您还可以使用函数库Dollar在数组上执行indexOf，例如http://www.dollarswift.org/#indexof-indexof

$.indexOf([1, 2, 3, 1, 2, 3], value: 2) 
=> 1

以防有人遇到这种问题

Cannot invoke initializer for type 'Int' with an argument list of type '(Array<Element>.Index?)'

一定要这么做

extension Int {
    var toInt: Int {
        return self
    }
}

then

guard let finalIndex = index?.toInt else {
    return false
}

这些方法对我都适用

这是我对Swift 4的解决方案:

let monday = Day(name: "M")
let tuesday = Day(name: "T")
let friday = Day(name: "F")

let days = [monday, tuesday, friday]

let index = days.index(where: { 
            //important to test with === to be sure it's the same object reference
            $0 === tuesday
        })

虽然indexOf()工作得很好，但它只返回一个索引。

我正在寻找一种优雅的方法来获得满足某些条件的元素的索引数组。

以下是如何做到这一点:

斯威夫特3:

let array = ["apple", "dog", "log"]

let indexes = array.enumerated().filter {
    $0.element.contains("og")
    }.map{$0.offset}

print(indexes)

斯威夫特2:

let array = ["apple", "dog", "log"]

let indexes = array.enumerate().filter {
    $0.element.containsString("og")
    }.map{$0.index}

print(indexes)

如果你还在使用Swift 1.x

然后尝试,

let testArray = ["A","B","C"]

let indexOfA = find(testArray, "A") 
let indexOfB = find(testArray, "B")
let indexOfC = find(testArray, "C")

在Swift 4/5中，使用“firstIndex”查找索引。

let index = array.firstIndex{$0 == value}