在sh中，jobs命令将列出后台进程。在某些情况下，最好先杀死最新的进程，例如旧进程创建了一个共享套接字。在这些情况下，将pid按相反的顺序排序。有时您希望在作业停止之前等待作业在磁盘上写入一些内容或类似的东西。

如果没必要就不要杀人!

for SIGNAL in TERM KILL; do
  for CHILD in $(jobs -s|sort -r); do
    kill -s $SIGNAL $CHILD
    sleep $MOMENT
  done
done

如果你知道传递父进程的pid，下面这个shell脚本应该可以工作:

for child in $(ps -o pid,ppid -ax | \
   awk "{ if ( \$2 == $pid ) { print \$1 }}")
do
  echo "Killing child process $child because ppid = $pid"
  kill $child
done

要递归地杀死进程树，请使用killtree():

#!/bin/bash

killtree() {
    local _pid=$1
    local _sig=${2:--TERM}
    kill -stop ${_pid} # needed to stop quickly forking parent from producing children between child killing and parent killing
    for _child in $(ps -o pid --no-headers --ppid ${_pid}); do
        killtree ${_child} ${_sig}
    done
    kill -${_sig} ${_pid}
}

if [ $# -eq 0 -o $# -gt 2 ]; then
    echo "Usage: $(basename $0) <pid> [signal]"
    exit 1
fi

killtree $@

我进一步开发了志刚、木uri和固颈的溶液:

 #!/bin/bash

if test $# -lt 1 ; then
    echo >&2 "usage: kiltree pid (sig)"
    exit 1 ;
  fi ;

_pid=$1
_sig=${2:-TERM}

# echo >&2 "killtree($_pid) mypid = $$"
# ps axwwf | grep -6 "^[ ]*$_pid " >&2 ;

function _killtree () {
    local _children
    local _child
    local _success

    if test $1 -eq $2 ; then # this is killtree - don't commit suicide!
        echo >&2 "killtree can´t kill it´s own branch - some processes will survive." ; 
        return 1 ;
      fi ;
    # this avoids that children are spawned or disappear.
    kill -SIGSTOP $2 ;

    _children=$(ps -o pid --no-headers --ppid $2) ;        
    _success=0 
    for _child in ${_children}; do
        _killtree $1 ${_child} $3 ;
        _success=$(($_success+$?)) ;
      done ;

    if test $_success -eq 0 ; then
        kill -$3 $2
      fi ;
    # when a stopped process is killed, it will linger in the system until it is continued
    kill -SIGCONT $2
    test $_success -eq 0 ;
    return $?
    }

_killtree $$ $_pid $_sig

这个版本将避免杀死它的祖先进程——在以前的解决方案中，这会导致大量的子进程。

在确定子列表之前适当地停止进程，这样就不会创建或消失新的子列表。

停止的作业被杀死后，必须继续执行，才能从系统中消失。

brad的答案也是我推荐的，除了如果你使用——ppid选项ps，你可以完全放弃awk。

for child in $(ps -o pid -ax --ppid $PPID) do ....... done

修改后的志刚回答:

#!/usr/bin/env bash
set -eu

killtree() {
    local pid
    for pid; do
        kill -stop $pid
        local cpid
        for cpid in $(pgrep -P $pid); do
            killtree $cpid
        done
        kill $pid
        kill -cont $pid
        wait $pid 2>/dev/null || true
   done
}

cpids() {
    local pid=$1 options=${2:-} space=${3:-}
    local cpid
    for cpid in $(pgrep -P $pid); do
        echo "$space$cpid"
        if [[ "${options/a/}" != "$options" ]]; then
            cpids $cpid "$options" "$space  "
        fi
    done
}

while true; do sleep 1; done &
cpid=$!
for i in $(seq 1 2); do
    cpids $$ a
    sleep 1
done
killtree $cpid
echo ---
cpids $$ a