我有一些参数,我想POST表单编码到我的服务器:

{
    'userName': 'test@gmail.com',
    'password': 'Password!',
    'grant_type': 'password'
}

我像这样发送我的请求(目前没有参数)

var obj = {
  method: 'POST',
  headers: {
    'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
  },
};
fetch('https://example.com/login', obj)
  .then(function(res) {
    // Do stuff with result
  }); 

如何在请求中包含表单编码的参数?


当前回答

var details = {
    'userName': 'test@gmail.com',
    'password': 'Password!',
    'grant_type': 'password'
};

var formBody = [];
for (var property in details) {
  var encodedKey = encodeURIComponent(property);
  var encodedValue = encodeURIComponent(details[property]);
  formBody.push(encodedKey + "=" + encodedValue);
}
formBody = formBody.join("&");

fetch('http://identity.azurewebsites.net' + '/token', {
  method: 'POST',
  headers: {
    'Accept': 'application/json',
    'Content-Type': 'application/x-www-form-urlencoded'
  },
  body: formBody
})

它对我很有帮助,而且没有任何错误

参考资料:https://gist.github.com/milon87/f391e54e64e32e1626235d4dc4d16dc8

其他回答

如果你正在使用JQuery,这也是有效的。

fetch(url, {
      method: 'POST', 
      body: $.param(data),
      headers:{
        'Content-Type': 'application/x-www-form-urlencoded'
      }
})

使用URLSearchParams

https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams

var data = new URLSearchParams();
data.append('userName', 'test@gmail.com');
data.append('password', 'Password');
data.append('grant_type', 'password');
var details = {
    'userName': 'test@gmail.com',
    'password': 'Password!',
    'grant_type': 'password'
};

var formBody = [];
for (var property in details) {
  var encodedKey = encodeURIComponent(property);
  var encodedValue = encodeURIComponent(details[property]);
  formBody.push(encodedKey + "=" + encodedValue);
}
formBody = formBody.join("&");

fetch('http://identity.azurewebsites.net' + '/token', {
  method: 'POST',
  headers: {
    'Accept': 'application/json',
    'Content-Type': 'application/x-www-form-urlencoded'
  },
  body: formBody
})

它对我很有帮助,而且没有任何错误

参考资料:https://gist.github.com/milon87/f391e54e64e32e1626235d4dc4d16dc8

您可以使用react-native-easy-app,更容易发送http请求和制定拦截请求。

import { XHttp } from 'react-native-easy-app';

* Synchronous request
const params = {name:'rufeng',age:20}
const response = await XHttp().url(url).param(params).formEncoded().execute('GET');
const {success, json, message, status} = response;


* Asynchronous requests
XHttp().url(url).param(params).formEncoded().get((success, json, message, status)=>{
    if (success){
       this.setState({content: JSON.stringify(json)});
    } else {
       showToast(msg);
    }
});

根据规范,使用encodeURIComponent不会给你一个符合要求的查询字符串。州:

Control names and values are escaped. Space characters are replaced by +, and then reserved characters are escaped as described in [RFC1738], section 2.2: Non-alphanumeric characters are replaced by %HH, a percent sign and two hexadecimal digits representing the ASCII code of the character. Line breaks are represented as "CR LF" pairs (i.e., %0D%0A). The control names/values are listed in the order they appear in the document. The name is separated from the value by = and name/value pairs are separated from each other by &.

问题是,encodeURIComponent将空格编码为%20,而不是+。

表单主体应该使用其他答案中显示的encodeURIComponent方法的变体进行编码。

const formUrlEncode = str => {
  return str.replace(/[^\d\w]/g, char => {
    return char === " " 
      ? "+" 
      : encodeURIComponent(char);
  })
}

const data = {foo: "bar߃©˙∑  baz", boom: "pow"};

const dataPairs = Object.keys(data).map( key => {
  const val = data[key];
  return (formUrlEncode(key) + "=" + formUrlEncode(val));
}).join("&");

// dataPairs is "foo=bar%C3%9F%C6%92%C2%A9%CB%99%E2%88%91++baz&boom=pow"