我有一些参数，我想POST表单编码到我的服务器:
{
'userName': 'test@gmail.com',
'password': 'Password!',
'grant_type': 'password'
}
我像这样发送我的请求(目前没有参数)
var obj = {
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8',
},
};
fetch('https://example.com/login', obj)
.then(function(res) {
// Do stuff with result
});
如何在请求中包含表单编码的参数?
当前回答
根据规范，使用encodeURIComponent不会给你一个符合要求的查询字符串。州:
Control names and values are escaped. Space characters are replaced by +, and then reserved characters are escaped as described in [RFC1738], section 2.2: Non-alphanumeric characters are replaced by %HH, a percent sign and two hexadecimal digits representing the ASCII code of the character. Line breaks are represented as "CR LF" pairs (i.e., %0D%0A). The control names/values are listed in the order they appear in the document. The name is separated from the value by = and name/value pairs are separated from each other by &.
问题是，encodeURIComponent将空格编码为%20，而不是+。
表单主体应该使用其他答案中显示的encodeURIComponent方法的变体进行编码。
const formUrlEncode = str => {
return str.replace(/[^\d\w]/g, char => {
return char === " "
? "+"
: encodeURIComponent(char);
})
}
const data = {foo: "bar߃©˙∑ baz", boom: "pow"};
const dataPairs = Object.keys(data).map( key => {
const val = data[key];
return (formUrlEncode(key) + "=" + formUrlEncode(val));
}).join("&");
// dataPairs is "foo=bar%C3%9F%C6%92%C2%A9%CB%99%E2%88%91++baz&boom=pow"
其他回答
不需要使用jQuery、querystring或手动组装有效负载。URLSearchParams是一种方法，这里是一个最简洁的答案与完整的请求示例:
fetch('https://example.com/login', {
method: 'POST',
body: new URLSearchParams({
param: 'Some value',
anotherParam: 'Another value'
})
})
.then(response => {
// Do stuff with the response
});
同样的技术使用async / await。
const login = async () => {
const response = await fetch('https://example.com/login', {
method: 'POST',
body: new URLSearchParams({
param: 'Some value',
anotherParam: 'Another value'
})
})
// Do stuff with the response
}
是的，您可以使用Axios或任何其他HTTP客户端库来代替本机获取。
您可以使用react-native-easy-app，更容易发送http请求和制定拦截请求。
import { XHttp } from 'react-native-easy-app';
* Synchronous request
const params = {name:'rufeng',age:20}
const response = await XHttp().url(url).param(params).formEncoded().execute('GET');
const {success, json, message, status} = response;
* Asynchronous requests
XHttp().url(url).param(params).formEncoded().get((success, json, message, status)=>{
if (success){
this.setState({content: JSON.stringify(json)});
} else {
showToast(msg);
}
});
你可以使用FormData和URLSearchParams发布为application/x-www-form-urlencoded，示例如下:
如果你有一个表格:
<form>
<input name="username" type="text" />
<input name="password" type="password" />
<button type="submit">login</button>
</form>
您可以添加使用下面的JS来提交表单。
const form = document.querySelector("form");
form.addEventListener("submit", async () => {
const formData = new FormData(form);
try {
await fetch("https://example.com/login", {
method: "POST",
headers: {
"Content-Type": "application/x-www-form-urlencoded",
},
body: new URLSearchParams(formData),
});
} catch (err) {
console.log(err);
}
});
根据规范，使用encodeURIComponent不会给你一个符合要求的查询字符串。州:
Control names and values are escaped. Space characters are replaced by +, and then reserved characters are escaped as described in [RFC1738], section 2.2: Non-alphanumeric characters are replaced by %HH, a percent sign and two hexadecimal digits representing the ASCII code of the character. Line breaks are represented as "CR LF" pairs (i.e., %0D%0A). The control names/values are listed in the order they appear in the document. The name is separated from the value by = and name/value pairs are separated from each other by &.
问题是，encodeURIComponent将空格编码为%20，而不是+。
表单主体应该使用其他答案中显示的encodeURIComponent方法的变体进行编码。
const formUrlEncode = str => {
return str.replace(/[^\d\w]/g, char => {
return char === " "
? "+"
: encodeURIComponent(char);
})
}
const data = {foo: "bar߃©˙∑ baz", boom: "pow"};
const dataPairs = Object.keys(data).map( key => {
const val = data[key];
return (formUrlEncode(key) + "=" + formUrlEncode(val));
}).join("&");
// dataPairs is "foo=bar%C3%9F%C6%92%C2%A9%CB%99%E2%88%91++baz&boom=pow"
只是这样做，UrlSearchParams做的把戏 这是我的代码，如果能帮到别人的话
import 'url-search-params-polyfill';
const userLogsInOptions = (username, password) => {
// const formData = new FormData();
const formData = new URLSearchParams();
formData.append('grant_type', 'password');
formData.append('client_id', 'XXXX-app');
formData.append('username', username);
formData.append('password', password);
return (
{
method: 'POST',
headers: {
// "Content-Type": "application/json; charset=utf-8",
"Content-Type": "application/x-www-form-urlencoded",
},
body: formData.toString(),
json: true,
}
);
};
const getUserUnlockToken = async (username, password) => {
const userLoginUri = `${scheme}://${host}/auth/realms/${realm}/protocol/openid-connect/token`;
const response = await fetch(
userLoginUri,
userLogsInOptions(username, password),
);
const responseJson = await response.json();
console.log('acces_token ', responseJson.access_token);
if (responseJson.error) {
console.error('error ', responseJson.error);
}
console.log('json ', responseJson);
return responseJson.access_token;
};
