通过urllib和python下载图片

所以我试图制作一个Python脚本，下载网络漫画，并将它们放在我桌面上的文件夹中。我在这里找到了一些类似的程序，它们的功能类似，但都不是我所需要的。我发现最相似的一个在这里(http://bytes.com/topic/python/answers/850927-problem-using-urllib-download-images)。我尝试使用以下代码:

>>> import urllib
>>> image = urllib.URLopener()
>>> image.retrieve("http://www.gunnerkrigg.com//comics/00000001.jpg","00000001.jpg")
('00000001.jpg', <httplib.HTTPMessage instance at 0x1457a80>)

I then searched my computer for a file "00000001.jpg", but all I found was the cached picture of it. I'm not even sure it saved the file to my computer. Once I understand how to get the file downloaded, I think I know how to handle the rest. Essentially just use a for loop and split the string at the '00000000'.'jpg' and increment the '00000000' up to the largest number, which I would have to somehow determine. Any reccomendations on the best way to do this or how to download the file correctly?

谢谢!

编辑6/15/10

这是完成的脚本，它将文件保存到您选择的任何目录。出于某种奇怪的原因，文件没有下载，他们就下载了。任何关于如何清理它的建议都将非常感激。我目前正在研究如何找到许多漫画存在于网站上，这样我就可以得到最新的一个，而不是有程序退出后，一定数量的异常被提出。

import urllib
import os

comicCounter=len(os.listdir('/file'))+1  # reads the number of files in the folder to start downloading at the next comic
errorCount=0

def download_comic(url,comicName):
    """
    download a comic in the form of

    url = http://www.example.com
    comicName = '00000000.jpg'
    """
    image=urllib.URLopener()
    image.retrieve(url,comicName)  # download comicName at URL

while comicCounter <= 1000:  # not the most elegant solution
    os.chdir('/file')  # set where files download to
        try:
        if comicCounter < 10:  # needed to break into 10^n segments because comic names are a set of zeros followed by a number
            comicNumber=str('0000000'+str(comicCounter))  # string containing the eight digit comic number
            comicName=str(comicNumber+".jpg")  # string containing the file name
            url=str("http://www.gunnerkrigg.com//comics/"+comicName)  # creates the URL for the comic
            comicCounter+=1  # increments the comic counter to go to the next comic, must be before the download in case the download raises an exception
            download_comic(url,comicName)  # uses the function defined above to download the comic
            print url
        if 10 <= comicCounter < 100:
            comicNumber=str('000000'+str(comicCounter))
            comicName=str(comicNumber+".jpg")
            url=str("http://www.gunnerkrigg.com//comics/"+comicName)
            comicCounter+=1
            download_comic(url,comicName)
            print url
        if 100 <= comicCounter < 1000:
            comicNumber=str('00000'+str(comicCounter))
            comicName=str(comicNumber+".jpg")
            url=str("http://www.gunnerkrigg.com//comics/"+comicName)
            comicCounter+=1
            download_comic(url,comicName)
            print url
        else:  # quit the program if any number outside this range shows up
            quit
    except IOError:  # urllib raises an IOError for a 404 error, when the comic doesn't exist
        errorCount+=1  # add one to the error count
        if errorCount>3:  # if more than three errors occur during downloading, quit the program
            break
        else:
            print str("comic"+ ' ' + str(comicCounter) + ' ' + "does not exist")  # otherwise say that the certain comic number doesn't exist
print "all comics are up to date"  # prints if all comics are downloaded

当前回答

使用请求

import requests
import shutil,os

headers = {
    'user-agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/78.0.3904.108 Safari/537.36'
}
currentDir = os.getcwd()
path = os.path.join(currentDir,'Images')#saving images to Images folder

def ImageDl(url):
    attempts = 0
    while attempts < 5:#retry 5 times
        try:
            filename = url.split('/')[-1]
            r = requests.get(url,headers=headers,stream=True,timeout=5)
            if r.status_code == 200:
                with open(os.path.join(path,filename),'wb') as f:
                    r.raw.decode_content = True
                    shutil.copyfileobj(r.raw,f)
            print(filename)
            break
        except Exception as e:
            attempts+=1
            print(e)

if __name__ == '__main__':
    ImageDl(url)

2020-04-18 17:02:44

其他回答

所有上述代码，不允许保留原始图像名称，这有时是必需的。这将有助于将映像保存到本地驱动器，保留原始映像名称

    IMAGE = URL.rsplit('/',1)[1]
    urllib.urlretrieve(URL, IMAGE)

试着了解更多细节。

2014-07-18 04:42:26

Python 3版@DiGMi的回答:

from urllib import request
f = open('00000001.jpg', 'wb')
f.write(request.urlopen("http://www.gunnerkrigg.com/comics/00000001.jpg").read())
f.close()

2013-08-29 15:40:47

也许你需要'User-Agent':

import urllib2
opener = urllib2.build_opener()
opener.addheaders = [('User-Agent', 'Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/34.0.1847.137 Safari/537.36')]
response = opener.open('http://google.com')
htmlData = response.read()
f = open('file.txt','w')
f.write(htmlData )
f.close()

2014-05-20 09:30:24

对于Python 3，你需要导入import urllib.request:

import urllib.request 

urllib.request.urlretrieve(url, filename)

更多信息请点击链接

2017-07-30 14:48:55

那么这个呢:

import urllib, os

def from_url( url, filename = None ):
    '''Store the url content to filename'''
    if not filename:
        filename = os.path.basename( os.path.realpath(url) )

    req = urllib.request.Request( url )
    try:
        response = urllib.request.urlopen( req )
    except urllib.error.URLError as e:
        if hasattr( e, 'reason' ):
            print( 'Fail in reaching the server -> ', e.reason )
            return False
        elif hasattr( e, 'code' ):
            print( 'The server couldn\'t fulfill the request -> ', e.code )
            return False
    else:
        with open( filename, 'wb' ) as fo:
            fo.write( response.read() )
            print( 'Url saved as %s' % filename )
        return True

##

def main():
    test_url = 'http://cdn.sstatic.net/stackoverflow/img/favicon.ico'

    from_url( test_url )

if __name__ == '__main__':
    main()

2014-10-30 01:37:22

通过urllib和python下载图片

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