Raugaral的回答，但是有-p功能。很丑，但很管用:

function mkdirp(dir) {
    let dirs = dir.split(/\\/).filter(asdf => !asdf.match(/^\s*$/))
    let fullpath = ''

    // Production directory will begin \\, test is on my local drive.
    if (dirs[0].match(/C:/i)) {
        fullpath = dirs[0] + '\\'
    }
    else {
        fullpath = '\\\\' + dirs[0] + '\\'
    }

    // Start from root directory + 1, build out one level at a time.
    dirs.slice(1).map(asdf => {
        fullpath += asdf + '\\'
        if (!fs.existsSync(fullpath)) {
            fs.mkdirSync(fullpath)
        }
    })
}//mkdirp

下面是我用来创建目录的ES6代码(当它不存在时):

const fs = require('fs');
const path = require('path');

function createDirectory(directoryPath) {
  const directory = path.normalize(directoryPath);

  return new Promise((resolve, reject) => {
    fs.stat(directory, (error) => {
      if (error) {
        if (error.code === 'ENOENT') {
          fs.mkdir(directory, (error) => {
            if (error) {
              reject(error);
            } else {
              resolve(directory);
            }
          });
        } else {
          reject(error);
        }
      } else {
        resolve(directory);
      }
    });
  });
}

const directoryPath = `${__dirname}/test`;

createDirectory(directoryPath).then((path) => {
  console.log(`Successfully created directory: '${path}'`);
}).catch((error) => {
  console.log(`Problem creating directory: ${error.message}`)
});

注意:

In the beginning of the createDirectory function, I normalize the path to guarantee that the path seperator type of the operating system will be used consistently (e.g. this will turn C:\directory/test into C:\directory\test (when being on Windows) fs.exists is deprecated, that's why I use fs.stat to check if the directory already exists If a directory doesn't exist, the error code will be ENOENT (Error NO ENTry) The directory itself will be created using fs.mkdir I prefer the asynchronous function fs.mkdir over it's blocking counterpart fs.mkdirSync and because of the wrapping Promise it will be guaranteed that the path of the directory will only be returned after the directory has been successfully created

fs的node.js文档。mkdir基本上遵循Linux手册页的mkdir(2)。这表明，如果路径存在，但不是目录，也将指示EEXIST，如果你走这条路，就会创建一个尴尬的角落情况。

你最好调用fs。Stat将告诉您路径是否存在，以及它是否是单个调用中的目录。对于(我假设的是)目录已经存在的正常情况，它只是一次文件系统命中。

这些fs模块方法是对原生C api的精简包装，所以你必须检查node.js文档中引用的手册页以获得详细信息。

您还可以使用fs-extra，它提供了许多常用的文件操作。

示例代码:

var fs = require('fs-extra')

fs.mkdirs('/tmp/some/long/path/that/prob/doesnt/exist', function (err) {
  if (err) return console.error(err)
  console.log("success!")
})

fs.mkdirsSync('/tmp/another/path')

文档地址:https://github.com/jprichardson/node-fs-extra#mkdirsdir-callback

实现这一点的好方法是使用mkdirp模块。

$ npm install mkdirp

使用它来运行需要该目录的函数。回调函数在路径创建后或路径已经存在时调用。mkdirp创建目录路径失败，设置错误err。

var mkdirp = require('mkdirp');
mkdirp('/tmp/some/path/foo', function(err) { 

    // path exists unless there was an error

});

上面@Liberateur的答案对我来说无效(Node v8.10.0)。 做了一点修改，但我不确定这是否是一个正确的方式。请建议。

// Get modules node
const fs   = require('fs');
const path = require('path');

// Create
function mkdirpath(dirPath)
{
    try {
        fs.accessSync(dirPath, fs.constants.R_OK | fs.constants.W_OK);
    }
    catch(err) {
        try
        {
            fs.mkdirSync(dirPath);
        }
        catch(e)
        {
            mkdirpath(path.dirname(dirPath));
            mkdirpath(dirPath);
        }
    }
}

// Create folder path
mkdirpath('my/new/folder/create');