我如何转换,NSDate到NSString,以便只有年在@“yyyy”格式输出到字符串?


当前回答


使用扩展有清晰的代码


您可以编写一个扩展来将任何Date对象转换为任何所需的日历和格式

extension Date{
    func asString(format: String = "yy/MM/dd HH:mm",
                  for identifier: Calendar.Identifier = .persian) -> String {
        let formatter = DateFormatter()
        formatter.calendar = Calendar(identifier: identifier)
        formatter.dateFormat = format
        
        return formatter.string(from: self)
    }
}

然后这样使用它:

let now = Date()

print(now.asString())  // prints -> 00/04/18 20:25
print(now.asString(format: "yyyy/MM/dd"))  // prints -> 1400/04/18
print(now.asString(format: "MM/dd", for: .gregorian))  //  prints -> 07/09  

要了解如何指定您想要的格式字符串,请查看此链接。 关于如何格式化日期的完整参考,请参阅Apple官方日期格式化指南。

其他回答

+(NSString*)date2str:(NSDate*)myNSDateInstance onlyDate:(BOOL)onlyDate{
    NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
    if (onlyDate) {
        [formatter setDateFormat:@"yyyy-MM-dd"];
    }else{
        [formatter setDateFormat: @"yyyy-MM-dd HH:mm:ss"];
    }

    //Optionally for time zone conversions
    //   [formatter setTimeZone:[NSTimeZone timeZoneWithName:@"..."]];

    NSString *stringFromDate = [formatter stringFromDate:myNSDateInstance];
    return stringFromDate;
}

+(NSDate*)str2date:(NSString*)dateStr{
    if ([dateStr isKindOfClass:[NSDate class]]) {
        return (NSDate*)dateStr;
    }

    NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
    [dateFormat setDateFormat:@"yyyy-MM-dd"];
    NSDate *date = [dateFormat dateFromString:dateStr];
    return date;
}

如何……

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy"];

//Optionally for time zone conversions
[formatter setTimeZone:[NSTimeZone timeZoneWithName:@"..."]];

NSString *stringFromDate = [formatter stringFromDate:myNSDateInstance];

//unless ARC is active
[formatter release];

Swift 4.2:

func stringFromDate(_ date: Date) -> String {
    let formatter = DateFormatter()
    formatter.dateFormat = "dd MMM yyyy HH:mm" //yyyy
    return formatter.string(from: date)
}

简单的方法,使用c#风格的方式将日期转换为字符串。

用法:

let a = time.asString()
// 1990-03-25


let b = time.asString("MM ∕ dd ∕ yyyy, hh꞉mm a")
// 03 / 25 / 1990, 10:33 PM

扩展:

extension Date {
    func asString(_ template: String? = nil) -> String {
        if let template = template {
            let df = DateFormatter.with(template: template)
            
            return df.string(from: self)
        }
        else {
            return globalDateFormatter.string(from: self)
        }
    }
}

// Here you can set default template for DateFormatter
public let globalDateFormatter: DateFormatter = DateFormatter.with(template: "y-M-d")

public extension DateFormatter {
    static func with(template: String ) -> DateFormatter {
        let df = DateFormatter()
        df.dateFormat = template
        return df
    }
}

如果你没有NSDate -descriptionWithCalendarFormat:timeZone:locale: available(我不相信iPhone/Cocoa Touch包括这个),你可能需要使用strftime和一些c风格的字符串。您可以使用NSDate -timeIntervalSince1970从NSDate中获取UNIX时间戳。

iOS 15更新

iOS 15现在支持直接在Date对象上调用.格式化,而不需要显式的DateFormatter。

常见格式示例

文档

date.formatted() // 6/8/2021, 7:30 PM
date.formatted(date: .omitted, time: .complete) // 19:30
date.formatted(date: .omitted, time: .standard) // 07:30 PM
date.formatted(date: .omitted, time: .shortened) // 7:30 PM
date.formatted(date: .omitted, time: .omitted)

替代语法

文档

// We can also specify each DateComponent separately by chaining modifiers.
date.formatted(.dateTime.weekday(.wide).day().month().hour().minute())
// Tuesday, Jun 8, 7:30 pm

// Answer to specific question
date.formatted(.dateTime.year())