     * @return true iff the file and all sub files/directories have been removed
     * @throws FileNotFoundException
     */
    public static boolean deleteRecursive(File path) throws FileNotFoundException{
        if (!path.exists()) throw new FileNotFoundException(path.getAbsolutePath());
        boolean ret = true;
        if (path.isDirectory()){
            for (File f : path.listFiles()){
                ret = ret && deleteRecursive(f);
            }
        }
        return ret && path.delete();
    }
}

你可以用:

org . apache commons。我deleteQuietly (destFile FileUtils);

删除文件，从不抛出异常。如果file是目录，请删除该目录及其所有子目录。 File.delete()和这个方法的区别是: 待删除的目录不需要为空目录。 当无法删除文件或目录时，不会抛出异常。