我个人更喜欢不带前导零的开头单位(天、小时、分钟)。但是秒应该总是以分钟(0:13)开头，这种表示很容易被认为是“持续时间”，不需要进一步解释(标记为min, sec(s)等)，可用于各种语言(国际化)。

    // returns  (-)d.h:mm:ss(.f)
    //          (-)h:mm:ss(.f)
    //          (-)m:ss(.f)
    function formatSeconds (value, fracDigits) {
        var isNegative = false;
        if (isNaN(value)) {
            return value;
        } else if (value < 0) {
            isNegative = true;
            value = Math.abs(value);
        }
        var days = Math.floor(value / 86400);
        value %= 86400;
        var hours = Math.floor(value / 3600);
        value %= 3600;
        var minutes = Math.floor(value / 60);
        var seconds = (value % 60).toFixed(fracDigits || 0);
        if (seconds < 10) {
            seconds = '0' + seconds;
        }

        var res = hours ? (hours + ':' + ('0' + minutes).slice(-2) + ':' + seconds) : (minutes + ':' + seconds);
        if (days) {
            res = days + '.' + res;
        }
        return (isNegative ? ('-' + res) : res);
    }

//模仿服务器端(.net, c#)持续时间格式:

    public static string Format(this TimeSpan interval)
    {
        string pattern;
        if (interval.Days > 0)          pattern = @"d\.h\:mm\:ss";
        else if (interval.Hours > 0)    pattern = @"h\:mm\:ss";
        else                            pattern = @"m\:ss";
        return string.Format("{0}", interval.ToString(pattern));
    }

toHHMMSS的非原型版本:

    function toHHMMSS(seconds) {
        var sec_num = parseInt(seconds);
        var hours   = Math.floor(sec_num / 3600);
        var minutes = Math.floor((sec_num - (hours * 3600)) / 60);
        var seconds = sec_num - (hours * 3600) - (minutes * 60);        
        if (hours   < 10) {hours   = "0"+hours;}
        if (minutes < 10) {minutes = "0"+minutes;}
        if (seconds < 10) {seconds = "0"+seconds;}
        var time    = hours+':'+minutes+':'+seconds;
        return time;
    }   

这是最简单的方法。

new Date(sec * 1000).toISOString().substr(11, 8)

你可以在没有任何外部JS库的帮助下使用JS Date方法做到这一点，如下所示:

var date = new date (0); date.setSeconds (45);//指定SECONDS的值 var timeString = date.toISOString()。substring(11、19); console.log (timeString)

在谷歌上搜索的结果是这样的:

function secondsToTime(secs)
{
    secs = Math.round(secs);
    var hours = Math.floor(secs / (60 * 60));

    var divisor_for_minutes = secs % (60 * 60);
    var minutes = Math.floor(divisor_for_minutes / 60);

    var divisor_for_seconds = divisor_for_minutes % 60;
    var seconds = Math.ceil(divisor_for_seconds);

    var obj = {
        "h": hours,
        "m": minutes,
        "s": seconds
    };
    return obj;
}

最普遍的答案是

function hms(seconds) {
  return [3600, 60]
    .reduceRight(
      (p, b) => r => [Math.floor(r / b)].concat(p(r % b)),
      r => [r]
    )(seconds)
    .map(a => a.toString().padStart(2, '0'))
    .join(':');
}

一些示例输出:

> hms(0)
< "00:00:00"

> hms(5)
< "00:00:05"

> hms(60)
< "00:01:00"

> hms(3785)
< "01:03:05"

> hms(37850)
< "10:30:50"

> hms(378500)
< "105:08:20"

详见https://stackoverflow.com/a/66504936/1310733