我很惊讶，客体。还没有提到Assign。

let cloned = Object.assign({}, source);

如果可用(例如Babel)，你可以使用对象展开操作符:

let cloned = { ... source };

如果你不想“滚出你自己的”，还有一些Node模块。这个看起来不错:https://www.npmjs.com/package/clone

看起来它可以处理各种各样的东西，包括循环引用。来自github页面:

clone主人克隆对象，数组，日期对象和RegEx 对象。所有内容都是递归克隆的，因此您可以克隆日期 例如，在对象的数组中。[…循环推荐?是的!

There is no built-in way to do a real clone (deep copy) of an object in node.js. There are some tricky edge cases so you should definitely use a library for this. I wrote such a function for my simpleoo library. You can use the deepCopy function without using anything else from the library (which is quite small) if you don't need it. This function supports cloning multiple data types, including arrays, dates, and regular expressions, it supports recursive references, and it also works with objects whose constructor functions have required parameters.

代码如下:

//If Object.create isn't already defined, we just do the simple shim, without the second argument,
//since that's all we need here
var object_create = Object.create;
if (typeof object_create !== 'function') {
    object_create = function(o) {
        function F() {}
        F.prototype = o;
        return new F();
    };
}

/**
 * Deep copy an object (make copies of all its object properties, sub-properties, etc.)
 * An improved version of http://keithdevens.com/weblog/archive/2007/Jun/07/javascript.clone
 * that doesn't break if the constructor has required parameters
 * 
 * It also borrows some code from http://stackoverflow.com/a/11621004/560114
 */ 
function deepCopy = function deepCopy(src, /* INTERNAL */ _visited) {
    if(src == null || typeof(src) !== 'object'){
        return src;
    }

    // Initialize the visited objects array if needed
    // This is used to detect cyclic references
    if (_visited == undefined){
        _visited = [];
    }
    // Ensure src has not already been visited
    else {
        var i, len = _visited.length;
        for (i = 0; i < len; i++) {
            // If src was already visited, don't try to copy it, just return the reference
            if (src === _visited[i]) {
                return src;
            }
        }
    }

    // Add this object to the visited array
    _visited.push(src);

    //Honor native/custom clone methods
    if(typeof src.clone == 'function'){
        return src.clone(true);
    }

    //Special cases:
    //Array
    if (Object.prototype.toString.call(src) == '[object Array]') {
        //[].slice(0) would soft clone
        ret = src.slice();
        var i = ret.length;
        while (i--){
            ret[i] = deepCopy(ret[i], _visited);
        }
        return ret;
    }
    //Date
    if (src instanceof Date) {
        return new Date(src.getTime());
    }
    //RegExp
    if (src instanceof RegExp) {
        return new RegExp(src);
    }
    //DOM Element
    if (src.nodeType && typeof src.cloneNode == 'function') {
        return src.cloneNode(true);
    }

    //If we've reached here, we have a regular object, array, or function

    //make sure the returned object has the same prototype as the original
    var proto = (Object.getPrototypeOf ? Object.getPrototypeOf(src): src.__proto__);
    if (!proto) {
        proto = src.constructor.prototype; //this line would probably only be reached by very old browsers 
    }
    var ret = object_create(proto);

    for(var key in src){
        //Note: this does NOT preserve ES5 property attributes like 'writable', 'enumerable', etc.
        //For an example of how this could be modified to do so, see the singleMixin() function
        ret[key] = deepCopy(src[key], _visited);
    }
    return ret;
};

如果你正在使用coffee-script，它就像:

newObject = {}
newObject[key] = value  for own key,value of oldObject

虽然这不是一个深度克隆。

没有一个答案让我满意，一些不工作或只是肤浅的克隆，答案来自@clint-harris和使用JSON。Parse /stringify很好，但是很慢。我找到了一个可以快速进行深度克隆的模块:https://github.com/AlexeyKupershtokh/node-v8-clone

关于这个问题的好文章:https://www.samanthaming.com/tidbits/70-3-ways-to-clone-objects/

var obj1 = {x: 5, y:5};
var obj2 = Object.assign({}, obj1 );
    
obj2  = {z: 10};
    
console.log(obj1);
console.log(obj2);