下面是我以前如何将一个浮点数截断到小数点后两位
NSLog(@" %.02f %.02f %.02f", r, g, b);
我查了文档和电子书,但还没找到答案。谢谢!
下面是我以前如何将一个浮点数截断到小数点后两位
NSLog(@" %.02f %.02f %.02f", r, g, b);
我查了文档和电子书,但还没找到答案。谢谢!
当前回答
iOS 15+版本推荐:
2.31234.formatted(.number.precision(.fractionLength(1)))
其他回答
为什么要把它弄得这么复杂?你可以用这个代替:
import UIKit
let PI = 3.14159265359
round( PI ) // 3.0 rounded to the nearest decimal
round( PI * 100 ) / 100 //3.14 rounded to the nearest hundredth
round( PI * 1000 ) / 1000 // 3.142 rounded to the nearest thousandth
看它在游乐场工作。
PS:解决方案来自:http://rrike.sh/xcode/rounding-various-decimal-places-swift/
细节
Xcode 9.3, Swift 4.1 Xcode 10.2.1 (10E1001)
解决方案1
func round () -> Double
(5.2).rounded()
// 5.0
(5.5).rounded()
// 6.0
(-5.2).rounded()
// -5.0
(-5.5).rounded()
// -6.0
func圆润(_ rule: FloatingPointRoundingRule) -> Double
let x = 6.5
// Equivalent to the C 'round' function:
print(x.rounded(.toNearestOrAwayFromZero))
// Prints "7.0"
// Equivalent to the C 'trunc' function:
print(x.rounded(.towardZero))
// Prints "6.0"
// Equivalent to the C 'ceil' function:
print(x.rounded(.up))
// Prints "7.0"
// Equivalent to the C 'floor' function:
print(x.rounded(.down))
// Prints "6.0"
func round()
var x = 5.2
x.round()
// x == 5.0
var y = 5.5
y.round()
// y == 6.0
var z = -5.5
z.round()
// z == -6.0
func round(_ rule: FloatingPointRoundingRule)
// Equivalent to the C 'round' function:
var w = 6.5
w.round(.toNearestOrAwayFromZero)
// w == 7.0
// Equivalent to the C 'trunc' function:
var x = 6.5
x.round(.towardZero)
// x == 6.0
// Equivalent to the C 'ceil' function:
var y = 6.5
y.round(.up)
// y == 7.0
// Equivalent to the C 'floor' function:
var z = 6.5
z.round(.down)
// z == 6.0
解决方案2
extension Numeric {
private func _precision(number: NSNumber, formatter: NumberFormatter) -> Self? {
if let formatedNumString = formatter.string(from: number),
let formatedNum = formatter.number(from: formatedNumString) {
return formatedNum as? Self
}
return nil
}
private func toNSNumber() -> NSNumber? {
if let num = self as? NSNumber { return num }
guard let string = self as? String, let double = Double(string) else { return nil }
return NSNumber(value: double)
}
func precision(_ minimumFractionDigits: Int,
roundingMode: NumberFormatter.RoundingMode = NumberFormatter.RoundingMode.halfUp) -> Self? {
guard let number = toNSNumber() else { return nil }
let formatter = NumberFormatter()
formatter.minimumFractionDigits = minimumFractionDigits
formatter.roundingMode = roundingMode
return _precision(number: number, formatter: formatter)
}
func precision(with numberFormatter: NumberFormatter) -> String? {
guard let number = toNSNumber() else { return nil }
return numberFormatter.string(from: number)
}
}
使用
_ = 123.44.precision(2)
_ = 123.44.precision(3, roundingMode: .up)
let numberFormatter = NumberFormatter()
numberFormatter.minimumFractionDigits = 1
numberFormatter.groupingSeparator = " "
let num = 222.3333
_ = num.precision(2)
完整的样品
func option1<T: Numeric>(value: T, numerFormatter: NumberFormatter? = nil) {
print("Type: \(type(of: value))")
print("Original Value: \(value)")
let value1 = value.precision(2)
print("value1 = \(value1 != nil ? "\(value1!)" : "nil")")
let value2 = value.precision(5)
print("value2 = \(value2 != nil ? "\(value2!)" : "nil")")
if let value1 = value1, let value2 = value2 {
print("value1 + value2 = \(value1 + value2)")
}
print("")
}
func option2<T: Numeric>(value: T, numberFormatter: NumberFormatter) {
print("Type: \(type(of: value))")
print("Original Value: \(value)")
let value1 = value.precision(with: numberFormatter)
print("formated value = \(value1 != nil ? "\(value1!)" : "nil")\n")
}
func test(with double: Double) {
print("===========================\nTest with: \(double)\n")
let float = Float(double)
let float32 = Float32(double)
let float64 = Float64(double)
let float80 = Float80(double)
let cgfloat = CGFloat(double)
// Exapmle 1
print("-- Option1\n")
option1(value: double)
option1(value: float)
option1(value: float32)
option1(value: float64)
option1(value: float80)
