var xhr = new XMLHttpRequest();
xhr.open('POST', 'somewhere', true);
xhr.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');
xhr.onload = function () {
    // do something to response
    console.log(this.responseText);
};
xhr.send('user=person&pwd=password&organization=place&requiredkey=key');

或者如果你可以指望浏览器的支持，你可以使用FormData:

var data = new FormData();
data.append('user', 'person');
data.append('pwd', 'password');
data.append('organization', 'place');
data.append('requiredkey', 'key');

var xhr = new XMLHttpRequest();
xhr.open('POST', 'somewhere', true);
xhr.onload = function () {
    // do something to response
    console.log(this.responseText);
};
xhr.send(data);

这帮助我，因为我想只使用xmlHttpRequest和post对象作为表单数据:

function sendData(data) {
  var XHR = new XMLHttpRequest();
  var FD  = new FormData();

  // Push our data into our FormData object
  for(name in data) {
    FD.append(name, data[name]);
  }

  // Set up our request
  XHR.open('POST', 'https://example.com/cors.php');

  // Send our FormData object; HTTP headers are set automatically
  XHR.send(FD);
}

https://developer.mozilla.org/en-US/docs/Learn/HTML/Forms/Sending_forms_through_JavaScript

下面是一个完整的应用程序json解决方案:

// Input values will be grabbed by ID
<input id="loginEmail" type="text" name="email" placeholder="Email">
<input id="loginPassword" type="password" name="password" placeholder="Password">

// return stops normal action and runs login()
<button onclick="return login()">Submit</button>

<script>
    function login() {
        // Form fields, see IDs above
        const params = {
            email: document.querySelector('#loginEmail').value,
            password: document.querySelector('#loginPassword').value
        }

        const http = new XMLHttpRequest()
        http.open('POST', '/login')
        http.setRequestHeader('Content-type', 'application/json')
        http.send(JSON.stringify(params)) // Make sure to stringify
        http.onload = function() {
            // Do whatever with response
            alert(http.responseText)
        }
    }
</script>

确保你的后端API可以解析JSON。

例如，在Express JS中:

import bodyParser from 'body-parser'
app.use(bodyParser.json())

下面的代码演示了如何做到这一点。

var http = new XMLHttpRequest();
var url = 'get_data.php';
var params = 'orem=ipsum&name=binny';
http.open('POST', url, true);

//Send the proper header information along with the request
http.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');

http.onreadystatechange = function() {//Call a function when the state changes.
    if(http.readyState == 4 && http.status == 200) {
        alert(http.responseText);
    }
}
http.send(params);

如果你有/创建一个对象，你可以用下面的代码把它转换成参数，即:

var params = new Object();
params.myparam1 = myval1;
params.myparam2 = myval2;

// Turn the data object into an array of URL-encoded key/value pairs.
let urlEncodedData = "", urlEncodedDataPairs = [], name;
for( name in params ) {
 urlEncodedDataPairs.push(encodeURIComponent(name)+'='+encodeURIComponent(params[name]));
}

短而现代

您可以使用FormData捕获表单输入值并通过fetch发送它们

fetch(form.action, {method:'post', body: new FormData(form)});

function send() { let form = document.forms['inputform']; fetch(form.action, {method:'post', body: new FormData(form)}); } <form name="inputform" action="somewhere" method="post"> <input value="person" name="user"> <input type="hidden" value="password" name="pwd"> <input value="place" name="organization"> <input type="hidden" value="key" name="requiredkey"> </form> <!-- I remove type="hidden" for some inputs above only for show them --><br> Look: chrome console>network and click <button onclick="send()">send</button>

有一些重复的作品涉及到这一点，但没有人真正阐述它。我将借用公认答案的例子来说明

http.open('POST', url, true);
http.send('lorem=ipsum&name=binny');

为了说明，我过度简化了这一点(我使用http.onload(function(){})而不是那个答案的旧方法)。如果你按原样使用，你会发现你的服务器可能会将POST正文解释为字符串，而不是实际的key=value参数(即PHP不会显示任何$_POST变量)。你必须在http.send()之前传递表单头文件来获取它。

http.setRequestHeader('Content-type', 'application/x-www-form-urlencoded');

如果您使用的是JSON而不是url编码的数据，则应该传递application/ JSON