我有一些参数，我想POST表单编码到我的服务器:
{
'userName': 'test@gmail.com',
'password': 'Password!',
'grant_type': 'password'
}
我像这样发送我的请求(目前没有参数)
var obj = {
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
},
};
fetch('https://example.com/login', obj)
.then(function(res) {
// Do stuff with result
});
如何在请求中包含表单编码的参数?
当前回答
只是这样做，UrlSearchParams做的把戏 这是我的代码，如果能帮到别人的话
import 'url-search-params-polyfill';
const userLogsInOptions = (username, password) => {
// const formData = new FormData();
const formData = new URLSearchParams();
formData.append('grant_type', 'password');
formData.append('client_id', 'XXXX-app');
formData.append('username', username);
formData.append('password', password);
return (
{
method: 'POST',
headers: {
// "Content-Type": "application/json; charset=utf-8",
"Content-Type": "application/x-www-form-urlencoded",
},
body: formData.toString(),
json: true,
}
);
};
const getUserUnlockToken = async (username, password) => {
const userLoginUri = `${scheme}://${host}/auth/realms/${realm}/protocol/openid-connect/token`;
const response = await fetch(
userLoginUri,
userLogsInOptions(username, password),
);
const responseJson = await response.json();
console.log('acces_token ', responseJson.access_token);
if (responseJson.error) {
console.error('error ', responseJson.error);
}
console.log('json ', responseJson);
return responseJson.access_token;
};
其他回答
更简单:
fetch('https://example.com/login', {
method: 'POST',
headers:{
'Content-Type': 'application/x-www-form-urlencoded'
},
body: new URLSearchParams({
'userName': 'test@gmail.com',
'password': 'Password!',
'grant_type': 'password'
})
});
文档:https://developer.mozilla.org/en-US/docs/Web/API/WindowOrWorkerGlobalScope/fetch
只使用
import qs from "qs";
let data = {
'profileId': this.props.screenProps[0],
'accountId': this.props.screenProps[1],
'accessToken': this.props.screenProps[2],
'itemId': this.itemId
};
return axios.post(METHOD_WALL_GET, qs.stringify(data))
你可以使用UrlSearchParams，然后像这样做一个toString():
这里有一个简单的方法:
fetch('https://example.com/login', {
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'
},
body: new UrlSearchParams(...{
'userName': 'test@gmail.com',
'password': 'Password!',
'grant_type': 'password'
})
.toString()
})
.then(res => {
//Deal with response:
})
您可以使用react-native-easy-app，更容易发送http请求和制定拦截请求。
import { XHttp } from 'react-native-easy-app';
* Synchronous request
const params = {name:'rufeng',age:20}
const response = await XHttp().url(url).param(params).formEncoded().execute('GET');
const {success, json, message, status} = response;
* Asynchronous requests
XHttp().url(url).param(params).formEncoded().get((success, json, message, status)=>{
if (success){
this.setState({content: JSON.stringify(json)});
} else {
showToast(msg);
}
});
使用URLSearchParams
https://developer.mozilla.org/en-US/docs/Web/API/URLSearchParams
var data = new URLSearchParams();
data.append('userName', 'test@gmail.com');
data.append('password', 'Password');
data.append('grant_type', 'password');
