新版Pandas使用以下界面加载Excel文件:
read_excel('path_to_file.xls', 'Sheet1', index_col=None, na_values=['NA'])
但如果我不知道有哪些床单呢?
例如,我正在工作的excel文件,如下表
数据1,数据2…,数据N, foo, bar
但我不知道先验的N。
有没有办法从熊猫的excel文档中获得表的列表?
新版Pandas使用以下界面加载Excel文件:
read_excel('path_to_file.xls', 'Sheet1', index_col=None, na_values=['NA'])
但如果我不知道有哪些床单呢?
例如,我正在工作的excel文件,如下表
数据1,数据2…,数据N, foo, bar
但我不知道先验的N。
有没有办法从熊猫的excel文档中获得表的列表?
当前回答
With the load_workbook readonly option, what was earlier seen as a execution seen visibly waiting for many seconds happened with milliseconds. The solution could however be still improved. import pandas as pd from openpyxl import load_workbook class ExcelFile: def __init__(self, **kwargs): ........ ..... self._SheetNames = list(load_workbook(self._name,read_only=True,keep_links=False).sheetnames) The Excelfile.parse takes the same time as reading the complete xls in order of 10s of sec. This result was obtained with windows 10 operating system with below package versions C:\>python -V Python 3.9.1 C:\>pip list Package Version --------------- ------- et-xmlfile 1.0.1 numpy 1.20.2 openpyxl 3.0.7 pandas 1.2.3 pip 21.0.1 python-dateutil 2.8.1 pytz 2021.1 pyxlsb 1.0.8 setuptools 49.2.1 six 1.15.0 xlrd 2.0.1
其他回答
你仍然可以使用ExcelFile类(和sheet_names属性):
xl = pd.ExcelFile('foo.xls')
xl.sheet_names # see all sheet names
xl.parse(sheet_name) # read a specific sheet to DataFrame
更多选项参见文档解析…
import pandas as pd
path = "\\DB\\Expense\\reconcile\\"
file_name = "202209-v01.xlsx"
df = pd.read_excel(path + file_name, None)
print(df)
sheet_names = list(df.keys())
# print last sheet name
print(sheet_names[len(sheet_names)-1])
last_month = df.get(sheet_names[len(sheet_names)-1])
print(last_month)
基于@dhwanil_shah的回答,您不需要提取整个文件。zf。打开它可以直接从压缩文件中读取。
import xml.etree.ElementTree as ET
import zipfile
def xlsxSheets(f):
zf = zipfile.ZipFile(f)
f = zf.open(r'xl/workbook.xml')
l = f.readline()
l = f.readline()
root = ET.fromstring(l)
sheets=[]
for c in root.findall('{http://schemas.openxmlformats.org/spreadsheetml/2006/main}sheets/*'):
sheets.append(c.attrib['name'])
return sheets
连续的两个readline很难看,但是内容只在文本的第二行。不需要解析整个文件。
这个解决方案似乎比read_excel版本快得多,而且很可能也比完整的提取版本快得多。
#It will work for Both '.xls' and '.xlsx' by using pandas
import pandas as pd
excel_Sheet_names = (pd.ExcelFile(excelFilePath)).sheet_names
#for '.xlsx' use only openpyxl
from openpyxl import load_workbook
excel_Sheet_names = (load_workbook(excelFilePath, read_only=True)).sheet_names
如果你:
关注业绩 在执行时不需要文件中的数据。 想要使用传统的库还是使用自己的解决方案
下面是一个~10Mb的xlsx, xlsb文件的基准测试。
xls, xlsx
from openpyxl import load_workbook
def get_sheetnames_xlsx(filepath):
wb = load_workbook(filepath, read_only=True, keep_links=False)
return wb.sheetnames
基准测试:~ 14倍的速度提升
# get_sheetnames_xlsx vs pd.read_excel
225 ms ± 6.21 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
3.25 s ± 140 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
xlsb
from pyxlsb import open_workbook
def get_sheetnames_xlsb(filepath):
with open_workbook(filepath) as wb:
return wb.sheets
基准测试:~ 56倍的速度提升
# get_sheetnames_xlsb vs pd.read_excel
96.4 ms ± 1.61 ms per loop (mean ± std. dev. of 7 runs, 10 loops each)
5.36 s ± 162 ms per loop (mean ± std. dev. of 7 runs, 1 loop each)
注:
这是一个很好的资源 http://www.python-excel.org/ XLRD从2020年起不再维持