我正在构建一个PHP脚本,将JSON数据提供给另一个脚本。我的脚本将数据构建到一个大型关联数组中,然后使用json_encode输出数据。下面是一个脚本示例:

$data = array('a' => 'apple', 'b' => 'banana', 'c' => 'catnip');
header('Content-type: text/javascript');
echo json_encode($data);

上面的代码产生如下输出:

{"a":"apple","b":"banana","c":"catnip"}

如果你有少量的数据,这是很好的,但我更喜欢这样的东西:

{
    "a": "apple",
    "b": "banana",
    "c": "catnip"
}

有没有办法在PHP中做到这一点,而不需要丑陋的黑客?似乎Facebook的某个人发现了这一点。


当前回答

以下是对我有效的方法:

test.php的内容:

<html>
<body>
Testing JSON array output
  <pre>
  <?php
  $data = array('a'=>'apple', 'b'=>'banana', 'c'=>'catnip');
  // encode in json format 
  $data = json_encode($data);

  // json as single line
  echo "</br>Json as single line </br>";
  echo $data;
  // json as an array, formatted nicely
  echo "</br>Json as multiline array </br>";
  print_r(json_decode($data, true));
  ?>
  </pre>
</body>
</html>

输出:

Testing JSON array output


Json as single line 
{"a":"apple","b":"banana","c":"catnip"}
Json as multiline array 
Array
(
    [a] => apple
    [b] => banana
    [c] => catnip
)

还要注意html中“pre”标签的使用。

希望这能帮助到别人

其他回答

递归解的经典例子。这是我的:

class JsonFormatter {
    public static function prettyPrint(&$j, $indentor = "\t", $indent = "") {
        $inString = $escaped = false;
        $result = $indent;

        if(is_string($j)) {
            $bak = $j;
            $j = str_split(trim($j, '"'));
        }

        while(count($j)) {
            $c = array_shift($j);
            if(false !== strpos("{[,]}", $c)) {
                if($inString) {
                    $result .= $c;
                } else if($c == '{' || $c == '[') {
                    $result .= $c."\n";
                    $result .= self::prettyPrint($j, $indentor, $indentor.$indent);
                    $result .= $indent.array_shift($j);
                } else if($c == '}' || $c == ']') {
                    array_unshift($j, $c);
                    $result .= "\n";
                    return $result;
                } else {
                    $result .= $c."\n".$indent;
                } 
            } else {
                $result .= $c;
                $c == '"' && !$escaped && $inString = !$inString;
                $escaped = $c == '\\' ? !$escaped : false;
            }
        }

        $j = $bak;
        return $result;
    }
}

用法:

php > require 'JsonFormatter.php';
php > $a = array('foo' => 1, 'bar' => 'This "is" bar', 'baz' => array('a' => 1, 'b' => 2, 'c' => '"3"'));
php > print_r($a);
Array
(
    [foo] => 1
    [bar] => This "is" bar
    [baz] => Array
        (
            [a] => 1
            [b] => 2
            [c] => "3"
        )

)
php > echo JsonFormatter::prettyPrint(json_encode($a));
{
    "foo":1,
    "bar":"This \"is\" bar",
    "baz":{
        "a":1,
        "b":2,
        "c":"\"3\""
    }
}

干杯

将<pre>与json_encode()和JSON_PRETTY_PRINT选项结合使用:

<pre>
    <?php
    echo json_encode($dataArray, JSON_PRETTY_PRINT);
    ?>
</pre>

如果你正在使用MVC

尝试在您的控制器中执行此操作

public function getLatestUsers() {
    header('Content-Type: application/json');
    echo $this->model->getLatestUsers(); // this returns json_encode($somedata, JSON_PRETTY_PRINT)
}

然后如果你调用/getLatestUsers,你会得到一个漂亮的JSON输出;)

把几个答案粘在一起适合我对现有json的需求:

Code:
echo "<pre>"; 
echo json_encode(json_decode($json_response), JSON_PRETTY_PRINT); 
echo "</pre>";

Output:
{
    "data": {
        "token_type": "bearer",
        "expires_in": 3628799,
        "scopes": "full_access",
        "created_at": 1540504324
    },
    "errors": [],
    "pagination": {},
    "token_type": "bearer",
    "expires_in": 3628799,
    "scopes": "full_access",
    "created_at": 1540504324
}

这个解决方案生成“非常漂亮”的JSON。这并不完全是OP所要求的,但它让您更好地可视化JSON。

/**
 * takes an object parameter and returns the pretty json format.
 * this is a space saving version that uses 2 spaces instead of the regular 4
 *
 * @param $in
 *
 * @return string
 */
function pretty_json ($in): string
{
  return preg_replace_callback('/^ +/m',
    function (array $matches): string
    {
      return str_repeat(' ', strlen($matches[0]) / 2);
    }, json_encode($in, JSON_PRETTY_PRINT | JSON_HEX_APOS)
  );
}

/**
 * takes a JSON string an adds colours to the keys/values
 * if the string is not JSON then it is returned unaltered.
 *
 * @param string $in
 *
 * @return string
 */

function markup_json (string $in): string
{
  $string  = 'green';
  $number  = 'darkorange';
  $null    = 'magenta';
  $key     = 'red';
  $pattern = '/("(\\\\u[a-zA-Z0-9]{4}|\\\\[^u]|[^\\\\"])*"(\s*:)?|\b(true|false|null)\b|-?\d+(?:\.\d*)?(?:[eE][+\-]?\d+)?)/';
  return preg_replace_callback($pattern,
      function (array $matches) use ($string, $number, $null, $key): string
      {
        $match  = $matches[0];
        $colour = $number;
        if (preg_match('/^"/', $match))
        {
          $colour = preg_match('/:$/', $match)
            ? $key
            : $string;
        }
        elseif ($match === 'null')
        {
          $colour = $null;
        }
        return "<span style='color:{$colour}'>{$match}</span>";
      }, str_replace(['<', '>', '&'], ['&lt;', '&gt;', '&amp;'], $in)
   ) ?? $in;
}

public function test_pretty_json_object ()
{
  $ob       = new \stdClass();
  $ob->test = 'unit-tester';
  $json     = pretty_json($ob);
  $expected = <<<JSON
{
  "test": "unit-tester"
}
JSON;
  $this->assertEquals($expected, $json);
}

public function test_pretty_json_str ()
{
  $ob   = 'unit-tester';
  $json = pretty_json($ob);
  $this->assertEquals("\"$ob\"", $json);
}

public function test_markup_json ()
{
  $json = <<<JSON
[{"name":"abc","id":123,"warnings":[],"errors":null},{"name":"abc"}]
JSON;
  $expected = <<<STR
[
  {
    <span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>,
    <span style='color:red'>"id":</span> <span style='color:darkorange'>123</span>,
    <span style='color:red'>"warnings":</span> [],
    <span style='color:red'>"errors":</span> <span style='color:magenta'>null</span>
  },
  {
    <span style='color:red'>"name":</span> <span style='color:green'>"abc"</span>
  }
]
STR;

  $output = markup_json(pretty_json(json_decode($json)));
  $this->assertEquals($expected,$output);
}

}