我刚刚发现另一个bug时使用UITableViewController。当键盘出现时，它不会自动滚动。我注意到这是因为contentInsetAdjustmentBehavior = .never在UITableView上。

在viewdidload

-(void)viewdidload{

[super viewdidload];

    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(keyboardWillChange:) name:UIKeyboardWillChangeFrameNotification object:nil];
}

    -(void)keyboardWillChange:(NSNotification*)sender{

        NSLog(@"keyboardwillchange sender %@",sender);

float margin=0  // set your own topmargin


        CGFloat originY = [[sender.userInfo objectForKey:UIKeyboardFrameEndUserInfoKey] CGRectValue].origin.y;


        if (originY >= self.view.frame.size.height){

            NSLog(@"keyboardclose");



            [tb_ setFrame:CGRectMake(0, margin, self.view.frame.size.width, self.view.frame.size.height-margin)];

        }else{

            NSLog(@"keyobard on");

            float adjustedHeight = self.view.frame.size.height - margin - (self.view.frame.size.height-originY);

            [tb_ setFrame:CGRectMake(0, margin, self.view.frame.size.width, adjustedHeight)];
        }







    }

UITableViewController会自动进行滚动。 与使用UIViewController相比的区别是，当使用TableViewController时，你必须通过使用NavigationController以编程方式创建navbar - buttonitem。

这个解决方案为我工作，请注意这一行

[tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height+160) animated:YES];

您可以更改160值以使其与您的工作相匹配

- (void)keyboardWasShown:(NSNotification*)aNotification
{
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;
    CGRect bkgndRect = activeField.superview.frame;
                        bkgndRect.size.height += kbSize.height;
     [activeField.superview setFrame:bkgndRect];
     [tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height+160) animated:YES];
}

- (void)textFieldDidBeginEditing:(UITextField *)textField
{
   activeField = textField;
}
-(void)textFieldDidEndEditing:(UITextField *)textField
 {
     activeField = nil;
 }
// Called when the UIKeyboardWillHideNotification is sent
- (void)keyboardWillBeHidden:(NSNotification*)aNotification
{
    UIEdgeInsets contentInsets = UIEdgeInsetsZero;
    tableView.contentInset = contentInsets;
    tableView.scrollIndicatorInsets = contentInsets;
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;
    CGRect bkgndRect = activeField.superview.frame;
    //bkgndRect.size.height += kbSize.height;
    [activeField.superview setFrame:bkgndRect];
    [tableView setContentOffset:CGPointMake(0.0, activeField.frame.origin.y-kbSize.height) animated:YES];
}

在Swift中的一个例子，使用从UITableViewCell中获取UITextField的indexPath的文本字段的确切点:

func textFieldDidBeginEditing(textField: UITextField) {
    let pointInTable = textField.convertPoint(textField.bounds.origin, toView: self.accountsTableView)
    let textFieldIndexPath = self.accountsTableView.indexPathForRowAtPoint(pointInTable)
    accountsTableView.scrollToRowAtIndexPath(textFieldIndexPath!, atScrollPosition: .Top, animated: true)
}

我刚刚解决了这样一个问题，我参考了大量的解决方案通过谷歌和堆栈溢出。

首先，请确保你已经为UIScrollView设置了IBOutlet， 那么请仔细看看Apple Doc: Keyboard Management。 最后，如果你可以滚动背景，但键盘仍然覆盖文本字段，请看看这段代码:

// If active text field is hidden by keyboard, scroll it so it's visible
// Your application might not need or want this behavior.
CGRect aRect = self.view.frame;
aRect.size.height -= kbSize.height;

if (aRect.size.height < activeField.frame.origin.y+activeField.frame.size.height) {

    CGPoint scrollPoint = CGPointMake(0.0, activeField.frame.origin.y+activeField.frame.size.height-aRect.size.height);

    [scrollView setContentOffset:scrollPoint animated:YES];

这款游戏与苹果游戏的主要区别在于if条件。我认为apple计算滚动距离和键盘是否覆盖文本字段的条件不准确，所以我做了如上修改。

如果有用请告诉我