从他们的IP获取国家访客

我想通过他们的IP吸引游客…现在我正在使用这个(http://api.hostip.info/country.php?ip=......)

这是我的代码:

<?php

if (isset($_SERVER['HTTP_CLIENT_IP']))
{
    $real_ip_adress = $_SERVER['HTTP_CLIENT_IP'];
}

if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
{
    $real_ip_adress = $_SERVER['HTTP_X_FORWARDED_FOR'];
}
else
{
    $real_ip_adress = $_SERVER['REMOTE_ADDR'];
}

$cip = $real_ip_adress;
$iptolocation = 'http://api.hostip.info/country.php?ip=' . $cip;
$creatorlocation = file_get_contents($iptolocation);

?>

好吧，它正常工作，但问题是，这返回国家代码，如US或CA.，而不是整个国家名称，如美国或加拿大。

那么，除了hostip.info提供的这些，还有什么好的选择吗?

我知道我可以编写一些代码，最终将这两个字母转换为整个国家的名称，但我实在懒得编写包含所有国家的代码……

注:出于某种原因，我不想使用任何现成的CSV文件或任何代码，将抓取这个信息为我，像ip2country现成的代码和CSV。

当前回答

Try

  <?php
  //gives you the IP address of the visitors
  if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
      $ip = $_SERVER['HTTP_CLIENT_IP'];}
  else if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
      $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
  } else {
      $ip = $_SERVER['REMOTE_ADDR'];
  }

  //return the country code
  $url = "http://api.wipmania.com/$ip";
  $country = file_get_contents($url);
  echo $country;

  ?>

2019-04-06 13:00:11

其他回答

将127.0.0.1替换为访问者IpAddress。

$country = geoip_country_name_by_name('127.0.0.1');

安装说明在这里，并阅读了解如何获取城市，州，国家，经度，纬度等…

2014-11-01 12:36:34

Try

  <?php
  //gives you the IP address of the visitors
  if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
      $ip = $_SERVER['HTTP_CLIENT_IP'];}
  else if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
      $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
  } else {
      $ip = $_SERVER['REMOTE_ADDR'];
  }

  //return the country code
  $url = "http://api.wipmania.com/$ip";
  $country = file_get_contents($url);
  echo $country;

  ?>

2019-04-06 13:00:11

以下是使用guzzle的更清晰的工作版本:

你可以使用curl而不是guzzle，这只是一个简单的get请求。

    function ip_info($ip = NULL, $purpose = "location", $deep_detect = TRUE) {
        $output = NULL;
        if (filter_var($ip, FILTER_VALIDATE_IP) === FALSE) {
            $ip = $_SERVER["REMOTE_ADDR"];
            if ($deep_detect) {
                if (filter_var(@$_SERVER['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP))
                    $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
                if (filter_var(@$_SERVER['HTTP_CLIENT_IP'], FILTER_VALIDATE_IP))
                    $ip = $_SERVER['HTTP_CLIENT_IP'];
            }
        }
        $purpose    = str_replace(array("name", "\n", "\t", " ", "-", "_"), NULL, strtolower(trim($purpose)));
        $support    = array("country", "countrycode", "state", "region", "city", "location", "address");
        $continents = array(
            "AF" => "Africa",
            "AN" => "Antarctica",
            "AS" => "Asia",
            "EU" => "Europe",
            "OC" => "Australia (Oceania)",
            "NA" => "North America",
            "SA" => "South America"
        );
        if (filter_var($ip, FILTER_VALIDATE_IP) && in_array($purpose, $support, true)) {
            $client = New \GuzzleHttp\Client();
            $ipdat = json_decode($client->request('GET','http://www.geoplugin.net/json.gp',$params = [
                'query' => [
                    'ip' => $ip,
                ]
            ])->getBody()->getContents(),true);
            if (strlen(trim($ipdat['geoplugin_countryCode'])) === 2) {
                switch ($purpose) {
                    case "location":
                        $output = array(
                            "city"           => $ipdat['geoplugin_city'],
                            "state"          => $ipdat['geoplugin_regionName'],
                            "country"        => $ipdat['geoplugin_countryName'],
                            "country_code"   => $ipdat['geoplugin_countryCode'],
                            "continent"      => $continents[strtoupper($ipdat['geoplugin_continentCode'])],
                            "continent_code" => $ipdat['geoplugin_continentCode']
                        );
                        break;
                    case "address":
                        $address = array($ipdat['geoplugin_countryName']);
                        if (@strlen($ipdat['geoplugin_regionName']) >= 1)
                            $address[] = $ipdat['geoplugin_regionName'];
                        if (@strlen($ipdat['geoplugin_city']) >= 1)
                            $address[] = $ipdat['geoplugin_city'];
                        $output = implode(", ", array_reverse($address));
                        break;
                    case "city":
                        $output = $ipdat['geoplugin_city'];
                        break;
                    case "region":
                    case "state":
                        $output = $ipdat['geoplugin_regionName'];
                        break;
                    case "country":
                        $output = $ipdat['geoplugin_countryName'];
                        break;
                    case "countrycode":
                        $output = $ipdat['geoplugin_countryCode'];
                        break;
                }
            }
        }
        return $output;
    }

2021-02-07 08:19:23

不确定这是否是一个新的服务，但现在(2016)在php中最简单的方法是使用geoplugin的php web服务:http://www.geoplugin.net/php.gp:

基本用法:

// GET IP ADDRESS
if (!empty($_SERVER['HTTP_CLIENT_IP'])) {
    $ip = $_SERVER['HTTP_CLIENT_IP'];
} else if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
    $ip = $_SERVER['HTTP_X_FORWARDED_FOR'];
} else if (!empty($_SERVER['REMOTE_ADDR'])) {
    $ip = $_SERVER['REMOTE_ADDR'];
} else {
    $ip = false;
}

// CALL THE WEBSERVICE
$ip_info = unserialize(file_get_contents('http://www.geoplugin.net/php.gp?ip='.$ip));

它们还提供了一个现成的类:http://www.geoplugin.com/_media/webservices/geoplugin.class.php.tgz?id=webservices%3Aphp&cache=cache

2016-06-17 19:37:09

用户国家API正是您所需要的。下面是一个使用file_get_contents()的示例代码，就像你最初做的那样:

$result = json_decode(file_get_contents('http://usercountry.com/v1.0/json/'.$cip), true);
$result['country']['name']; // this contains what you need

2017-08-10 04:05:07

从他们的IP获取国家访客

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