以上所有解决方案+额外的糖。(终极AIO解决方案)

/**
 * Check that given URL is valid and exists.
 * @param string $url URL to check
 * @return bool TRUE when valid | FALSE anyway
 */
function urlExists ( $url ) {
    // Remove all illegal characters from a url
    $url = filter_var($url, FILTER_SANITIZE_URL);

    // Validate URI
    if (filter_var($url, FILTER_VALIDATE_URL) === FALSE
        // check only for http/https schemes.
        || !in_array(strtolower(parse_url($url, PHP_URL_SCHEME)), ['http','https'], true )
    ) {
        return false;
    }

    // Check that URL exists
    $file_headers = @get_headers($url);
    return !(!$file_headers || $file_headers[0] === 'HTTP/1.1 404 Not Found');
}

例子:

var_dump ( urlExists('http://stackoverflow.com/') );
// Output: true;

$url = 'http://google.com';
$not_url = 'stp://google.com';

if (@file_get_contents($url)): echo "Found '$url'!";
else: echo "Can't find '$url'.";
endif;
if (@file_get_contents($not_url)): echo "Found '$not_url!";
else: echo "Can't find '$not_url'.";
endif;

// Found 'http://google.com'!Can't find 'stp://google.com'.

在某些服务器中不能使用curl 你可以用这个代码

<?php
$url = 'http://www.example.com';
$array = get_headers($url);
$string = $array[0];
if(strpos($string,"200"))
  {
    echo 'url exists';
  }
  else
  {
    echo 'url does not exist';
  }
?>

function urlIsOk($url)
{
    $headers = @get_headers($url);
    $httpStatus = intval(substr($headers[0], 9, 3));
    if ($httpStatus<400)
    {
        return true;
    }
    return false;
}

get_headers()返回一个数组，其中包含服务器响应HTTP请求时发送的报头。

$image_path = 'https://your-domain.com/assets/img/image.jpg';

$file_headers = @get_headers($image_path);
//Prints the response out in an array
//print_r($file_headers); 

if($file_headers[0] == 'HTTP/1.1 404 Not Found'){
   echo 'Failed because path does not exist.</br>';
}else{
   echo 'It works. Your good to go!</br>';
}

到目前为止使用get_headers()的最佳和最简单的答案 最好检查字符串“200 ok”。这比检查要好得多

$file_headers = @get_headers($file-path);
$file_headers[0];

因为有时数组键值会变化。所以最好的办法是检查“200 ok”。任何URL都将在get_headers()响应的任何地方有“200 ok”。

function url_exist($url) {
        $urlheaders = get_headers($url);
        //print_r($urlheaders);
        $urlmatches  = preg_grep('/200 ok/i', $urlheaders);
         if(!empty($urlmatches)){
           return true;
         }else{
           return false;
         }
}

现在检查函数是否为真或假

if(url_exist(php-url-variable-here)
  URL exist
}else{
  URL don't exist
}