我如何转换,NSDate到NSString,以便只有年在@“yyyy”格式输出到字符串?


当前回答

  NSDateFormatter *dateformate=[[NSDateFormatter alloc]init];
  [dateformate setDateFormat:@"yyyy"]; // Date formater
  NSString *date = [dateformate stringFromDate:[NSDate date]]; // Convert date to string
  NSLog(@"date :%@",date);

其他回答

#ios #swift #convertDateinString

简单地像这样按你传递的格式“将日期转换为字符串”:

let formatter = DateFormatter()

formatter.dateFormat = "dd-MM-YYYY" // pass formate here
        
let myString = formatter.string(from: date) // this will convert Date in String

注意:你可以指定不同的格式,如"yyyy-MM-dd", "yyyy", "MM"等。

如果你没有NSDate -descriptionWithCalendarFormat:timeZone:locale: available(我不相信iPhone/Cocoa Touch包括这个),你可能需要使用strftime和一些c风格的字符串。您可以使用NSDate -timeIntervalSince1970从NSDate中获取UNIX时间戳。

+(NSString*)date2str:(NSDate*)myNSDateInstance onlyDate:(BOOL)onlyDate{
    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    if (onlyDate) {
        [formatter setDateFormat:@"yyyy-MM-dd"];
    }else{
        [formatter setDateFormat: @"yyyy-MM-dd HH:mm:ss"];
    }

    //Optionally for time zone conversions
    //   [formatter setTimeZone:[NSTimeZone timeZoneWithName:@"..."]];

    NSString *stringFromDate = [formatter stringFromDate:myNSDateInstance];
    return stringFromDate;
}

+(NSDate*)str2date:(NSString*)dateStr{
    if ([dateStr isKindOfClass:[NSDate class]]) {
        return (NSDate*)dateStr;
    }

    NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
    [dateFormat setDateFormat:@"yyyy-MM-dd"];
    NSDate *date = [dateFormat dateFromString:dateStr];
    return date;
}

iOS 15更新

iOS 15现在支持直接在Date对象上调用.格式化,而不需要显式的DateFormatter。

常见格式示例

文档

date.formatted() // 6/8/2021, 7:30 PM
date.formatted(date: .omitted, time: .complete) // 19:30
date.formatted(date: .omitted, time: .standard) // 07:30 PM
date.formatted(date: .omitted, time: .shortened) // 7:30 PM
date.formatted(date: .omitted, time: .omitted)

替代语法

文档

// We can also specify each DateComponent separately by chaining modifiers.
date.formatted(.dateTime.weekday(.wide).day().month().hour().minute())
// Tuesday, Jun 8, 7:30 pm

// Answer to specific question
date.formatted(.dateTime.year())

定义您自己的实用程序格式的日期所需的日期格式 如。

NSString * stringFromDate(NSDate *date)  
 {   NSDateFormatter *formatter
    [[NSDateFormatter alloc] init];  
    [formatter setDateFormat:@"MM ∕ dd ∕ yyyy, hh꞉mm a"];    
    return [formatter stringFromDate:date]; 
}