我有一些复选框:

<input type='checkbox' value="apple" checked>
<input type='checkbox' value="orange">
<input type='checkbox' value="pear" checked>
<input type='checkbox' value="naartjie">

我想绑定到我的控制器中的一个列表,这样每当一个复选框被更改时,控制器就会维护一个包含所有选中值的列表,例如,['apple', 'pear']。

Ng-model似乎只能将一个复选框的值绑定到控制器中的一个变量。

是否有其他方法可以将这四个复选框绑定到控制器中的列表?


当前回答

使用@Umur kontacabi这个例子,我认为在使用捕获选择的数据通过另一个对象/数组,像一个编辑页面。

捕获数据库中的选项

切换某个选项

例如,下面是所有颜色的json:

{
    "colors": [
        {
            "id": 1,
            "title": "Preto - #000000"
        },
        {
            "id": 2,
            "title": "Azul - #005AB1"
        },
        {
            "id": 3,
            "title": "Azul Marinho - #001A66"
        },
        {
            "id": 4,
            "title": "Amarelo - #FFF100"
        },
        {
            "id": 5,
            "title": "Vermelho - #E92717"
        },
        {
            "id": 6,
            "title": "Verde - #008D2F"
        },
        {
            "id": 7,
            "title": "Cinza - #8A8A8A"
        },
        {
            "id": 8,
            "title": "Prata - #C8C9CF"
        },
        {
            "id": 9,
            "title": "Rosa - #EF586B"
        },
        {
            "id": 10,
            "title": "Nude - #E4CAA6"
        },
        {
            "id": 11,
            "title": "Laranja - #F68700"
        },
        {
            "id": 12,
            "title": "Branco - #FFFFFF"
        },
        {
            "id": 13,
            "title": "Marrom - #764715"
        },
        {
            "id": 14,
            "title": "Dourado - #D9A300"
        },
        {
            "id": 15,
            "title": "Bordo - #57001B"
        },
        {
            "id": 16,
            "title": "Roxo - #3A0858"
        },
        {
            "id": 18,
            "title": "Estampado "
        },
        {
            "id": 17,
            "title": "Bege - #E5CC9D"
        }
    ]
}

以及2种类型的数据对象,包含一个对象的数组和包含两个/多个对象数据的对象:

在数据库中选择两个捕获项: [{" id ": 12,“标题”:“布兰科- # FFFFFF "}, {" id ": 16,“标题”:“Roxo - # 3 a0858”}] 在数据库中选择一个捕获项: {"id":12,"title":"Branco - #FFFFFF"}

这里是我的javascript代码:

/**
 * Add this code after catch data of database.
 */

vm.checkedColors = [];
var _colorObj = vm.formData.color_ids;
var _color_ids = [];

if (angular.isObject(_colorObj)) {
    // vm.checkedColors.push(_colorObj);
    _color_ids.push(_colorObj);
} else if (angular.isArray(_colorObj)) {
    angular.forEach(_colorObj, function (value, key) {
        // vm.checkedColors.push(key + ':' + value);
        _color_ids.push(key + ':' + value);
    });
}

angular.forEach(vm.productColors, function (object) {
    angular.forEach(_color_ids, function (color) {
        if (color.id === object.id) {
            vm.checkedColors.push(object);
        }
    });
});

/**
 * Add this code in your js function initialized in this HTML page
 */
vm.toggleColor = function (color) {
    console.log('toggleColor is: ', color);

    if (vm.checkedColors.indexOf(color) === -1) {
        vm.checkedColors.push(color);
    } else {
        vm.checkedColors.splice(vm.checkedColors.indexOf(color), 1);
    }
    vm.formData.color_ids = vm.checkedColors;
};

我的Html代码:

<div class="checkbox" ng-repeat="color in productColors">
    <label>
        <input type="checkbox"
               ng-checked="checkedColors.indexOf(color) != -1"
               ng-click="toggleColor(color)"/>
        <% color.title %>
    </label>
</div>

<p>checkedColors Output:</p>
<pre><% checkedColors %></pre>

[编辑]重构代码如下:

function makeCheckedOptions(objectOptions, optionObj) {
    var checkedOptions = [];
    var savedOptions = [];

    if (angular.isObject(optionObj)) {
        savedOptions.push(optionObj);
    } else if (angular.isArray(optionObj)) {
        angular.forEach(optionObj, function (value, key) {
            savedOptions.push(key + ':' + value);
        });
    }

    angular.forEach(objectOptions, function (object) {
        angular.forEach(savedOptions, function (color) {
            if (color.id === object.id) {
                checkedOptions.push(object);
            }
        });
    });

    return checkedOptions;
}

并调用new方法如下所示:

vm.checkedColors = makeCheckedOptions(productColors, vm.formData.color_ids);

就是这样!

