我有一个应用程序，可以在Xcode6-Beta1和Xcode6-Beta2与iOS7和iOS8上正常工作。但是对于Xcode6-Beta3, Beta4, Beta5，我在iOS8上面临网络问题，但在iOS7上一切都很好。我得到错误“网络连接丢失”。错误如下:
Error: ErrorDomain =NSURLErrorDomain Code=-1005 "The network connection was lost."UserInfo=0x7ba8e5b0 {NSErrorFailingURLStringKey=， _kCFStreamErrorCodeKey=57, NSErrorFailingURLKey=， NSLocalizedDescription=网络连接丢失。， _kCFStreamErrorDomainKey=1, NSUnderlyingError=0x7a6957e0 "The network connection was lost."｝
我使用AFNetworking 2。X和下面的代码片段进行网络调用:
AFHTTPRequestOperationManager *manager = [AFHTTPRequestOperationManager manager];
[manager setSecurityPolicy:policy];
manager.requestSerializer = [AFHTTPRequestSerializer serializer];
manager.responseSerializer = [AFHTTPResponseSerializer serializer];
[manager POST:<example-url>
parameters:<parameteres>
success:^(AFHTTPRequestOperation *operation, id responseObject) {
NSLog(@“Success: %@", responseObject);
} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
NSLog(@"Error: %@", error);
}];
我尝试了NSURLSession，但仍然收到相同的错误。
On top of all the answers i found one nice solution. Actually The issue related to network connection fail for iOS 12 onword is because there is a bug in the iOS 12.0 onword. And it Yet to resolved. I had gone through the git hub community for AFNetworking related issue when app came from background and tries to do network call and fails on connection establish. I spend 3 days on this and tries many things to get to the root cause for this and found nothing. Finally i got some light in the dark when i red this blog https://github.com/AFNetworking/AFNetworking/issues/4279
据说iOS 12系统有漏洞。基本上，如果应用程序不在前台，你就不能期望网络调用完成。由于这个错误，网络呼叫被中断，我们在日志中得到网络故障。
我给你的最好的建议是，当你的应用从后台到前台有网络呼叫时，提供一些延迟。使调度中的网络调用具有一定的延迟。你永远不会得到网络呼叫掉线或连接丢失。
不要等待苹果在iOS 12中解决这个问题，因为它仍然没有修复。
你可以通过为你的网络请求NSURLConnection, NSURLSession或AFNetworking或ALAMOFIRE提供一些延迟来解决这个问题。欢呼:)
我在iOS 8设备上运行时也遇到了这个问题。
这里有更详细的说明，似乎是iOS试图使用已经超时的连接。
我的问题与那个链接中解释的Keep-Alive问题不一样，但它似乎是相同的最终结果。
我已经通过运行一个递归块纠正了我的问题，每当我收到一个错误-1005，这使得连接最终通过，即使有时递归可以在连接工作之前循环100+次，然而，它只增加了一秒钟的运行时间，我打赌这只是需要调试器为我打印NSLog的时间。
下面是我如何用AFNetworking运行递归块:
将此代码添加到连接类文件中
// From Mike Ash's recursive block fixed-point-combinator strategy https://gist.github.com/1254684
dispatch_block_t recursiveBlockVehicle(void (^block)(dispatch_block_t recurse))
{
// assuming ARC, so no explicit copy
return ^{ block(recursiveBlockVehicle(block)); };
}
typedef void (^OneParameterBlock)(id parameter);
OneParameterBlock recursiveOneParameterBlockVehicle(void (^block)(OneParameterBlock recurse, id parameter))
{
return ^(id parameter){ block(recursiveOneParameterBlockVehicle(block), parameter); };
}
然后这样使用它:
+ (void)runOperationWithURLPath:(NSString *)urlPath
andStringDataToSend:(NSString *)stringData
withTimeOut:(NSString *)timeOut
completionBlockWithSuccess:(void (^)(AFHTTPRequestOperation *operation, id responseObject))success
failure:(void (^)(AFHTTPRequestOperation *operation, NSError *error))failure
{
OneParameterBlock run = recursiveOneParameterBlockVehicle(^(OneParameterBlock recurse, id parameter) {
// Put the request operation here that you want to keep trying
NSNumber *offset = parameter;
NSLog(@"--------------- Attempt number: %@ ---------------", offset);
MyAFHTTPRequestOperation *operation =
[[MyAFHTTPRequestOperation alloc] initWithURLPath:urlPath
andStringDataToSend:stringData
withTimeOut:timeOut];
[operation setCompletionBlockWithSuccess:
^(AFHTTPRequestOperation *operation, id responseObject) {
success(operation, responseObject);
}
failure:^(AFHTTPRequestOperation *operation2, NSError *error) {
if (error.code == -1005) {
if (offset.intValue >= numberOfRetryAttempts) {
// Tried too many times, so fail
NSLog(@"Error during connection: %@",error.description);
failure(operation2, error);
} else {
// Failed because of an iOS bug using timed out connections, so try again
recurse(@(offset.intValue+1));
}
} else {
NSLog(@"Error during connection: %@",error.description);
failure(operation2, error);
}
}];
[[NSOperationQueue mainQueue] addOperation:operation];
});
run(@0);
}
您将看到我使用了一个AFHTTPRequestOperation子类，但添加了您自己的请求代码。重要的部分是调用递归(@offset.intValue+1));使该块再次被调用。
