我认为没有“正确”的方法来做这件事。您必须为您的用例选择最合适的解决方案。 在我的iPad App中，我有一个UIViewController，它以UIModalPresentationFormSheet的形式呈现，由一个UITableView组成。这个表格每个单元格包含两个UITextFields。 只是调用scrollToRowAtIndexPath:atScrollPosition:animated:在textFieldDidBeginEditing:方法不为我工作。因此，我创建了一个tableFooterView:

- (void)viewDidLoad
{
    [super viewDidLoad];

    m_footerView = [[UIView alloc] initWithFrame:CGRectMake(0.0f, 0.0f, m_tableView.frame.size.width, 300.0f)];
    [m_footerView setBackgroundColor:[UIColor clearColor]];
    [m_tableView setTableFooterView:m_footerView];
    [m_footerView release];
}

这个想法是键盘隐藏tableFooterView而不是UITextFields。tableFooterView必须足够高。之后，你可以在textFieldDidBeginEditing:方法中使用scrollToRowAtIndexPath:atScrollPosition:animated:。

我认为也可以通过添加键盘通知的观察者来动态地显示和隐藏tableFooterView，但我还没有尝试过:

- (void)viewWillAppear:(BOOL)animated
{
    [super viewWillAppear:animated];

    [[NSNotificationCenter defaultCenter] addObserver:self 
                                             selector:@selector(keyboardWillShow:) 
                                                 name:UIKeyboardWillShowNotification 
                                               object:nil];
    [[NSNotificationCenter defaultCenter] addObserver:self 
                                             selector:@selector(keyboardWillHide:) 
                                                 name:UIKeyboardWillHideNotification 
                                               object:nil];
}

- (void)keyboardWillShow:(NSNotification *)notification 
{
     [m_tableView setTableFooterView:m_footerView];
}

- (void)keyboardWillHide:(NSNotification *)notification 
{
     [m_tableView setTableFooterView:nil];
}

- (void)viewWillDisappear:(BOOL)animated
{
    [super viewWillDisappear:animated];

    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillShowNotification object:nil];
    [[NSNotificationCenter defaultCenter] removeObserver:self name:UIKeyboardWillHideNotification object:nil];
}

如果你的UITableView是由UITableViewController的子类管理的，而不是UITableView，并且文本字段委托是UITableViewController，它应该自动管理所有的滚动——所有这些其他注释在实践中是很难实现的。

有关一个好例子，请参阅apple示例代码项目:TaggedLocations。

你可以看到它自动滚动，但似乎没有任何代码做到这一点。该项目还具有自定义表视图单元格，因此，如果使用它作为指南构建应用程序，应该会得到预期的结果。

如果你使用uitableview来放置你的文本字段(来自Jeff Lamarche)，你可以像这样使用委托方法滚动tableview。

(注意:我的文本字段存储在一个数组中，索引与表视图中的行相同)

- (void) textFieldDidBeginEditing:(UITextField *)textField
    {

        int index;
        for(UITextField *aField in textFields){

            if (textField == aField){
                index = [textFields indexOfObject:aField]-1;
            }
        }

         if(index >= 0) 
            [self.tableView scrollToRowAtIndexPath:[NSIndexPath indexPathForRow:index inSection:0] atScrollPosition:UITableViewScrollPositionTop animated:YES];

        [super textFieldDidBeginEditing:textField];
    }

我的方法:

我首先子类化UITextField并添加一个indexPath属性。在牢房里因为…方法我交出indexPath属性。

然后我添加以下代码:

UITableViewCell *cell = [self.tableView cellForRowAtIndexPath:textField.indexPath];

CGPoint cellPoint = [cell convertPoint:textField.center toView:self.tableView];
[UIView animateWithDuration:0.3 animations:^(void){self.tableView.contentOffset = CGPointMake(0, cellPoint.y-50);}];

textFieldShould/WillBegin…等等。

当键盘消失时，你必须反转它:

[UIView animateWithDuration:0.3 animations:^(void){self.tableView.contentOffset = CGPointMake(0, 0);}];

看看我的版本:)

    - (void)keyboardWasShown:(NSNotification *)aNotification
{
    NSDictionary* info = [aNotification userInfo];
    CGSize kbSize = [[info objectForKey:UIKeyboardFrameBeginUserInfoKey] CGRectValue].size;
    CGRect bkgndRect = cellSelected.superview.frame;
    bkgndRect.size.height += kbSize.height;
    [cellSelected.superview setFrame:bkgndRect];
    [tableView setContentOffset:CGPointMake(0.0, cellSelected.frame.origin.y-kbSize.height) animated:YES];
}


- (void)keyboardWasHidden:(NSNotification *)aNotification
{
    [tableView setContentOffset:CGPointMake(0.0, 0.0) animated:YES];
}

Swift最简单的解决方案:

override func viewDidLoad() {
    super.viewDidLoad()
    
    searchBar?.becomeFirstResponder()
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillShow(_:)), name: UIKeyboardDidShowNotification, object: nil)
    NSNotificationCenter.defaultCenter().addObserver(self, selector: #selector(MyViewController.keyboardWillHide(_:)), name: UIKeyboardDidHideNotification, object: nil)
}

deinit {
    NSNotificationCenter.defaultCenter().removeObserver(self)
}

func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
        if let keyboardHeight = userInfo[UIKeyboardFrameEndUserInfoKey]?.CGRectValue.size.height {
            tableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardHeight, 0)
        }
    }
}

func keyboardWillHide(notification: NSNotification) {
    UIView.animateWithDuration(0.2, animations: { self.table_create_issue.contentInset = UIEdgeInsetsMake(0, 0, 0, 0) })
    // For some reason adding inset in keyboardWillShow is animated by itself but removing is not, that's why we have to use animateWithDuration here
    }

Swift 4.2或更高版本

override func viewDidLoad() {
    super.viewDidLoad()
    searchBar?.becomeFirstResponder()
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillShow), name: UIResponder.keyboardDidShowNotification, object: nil)
    NotificationCenter.default.addObserver(self, selector: #selector(self.keyboardWillHide), name: UIResponder.keyboardDidHideNotification, object: nil)
}

deinit {
    NotificationCenter.default.removeObserver(self)
}

 @objc func keyboardWillShow(notification: NSNotification) {
    if let userInfo = notification.userInfo {
            let keyboardHeight = (userInfo[UIResponder.keyboardFrameEndUserInfoKey] as AnyObject).cgRectValue.size.height
            accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: keyboardHeight, right: 0)
        
    }
}
@objc func keyboardWillHide(notification: NSNotification) {
    UIView.animate(withDuration: 0.2, animations: { self.accountSettingsTableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: 0, right: 0) })}
}