其他回答

<input type='checkbox' ng-repeat="fruit in fruits"
  ng-checked="checkedFruits.indexOf(fruit) != -1" ng-click="toggleCheck(fruit)">

.

function SomeCtrl ($scope) {
    $scope.fruits = ["apple, orange, pear, naartjie"];
    $scope.checkedFruits = [];
    $scope.toggleCheck = function (fruit) {
        if ($scope.checkedFruits.indexOf(fruit) === -1) {
            $scope.checkedFruits.push(fruit);
        } else {
            $scope.checkedFruits.splice($scope.checkedFruits.indexOf(fruit), 1);
        }
    };
}

这里还有另一个解决方案。我的解决方案的好处是:

它不需要任何额外的手表(这可能会影响性能) 它不需要控制器中的任何代码来保持干净 代码仍然有些短 它只需要很少的代码就可以在多个地方重用,因为它只是一个指令

下面是指令:

function ensureArray(o) {
    var lAngular = angular;
    if (lAngular.isArray(o) || o === null || lAngular.isUndefined(o)) {
        return o;
    }
    return [o];
}

function checkboxArraySetDirective() {
    return {
        restrict: 'A',
        require: 'ngModel',
        link: function(scope, element, attrs, ngModel) {
            var name = attrs.checkboxArraySet;

            ngModel.$formatters.push(function(value) {
                return (ensureArray(value) || []).indexOf(name) >= 0;
            });

            ngModel.$parsers.push(function(value) {
                var modelValue = ensureArray(ngModel.$modelValue) || [],
                    oldPos = modelValue.indexOf(name),
                    wasSet = oldPos >= 0;
                if (value) {
                    if (!wasSet) {
                        modelValue = angular.copy(modelValue);
                        modelValue.push(name);
                    }
                } else if (wasSet) {
                    modelValue = angular.copy(modelValue);
                    modelValue.splice(oldPos, 1);
                }
                return modelValue;
            });
        }
    }
}

最后就像这样使用它:

<input ng-repeat="fruit in ['apple', 'banana', '...']" type="checkbox" ng-model="fruits" checkbox-array-set="{{fruit}}" />

这就是全部了。唯一增加的是复选框-数组-set属性。

我认为下面的方法对于嵌套ng-repeat更加清晰和有用。看看普伦克。

引用本文:

<html ng-app="plunker">
    <head>
        <title>Test</title>
        <script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.4/angular.min.js"></script>
    </head>

    <body ng-controller="MainCtrl">
        <div ng-repeat="tab in mytabs">

            <h1>{{tab.name}}</h1>
            <div ng-repeat="val in tab.values">
                <input type="checkbox" ng-change="checkValues()" ng-model="val.checked"/>
            </div>
        </div>

        <br>
        <pre> {{selected}} </pre>

            <script>
                var app = angular.module('plunker', []);

                app.controller('MainCtrl', function ($scope,$filter) {
                    $scope.mytabs = [
             {
                 name: "tab1",
                 values: [
                     { value: "value1",checked:false },
                     { value: "value2", checked: false },
                     { value: "value3", checked: false },
                     { value: "value4", checked: false }
                 ]
             },
             {
                 name: "tab2",
                 values: [
                     { value: "value1", checked: false },
                     { value: "value2", checked: false },
                     { value: "value3", checked: false },
                     { value: "value4", checked: false }
                 ]
             }
                    ]
                    $scope.selected = []
                    $scope.checkValues = function () {
                        angular.forEach($scope.mytabs, function (value, index) {
                         var selectedItems = $filter('filter')(value.values, { checked: true });
                         angular.forEach(selectedItems, function (value, index) {
                             $scope.selected.push(value);
                         });

                        });
                    console.log($scope.selected);
                    };
                });
        </script>
    </body>
</html>

你不需要编写所有的代码。AngularJS会通过使用ngTrueValue和ngFalseValue来使模型和复选框保持同步

代码在这里:http://codepen.io/paulbhartzog/pen/kBhzn

代码片段:

<p ng-repeat="item in list1" class="item" id="{{item.id}}">
  <strong>{{item.id}}</strong> <input name='obj1_data' type="checkbox" ng-model="list1[$index].data" ng-true-value="1" ng-false-value="0"> Click this to change data value below
</p>
<pre>{{list1 | json}}</pre>

我改编了Yoshi接受的答案来处理复杂的对象(而不是字符串)。

HTML

<div ng-controller="TestController">
    <p ng-repeat="permission in allPermissions">
        <input type="checkbox" ng-checked="selectedPermissions.containsObjectWithProperty('id', permission.id)" ng-click="toggleSelection(permission)" />
        {{permission.name}}
    </p>

    <hr />

    <p>allPermissions: | <span ng-repeat="permission in allPermissions">{{permission.name}} | </span></p>
    <p>selectedPermissions: | <span ng-repeat="permission in selectedPermissions">{{permission.name}} | </span></p>
</div>

JavaScript

Array.prototype.indexOfObjectWithProperty = function(propertyName, propertyValue)
{
    for (var i = 0, len = this.length; i < len; i++) {
        if (this[i][propertyName] === propertyValue) return i;
    }

    return -1;
};


Array.prototype.containsObjectWithProperty = function(propertyName, propertyValue)
{
    return this.indexOfObjectWithProperty(propertyName, propertyValue) != -1;
};


function TestController($scope)
{
    $scope.allPermissions = [
    { "id" : 1, "name" : "ROLE_USER" },
    { "id" : 2, "name" : "ROLE_ADMIN" },
    { "id" : 3, "name" : "ROLE_READ" },
    { "id" : 4, "name" : "ROLE_WRITE" } ];

    $scope.selectedPermissions = [
    { "id" : 1, "name" : "ROLE_USER" },
    { "id" : 3, "name" : "ROLE_READ" } ];

    $scope.toggleSelection = function toggleSelection(permission) {
        var index = $scope.selectedPermissions.indexOfObjectWithProperty('id', permission.id);

        if (index > -1) {
            $scope.selectedPermissions.splice(index, 1);
        } else {
            $scope.selectedPermissions.push(permission);
        }
    };
}

工作示例:http://jsfiddle.net/tCU8v/