Java要求，如果在构造函数中调用this()或super()，它必须是第一条语句。为什么?
例如:
public class MyClass {
public MyClass(int x) {}
}
public class MySubClass extends MyClass {
public MySubClass(int a, int b) {
int c = a + b;
super(c); // COMPILE ERROR
}
}
Sun编译器说，调用super必须是构造函数中的第一条语句。Eclipse编译器说，构造函数调用必须是构造函数中的第一个语句。
然而，你可以通过稍微重新安排代码来解决这个问题:
public class MySubClass extends MyClass {
public MySubClass(int a, int b) {
super(a + b); // OK
}
}
下面是另一个例子:
public class MyClass {
public MyClass(List list) {}
}
public class MySubClassA extends MyClass {
public MySubClassA(Object item) {
// Create a list that contains the item, and pass the list to super
List list = new ArrayList();
list.add(item);
super(list); // COMPILE ERROR
}
}
public class MySubClassB extends MyClass {
public MySubClassB(Object item) {
// Create a list that contains the item, and pass the list to super
super(Arrays.asList(new Object[] { item })); // OK
}
}
因此，它不会阻止您在调用super()之前执行逻辑。它只是阻止您执行无法放入单个表达式中的逻辑。
调用this()也有类似的规则。编译器说，调用this必须是构造函数中的第一条语句。
为什么编译器有这些限制?你能给出一个代码例子，如果编译器没有这个限制，就会发生不好的事情吗?
父类的构造函数需要在子类的构造函数之前调用。这将确保如果在构造函数中调用父类上的任何方法，父类已经正确设置。
你要做的是，将参数传递给超级构造函数是完全合法的，你只需要像你所做的那样内联构造这些参数，或者将它们传递给你的构造函数，然后将它们传递给super:
public MySubClassB extends MyClass {
public MySubClassB(Object[] myArray) {
super(myArray);
}
}
如果编译器没有强制执行，你可以这样做:
public MySubClassB extends MyClass {
public MySubClassB(Object[] myArray) {
someMethodOnSuper(); //ERROR super not yet constructed
super(myArray);
}
}
在父类有默认构造函数的情况下，编译器会自动插入对super的调用。由于Java中的每个类都继承自Object，所以必须以某种方式调用Object的构造函数，并且必须首先执行它。编译器可以自动插入super()。强制super首先出现，强制构造函数主体以正确的顺序执行，即:Object -> Parent -> Child -> ChildOfChild -> SoOnSoForth
因为这就是传承哲学。根据Java语言规范，构造函数体是这样定义的:
ConstructorBody:
{ExplicitConstructorInvocationopt BlockStatementsopt}
构造函数体的第一个语句可以是任意一个
显式调用同一类的另一个构造函数(通过使用关键字“this”);或
直接超类的显式调用(通过使用关键字"super")
If a constructor body does not begin with an explicit constructor invocation and the constructor being declared is not part of the primordial class Object, then the constructor body implicitly begins with a superclass constructor invocation "super();", an invocation of the constructor of its direct superclass that takes no arguments. And so on.. there will be a whole chain of constructors called all the way back to the constructor of Object; "All Classes in the Java platform are Descendants of Object". This thing is called "Constructor Chaining".
为什么会这样?
Java以这种方式定义ConstructorBody的原因是，他们需要维护对象的层次结构。记住继承的定义;它扩展了一个类。话虽如此，你不能扩展不存在的东西。首先需要创建基类(超类)，然后才能派生它(子类)。这就是为什么他们称它们为父类和子类;你不能没有父母就有孩子。
On a technical level, a subclass inherits all the members (fields, methods, nested classes) from its parent. And since Constructors are NOT members (They don't belong to objects. They are responsible of creating objects) so they are NOT inherited by subclasses, but they can be invoked. And since at the time of object creation only ONE constructor is executed. So how do we guarantee the creation of the superclass when you create the subclass object? Thus the concept of "constructor chaining"; so we have the ability to invoke other constructors (i.e. super) from within the current constructor. And Java required this invocation to be the FIRST line in the subclass constructor to maintain the hierarchy and guarantee it. They assume that if you don't explicitly create the parent object FIRST (like if you forgot about it), they will do it implicitly for you.
该检查在编译期间进行。但是我不确定在运行时会发生什么，我们会得到什么样的运行时错误，如果Java没有抛出一个编译错误，当我们显式地试图从子类的构造函数中执行一个基本构造函数时，在它的主体中间，而不是从第一行开始……