option1(value: cgfloat)
// Exapmle 2
let numberFormatter = NumberFormatter()
numberFormatter.formatterBehavior = .behavior10_4
numberFormatter.minimumIntegerDigits = 1
numberFormatter.minimumFractionDigits = 4
numberFormatter.maximumFractionDigits = 9
numberFormatter.usesGroupingSeparator = true
numberFormatter.groupingSeparator = " "
numberFormatter.groupingSize = 3
print("-- Option 2\n")
option2(value: double, numberFormatter: numberFormatter)
option2(value: float, numberFormatter: numberFormatter)
option2(value: float32, numberFormatter: numberFormatter)
option2(value: float64, numberFormatter: numberFormatter)
option2(value: float80, numberFormatter: numberFormatter)
option2(value: cgfloat, numberFormatter: numberFormatter)
}
test(with: 123.22)
test(with: 1234567890987654321.0987654321)
输出
===========================
Test with: 123.22
-- Option1
Type: Double
Original Value: 123.22
value1 = 123.22
value2 = 123.22
value1 + value2 = 246.44
Type: Float
Original Value: 123.22
value1 = nil
value2 = nil
Type: Float
Original Value: 123.22
value1 = nil
value2 = nil
Type: Double
Original Value: 123.22
value1 = 123.22
value2 = 123.22
value1 + value2 = 246.44
Type: Float80
Original Value: 123.21999999999999886
value1 = nil
value2 = nil
Type: CGFloat
Original Value: 123.22
value1 = 123.22
value2 = 123.22
value1 + value2 = 246.44
-- Option 2
Type: Double
Original Value: 123.22
formatted value = 123.2200
Type: Float
Original Value: 123.22
formatted value = 123.220001221
Type: Float
Original Value: 123.22
formatted value = 123.220001221
Type: Double
Original Value: 123.22
formatted value = 123.2200
Type: Float80
Original Value: 123.21999999999999886
formatted value = nil
Type: CGFloat
Original Value: 123.22
formatted value = 123.2200
===========================
Test with: 1.2345678909876544e+18
-- Option1
Type: Double
Original Value: 1.2345678909876544e+18
value1 = 1.23456789098765e+18
value2 = 1.23456789098765e+18
value1 + value2 = 2.4691357819753e+18
Type: Float
Original Value: 1.234568e+18
value1 = nil
value2 = nil
Type: Float
Original Value: 1.234568e+18
value1 = nil
value2 = nil
Type: Double
Original Value: 1.2345678909876544e+18
value1 = 1.23456789098765e+18
value2 = 1.23456789098765e+18
value1 + value2 = 2.4691357819753e+18
Type: Float80
Original Value: 1234567890987654400.0
value1 = nil
value2 = nil
Type: CGFloat
Original Value: 1.2345678909876544e+18
value1 = 1.23456789098765e+18
value2 = 1.23456789098765e+18
value1 + value2 = 2.4691357819753e+18
-- Option 2
Type: Double
Original Value: 1.2345678909876544e+18
formatted value = 1 234 567 890 987 650 000.0000
Type: Float
Original Value: 1.234568e+18
formatted value = 1 234 567 939 550 610 000.0000
Type: Float
Original Value: 1.234568e+18
formatted value = 1 234 567 939 550 610 000.0000
Type: Double
Original Value: 1.2345678909876544e+18
formatted value = 1 234 567 890 987 650 000.0000
Type: Float80
Original Value: 1234567890987654400.0
formatted value = nil
Type: CGFloat
Original Value: 1.2345678909876544e+18
formatted value = 1 234 567 890 987 650 000.0000
@Christian Dietrich):
而不是:
var k = 1.0
for i in 1...right+1 {
k = 10.0 * k
}
let n = Double(Int(left*k)) / Double(k)
return "\(n)"
也可以是:
let k = pow(10.0, Double(right))
let n = Double(Int(left*k)) / k
return "\(n)"
(更正:) 抱歉混淆* -当然这适用于双打。我认为,最实用的(如果你想让数字四舍五入,而不是被切断)应该是这样的:
infix operator ~> {}
func ~> (left: Double, right: Int) -> Double {
if right <= 0 {
return round(left)
}
let k = pow(10.0, Double(right))
return round(left*k) / k
}
仅对于Float,只需将Double替换为Float, pow替换为powf, round替换为roundf。 更新:我发现它是最实用的使用返回类型Double而不是字符串。它的工作原理与字符串输出相同,即:
println("Pi is roughly \(3.1415926 ~> 3)")
印花:圆周率大约是3.142 所以你可以用同样的方式使用它的字符串(你甚至可以写:println(d ~> 2)),但另外你也可以用它直接舍入值,即:
d = Double(slider.value) ~> 2
或者任何你需要的…
使用以下方法
let output = String.localizedStringWithFormat(" %.02f %.02f %.02f", r, g, b)
println(output)
以下代码:
import Foundation // required for String(format: _, _)
print(String(format: "a float number: %.2f", 1.0321))
将输出:
a float number: 1.03