处理异常的最佳解决方案是，方法抛出的异常应该总是描述该方法试图(和失败)做什么:

private void deleteRecursive(File f) throws Exception {
    try {
        if (f.isDirectory()) {
            for (File c : f.listFiles()) {
                deleteRecursive(c);
            }
        }
        if (!f.delete()) {
            throw new Exception("Delete command returned false for file: " + f);
        }
    } 
    catch (Exception e) {
        throw new Exception("Failed to delete the folder: " + f, e);
    }
}

Guava提供了一行代码:morefiles . deleterecursive()。

与许多共享的示例不同，它只考虑符号链接，并且不会(默认情况下)删除所提供路径之外的文件。

番石榴21.0及以上版本

有一个void deleterecursive (Path Path, RecursiveDeleteOption…)options)会抛出从Guava 21.0开始可用的MoreFiles类的IOException静态方法。

请参阅Javadoc文档:

public static void deleteRecursively(Path path, RecursiveDeleteOption... options) throws IOException Deletes the file or directory at the given path recursively. Deletes symbolic links, not their targets (subject to the caveat below). If an I/O exception occurs attempting to read, open or delete any file under the given directory, this method skips that file and continues. All such exceptions are collected and, after attempting to delete all files, an IOException is thrown containing those exceptions as suppressed exceptions.

在遗留项目中，我需要创建本地Java代码。我创建了类似于Paulitex代码的代码。看到:

public class FileHelper {

   public static boolean delete(File fileOrFolder) {
      boolean result = true;
      if(fileOrFolder.isDirectory()) {
         for (File file : fileOrFolder.listFiles()) {
            result = result && delete(file);
         }
      }
      result = result && fileOrFolder.delete();
      return result;
   } 
}

单元测试:

public class FileHelperTest {

    @Before
    public void setup() throws IOException {
       new File("FOLDER_TO_DELETE/SUBFOLDER").mkdirs();
       new File("FOLDER_TO_DELETE/SUBFOLDER_TWO").mkdirs();
       new File("FOLDER_TO_DELETE/SUBFOLDER_TWO/TEST_FILE.txt").createNewFile();
    }

    @Test
    public void deleteFolderWithFiles() {
       File folderToDelete = new File("FOLDER_TO_DELETE");
       Assert.assertTrue(FileHelper.delete(folderToDelete));
       Assert.assertFalse(new File("FOLDER_TO_DELETE").exists());
    }

}

在Java 7中，我们终于可以通过可靠的符号链接检测来做到这一点。(我不认为Apache的commons-io现在有可靠的符号链接检测，因为它不处理Windows上用mklink创建的链接。)

出于历史原因，这里有一个java 7之前的答案，它遵循符号链接。

void delete(File f) throws IOException {
  if (f.isDirectory()) {
    for (File c : f.listFiles())
      delete(c);
  }
  if (!f.delete())
    throw new FileNotFoundException("Failed to delete file: " + f);
}

一个有堆栈且没有递归方法的解决方案:

File dir = new File("/path/to/dir");
File[] currList;
Stack<File> stack = new Stack<File>();
stack.push(dir);
while (! stack.isEmpty()) {
    if (stack.lastElement().isDirectory()) {
        currList = stack.lastElement().listFiles();
        if (currList.length > 0) {
            for (File curr: currList) {
                stack.push(curr);
            }
        } else {
            stack.pop().delete();
        }
    } else {
        stack.pop().delete();
    }
}