当我echo时,我得到这个,当我把它输入到终端时,它就会运行

curl -i \
-H "Accept: application/json" \
-H "Content-Type:application/json" \
-X POST --data '{"account":{"email":"akdgdtk@test.com","screenName":"akdgdtk","type":"NIKE","passwordSettings":{"password":"Starwars1","passwordConfirm":"Starwars1"}},"firstName":"Test","lastName":"User","middleName":"ObiWan","locale":"en_US","registrationSiteId":"520","receiveEmail":"false","dateOfBirth":"1984-12-25","mobileNumber":"9175555555","gender":"male","fuelActivationDate":"2010-10-22","postalCode":"10022","country":"US","city":"Beverton","state":"OR","bio":"This is a test user","jpFirstNameKana":"unsure","jpLastNameKana":"ofthis","height":"80","weight":"175","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}' https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx

但是当在bash脚本文件中运行时,我得到这个错误

curl: (6) Could not resolve host: application; nodename nor servname provided, or not known
curl: (6) Could not resolve host: is; nodename nor servname provided, or not known
curl: (6) Could not resolve host: a; nodename nor servname provided, or not known
curl: (6) Could not resolve host: test; nodename nor servname provided, or not known
curl: (3) [globbing] unmatched close brace/bracket at pos 158

这是文件中的代码

curl -i \
-H '"'Accept: application/json'"' \
-H '"'Content-Type:application/json'"' \
-X POST --data "'"'{"account":{"email":"'$email'","screenName":"'$screenName'","type":"'$theType'","passwordSettings":{"password":"'$password'","passwordConfirm":"'$password'"}},"firstName":"'$firstName'","lastName":"'$lastName'","middleName":"'$middleName'","locale":"'$locale'","registrationSiteId":"'$registrationSiteId'","receiveEmail":"'$receiveEmail'","dateOfBirth":"'$dob'","mobileNumber":"'$mobileNumber'","gender":"'$gender'","fuelActivationDate":"'$fuelActivationDate'","postalCode":"'$postalCode'","country":"'$country'","city":"'$city'","state":"'$state'","bio":"'$bio'","jpFirstNameKana":"'$jpFirstNameKana'","jpLastNameKana":"'$jpLastNameKana'","height":"'$height'","weight":"'$weight'","distanceUnit":"MILES","weightUnit":"POUNDS","heightUnit":"FT/INCHES"}'"'" "https://xxx:xxxxx@xxxx-www.xxxxx.com/xxxxx/xxxx/xxxx"

我认为我的引号有问题,但我用过很多次,也得到过类似的错误。在实际脚本中,所有变量都是用不同的函数定义的


当前回答

几年之后,如果你使用eval或backtick替换,这可能会帮助到一些人:

postDataJson="{\"guid\":\"$guid\",\"auth_token\":\"$token\"}"

使用sed从响应的开头和结尾去掉引号

$(curl --silent -H "Content-Type: application/json" https://${target_host}/runs/get-work -d ${postDataJson} | sed -e 's/^"//' -e 's/"$//')

其他回答

以下是我从下面的回答中得到的建议:

export BASH_VARIABLE="[1,2,3]"
curl http://localhost:8080/path -d "$(cat <<EOF
{
  "name": $BASH_VARIABLE,
  "something": [
    "value1",
    "value2",
    "value3"
  ]
}
EOF
)" -H 'Content-Type: application/json'

现有的答案指出curl可以从文件中发布数据,并使用heredocs来避免过多的引号转义,并清楚地将JSON分离到新的行。然而,不需要定义函数或从cat获取输出,因为curl可以发布来自标准输入的数据。我觉得这个表格很有可读性:

curl -X POST -H 'Content-Type:application/json' --data '$@-' ${API_URL} << EOF
{
  "account": {
    "email": "$email",
    "screenName": "$screenName",
    "type": "$theType",
    "passwordSettings": {
      "password": "$password",
      "passwordConfirm": "$password"
    }
  },
  "firstName": "$firstName",
  "lastName": "$lastName",
  "middleName": "$middleName",
  "locale": "$locale",
  "registrationSiteId": "$registrationSiteId",
  "receiveEmail": "$receiveEmail",
  "dateOfBirth": "$dob",
  "mobileNumber": "$mobileNumber",
  "gender": "$gender",
  "fuelActivationDate": "$fuelActivationDate",
  "postalCode": "$postalCode",
  "country": "$country",
  "city": "$city",
  "state": "$state",
  "bio": "$bio",
  "jpFirstNameKana": "$jpFirstNameKana",
  "jpLastNameKana": "$jpLastNameKana",
  "height": "$height",
  "weight": "$weight",
  "distanceUnit": "MILES",
  "weightUnit": "POUNDS",
  "heightUnit": "FT/INCHES"
}
EOF

几年之后,如果你使用eval或backtick替换,这可能会帮助到一些人:

postDataJson="{\"guid\":\"$guid\",\"auth_token\":\"$token\"}"

使用sed从响应的开头和结尾去掉引号

$(curl --silent -H "Content-Type: application/json" https://${target_host}/runs/get-work -d ${postDataJson} | sed -e 's/^"//' -e 's/"$//')

使用https://httpbin.org/和内联bash脚本测试的解决方案 1. 对于没有空格的变量,即1: 只需添加'之前和之后$变量替换所需 字符串

for i in {1..3}; do \
  curl -X POST -H "Content-Type: application/json" -d \
    '{"number":"'$i'"}' "https://httpbin.org/post"; \
done

2. 对于带空格的输入: 用额外的“即”来包装变量。“el”:

declare -a arr=("el a" "el b" "el c"); for i in "${arr[@]}"; do \
  curl -X POST -H "Content-Type: application/json" -d \
    '{"elem":"'"$i"'"}' "https://httpbin.org/post"; \
done

哇工作:)

乔可能会帮忙:

$ export A=this B=that C=foo D=bar
$ jo -p a=$A b=$B nested=$(jo c=$C d=$D)
{
   "a": "this",
   "b": "that",
   "nested": {
      "c": "foo",
      "d": "bar"
   }
}