也许不太专业，但更简单的解决方案可以在消费者方法中创建一个DateTime参数。例如，不使用像SampleMethod这样的make方法，而是使用带参数的make SampleMethod1。SampleMethod1的测试更简单

public void SampleMethod()
    {
        DateTime anotherDateTime = DateTime.Today.AddDays(-10);
        if ((DateTime.Now-anotherDateTime).TotalDays>10)
        {

        }
    }
    public void SampleMethod1(DateTime dateTimeNow)
    {
        DateTime anotherDateTime = DateTime.Today.AddDays(-10);
        if ((dateTimeNow - anotherDateTime).TotalDays > 10)
        {

        }

    }

以下是我对这个问题的回答。我将“环境上下文”模式与IDisposable结合起来。你可以使用DateTimeProvider。当前在您的正常程序代码和测试中，您使用using语句覆盖范围。

using System;
using System.Collections.Immutable;


namespace ambientcontext {

public abstract class DateTimeProvider : IDisposable
{
    private static ImmutableStack<DateTimeProvider> stack = ImmutableStack<DateTimeProvider>.Empty.Push(new DefaultDateTimeProvider());

    protected DateTimeProvider()
    {
        if (this.GetType() != typeof(DefaultDateTimeProvider))
            stack = stack.Push(this);
    }

    public static DateTimeProvider Current => stack.Peek();
    public abstract DateTime Today { get; }
    public abstract DateTime Now {get; }

    public void Dispose()
    {
        if (this.GetType() != typeof(DefaultDateTimeProvider))
            stack = stack.Pop();
    }

    // Not visible Default Implementation 
    private class DefaultDateTimeProvider : DateTimeProvider {
        public override DateTime Today => DateTime.Today; 
        public override DateTime Now => DateTime.Now; 
    }
}
}

下面是如何在单元测试中使用上述DateTimeProvider

using System;
using Xunit;

namespace ambientcontext
{
    public class TestDateTimeProvider
    {
        [Fact]
        public void TestDateTime()
        {
            var actual = DateTimeProvider.Current.Today;
            var expected = DateTime.Today;

            Assert.Equal<DateTime>(expected, actual);

            using (new MyDateTimeProvider(new DateTime(2012,12,21)))
            {
                Assert.Equal(2012, DateTimeProvider.Current.Today.Year);

                using (new MyDateTimeProvider(new DateTime(1984,4,4)))
                {
                    Assert.Equal(1984, DateTimeProvider.Current.Today.Year);    
                }

                Assert.Equal(2012, DateTimeProvider.Current.Today.Year);
            }

            // Fall-Back to Default DateTimeProvider 
            Assert.Equal<int>(expected.Year,  DateTimeProvider.Current.Today.Year);
        }

        private class MyDateTimeProvider : DateTimeProvider 
        {
            private readonly DateTime dateTime; 

            public MyDateTimeProvider(DateTime dateTime):base()
            {
                this.dateTime = dateTime; 
            }

            public override DateTime Today => this.dateTime.Date;

            public override DateTime Now => this.dateTime;
        }
    }
}

这些都是很好的答案，这是我在另一个项目中所做的:

用法:

获取今天的真实日期时间

var today = SystemTime.Now().Date;

而不是使用DateTime。现在，你需要使用SystemTime.Now()…这并不难改变，但这种解决方案可能并不适合所有项目。

时间旅行(让我们去5年后)

SystemTime.SetDateTime(today.AddYears(5));

获得我们虚假的“今天”(从“今天”开始算起5年)

var fakeToday = SystemTime.Now().Date;

重置日期

SystemTime.ResetDateTime();

/// <summary>
/// Used for getting DateTime.Now(), time is changeable for unit testing
/// </summary>
public static class SystemTime
{
    /// <summary> Normally this is a pass-through to DateTime.Now, but it can be overridden with SetDateTime( .. ) for testing or debugging.
    /// </summary>
    public static Func<DateTime> Now = () => DateTime.Now;

    /// <summary> Set time to return when SystemTime.Now() is called.
    /// </summary>
    public static void SetDateTime(DateTime dateTimeNow)
    {
        Now = () =>  dateTimeNow;
    }

    /// <summary> Resets SystemTime.Now() to return DateTime.Now.
    /// </summary>
    public static void ResetDateTime()
    {
        Now = () => DateTime.Now;
    }
}

也许不太专业，但更简单的解决方案可以在消费者方法中创建一个DateTime参数。例如，不使用像SampleMethod这样的make方法，而是使用带参数的make SampleMethod1。SampleMethod1的测试更简单

public void SampleMethod()
    {
        DateTime anotherDateTime = DateTime.Today.AddDays(-10);
        if ((DateTime.Now-anotherDateTime).TotalDays>10)
        {

        }
    }
    public void SampleMethod1(DateTime dateTimeNow)
    {
        DateTime anotherDateTime = DateTime.Today.AddDays(-10);
        if ((dateTimeNow - anotherDateTime).TotalDays > 10)
        {

        }

    }

关于模拟DateTime有一个特别的注意事项。现在使用TypeMock…

DateTime的值。现在必须放置到一个变量中，以便正确地模拟。例如:

这行不通:

if ((DateTime.Now - message.TimeOpened.Value) > new TimeSpan(1, 0, 0))

然而，这样做:

var currentDateTime = DateTime.Now;
if ((currentDateTime - message.TimeOpened.Value) > new TimeSpan(1, 0, 0))

好的做法是，当DateTimeProvider实现IDisposable时。

public class DateTimeProvider : IDisposable 
{ 
    [ThreadStatic] 
    private static DateTime? _injectedDateTime; 

    private DateTimeProvider() 
    { 
    } 

    /// <summary> 
    /// Gets DateTime now. 
    /// </summary> 
    /// <value> 
    /// The DateTime now. 
    /// </value> 
    public static DateTime Now 
    { 
        get 
        { 
            return _injectedDateTime ?? DateTime.Now; 
        } 
    } 

    /// <summary> 
    /// Injects the actual date time. 
    /// </summary> 
    /// <param name="actualDateTime">The actual date time.</param> 
    public static IDisposable InjectActualDateTime(DateTime actualDateTime) 
    { 
        _injectedDateTime = actualDateTime; 

        return new DateTimeProvider(); 
    } 

    public void Dispose() 
    { 
        _injectedDateTime = null; 
    } 
} 

接下来，您可以为单元测试注入假DateTime

    using (var date = DateTimeProvider.InjectActualDateTime(expectedDateTime)) 
    { 
        var bankAccount = new BankAccount(); 

        bankAccount.DepositMoney(600); 

        var lastTransaction = bankAccount.Transactions.Last(); 

        Assert.IsTrue(expectedDateTime.Equals(bankAccount.Transactions[0].TransactionDate)); 
    } 

参见示例DateTimeProvider示例